请解释为啥这么说。"Good girls go to heaven, bad girls go everywhere. "

Posted 2023-05-09

我知道是歌词。请解释为什么这么说，有什么寓意吗？

好女孩去天堂，而坏女孩四处流浪 参考技术A 好女孩都死了,坏女孩子到处都是. 参考技术B 同意天堂水月的看法 参考技术C 歌词

Good Girls Go To Heaven

Some girls go to church on sunday
Live life by the golden rule
You got girls gonna graduate one day
Suma cum laude from party school
(From: http://cn.clyric.com )

Some they walk the straight and narrow
Some girls they just don't care
Good girls go to heaven
Bad girls¡­. go everywhere
(From: http://cn.clyric.com )

Some girls are into heavy metal
Dance with the devil everywhere they go
Others of ¡®em cut a rug to the fiddle
Dance to the rhythm of the cotton eyed joe
(From: http://cn.clyric.com )

Chorus
(From: http://cn.clyric.com )

Miss high fullutin' likes to sip fine champagne
Prim and proper drippin' in diamond rings
Little sister wears high heals and blue jeans
A long neck drinkin' certified wild thang
(From: http://cn.clyric.com )

Chorus
(From: http://cn.clyric.com )

Good girls go to heaven bad girls go everywhere本回答被提问者采纳 参考技术D 一楼回答完全正确!

HDU3294 Girls' research

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本文作者：ljh2000
作者博客：http://www.cnblogs.com/ljh2000-jump/
转载请注明出处，侵权必究，保留最终解释权！

 

Problem Description

One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps:
First step: girls will write a long string (only contains lower case) on the paper. For example, "abcde", but \'a\' inside is not the real \'a\', that means if we define the \'b\' is the real \'a\', then we can infer that \'c\' is the real \'b\', \'d\' is the real \'c\' ……, \'a\' is the real \'z\'. According to this, string "abcde" changes to "bcdef".
Second step: girls will find out the longest palindromic string in the given string, the length of palindromic string must be equal or more than 2.

 

 

Input

Input contains multiple cases.
Each case contains two parts, a character and a string, they are separated by one space, the character representing the real \'a\' is and the length of the string will not exceed 200000.All input must be lowercase.
If the length of string is len, it is marked from 0 to len-1.

 

 

Output

Please execute the operation following the two steps.
If you find one, output the start position and end position of palindromic string in a line, next line output the real palindromic string, or output "No solution!".
If there are several answers available, please choose the string which first appears.

 

 

Sample Input

b babd a abcd

 

 

Sample Output

0 2 aza No solution!

 

正解：manacher

解题报告：

　　manacher裸题。

　　按题意所说的做就可以了，注意分奇数和偶数的情况讨论，当然也可以不讨论，弄出一个公共的式子即可。

　　开始没策清楚下标关系，WA了一发...

 

//It is made by ljh2000
#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <algorithm>
using namespace std;
typedef long long LL;
const int MAXN = 400011;
int len,n,cha,p[MAXN],ans;
char ch[MAXN],s[MAXN],H;
inline int getint(){
    int w=0,q=0; char c=getchar(); while((c<\'0\'||c>\'9\') && c!=\'-\') c=getchar();
    if(c==\'-\') q=1,c=getchar(); while (c>=\'0\'&&c<=\'9\') w=w*10+c-\'0\',c=getchar(); return q?-w:w;
}

inline void manacher(){
	memset(p,0,sizeof(p)); int maxR=0,id=0;
	for(int i=1;i<=n;i++) {
		if(i<maxR) p[i]=min(p[2*id-i],maxR-i); else p[i]=1;
		for(;i+p[i]<=n && s[i-p[i]]==s[i+p[i]];p[i]++) ;
		if(i+p[i]>maxR) { maxR=i+p[i]; id=i; }
	}
}

inline void work(){
	while(scanf("%s",ch)!=EOF) {
		H=ch[0]; scanf("%s",ch); len=strlen(ch); n=1;
		cha=H-\'a\'; s[0]=\'%\'; s[1]=\'#\';	   
		for(int i=0;i<len;i++) {
			ch[i]-=cha; if(ch[i]<\'a\') ch[i]+=26;
			s[++n]=ch[i];
			s[++n]=\'#\';
		}
		manacher(); ans=1; int pos=1;
		for(int i=1;i<=n;i++) if(p[i]>ans) ans=p[i],pos=i;
		ans--; if(ans==1) { printf("No solution!\\n"); continue; }
		int l,r,mid;
		if(pos%2==0) { mid=pos/2-1; l=mid-ans/2; r=mid+ans/2; }
		else { mid=pos/2-1; l=mid-ans/2+1; r=mid+ans/2; }
		printf("%d %d\\n",l,r);
		for(int i=l;i<=r;i++) printf("%c",ch[i]);
		printf("\\n");
	}
}

int main()
{
    work();
    return 0;
}