用Python编写登录接口
Posted taozi123
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了用Python编写登录接口相关的知识,希望对你有一定的参考价值。
登陆接口要求:
- 输入用户名和密码
- 认证成功后显示欢迎信息
- 输错三次后锁定
代码:
1 #!/usr/bin/env python 2 # -*- coding:utf-8 -*- 3 # Author:James Tao 4 5 import pickle 6 import os 7 8 #注册 9 register={‘tz‘:‘1234‘,‘t‘:‘123‘,‘tza‘:‘12345abc‘} 10 locked_account=[] 11 12 #也可由用户输入注册账号 13 #register_username=input(‘newusername:‘) 14 #register_passord=input(‘newpassword:‘) 15 #print(‘注册成功‘) 16 #register[register_username]=register_passord 17 18 #用pickle把已注册的账号字典序列化写到文件中 19 w_register=open(‘register.txt‘,‘wb‘) 20 pickle.dump(register,w_register) 21 w_register.close() 22 23 #登陆 24 count=0 25 while count<3: 26 print(‘请登录‘) 27 username=input(‘username:‘) 28 password=input(‘password:‘) 29 30 #若被锁定账号文件不为空,读出已锁定的账号 31 if os.path.getsize(‘lockedaccount.txt‘) > 0: 32 33 #用pickle把被锁定账号从文件中反序列化读出来 34 r_lockedaccount=open(‘lockedaccount.txt‘, ‘rb‘) 35 locked_account=pickle.load(r_lockedaccount) 36 r_lockedaccount.close() 37 38 #判断输入的账号是否已被锁定,若账号已被锁定则直接跳出所有循环 39 judge_of_locked=False 40 for locked_name in locked_account: 41 if username==locked_name: 42 print(‘The account has been locked‘) 43 judge_of_locked = True 44 break 45 if judge_of_locked: 46 break 47 48 #用pickle把已注册的账号字典反序列化读出来 49 r_register=open(‘register.txt‘,‘rb‘) 50 login=pickle.load(r_register) 51 r_register.close() 52 53 #判断输入的账号是否存在密码是否正确 54 if username in login and password==login[username]: 55 print(‘Welcome‘) 56 break 57 else: 58 print(‘Non-existed username or password error‘) 59 count+=1 60 61 #若账号和密码输错三次账号会被锁定 62 else: 63 print(‘You have tried too many times,The account has been locked‘) 64 65 #插入被锁定账号的用户名 66 locked_account.append(username) 67 68 #用pickle把被锁定账号的列表序列化写到文件中 69 w_lockedaccount = open(‘lockedaccount.txt‘, ‘wb‘) 70 pickle.dump(locked_account,w_lockedaccount) 71 w_lockedaccount.close()
以上是关于用Python编写登录接口的主要内容,如果未能解决你的问题,请参考以下文章