TouchAction
1.源码可以在这个路径找到:Lib\\site-packages\\appium\\webdriver\\common\\touch_action.py
class TouchAction(object):
def __init__(self, driver=None):
self._driver = driver
self._actions = []
def tap(self, element=None, x=None, y=None, count=1):
模拟手指触摸屏
def press(self, el=None, x=None, y=None):
短按:模拟手指按住一个元素,或者坐标
def long_press(self, el=None, x=None, y=None, duration=1000):
长按:模拟按住一个元素,或者坐标
def wait(self, ms=0):
按住元素后的等待时间
def move_to(self, el=None, x=None, y=None):
移动手指到另外一个元素,或者坐标,注意这里坐标不是绝对坐标,是偏移量
def release(self):
释放手指
def perform(self):
执行前面的动作
2.TouchAction里面有这几个动作:
- 触摸 (tap)
- 短按 (press)
- 长按 (long_press)
- 等待 (wait)
- 移动到 (moveTo)
- 释放 (release)
- 执行 (perform)
九宫格解锁
1.有些九宫格的每个点可以直接定位到,这种相对来说容易一点,有一些九宫格就是一整个元素,比如QQ的九宫格解锁。
2.解决问题思路:先获取元素坐标位置,再获取元素大小,然后切割图片,分别计算出每个点的坐标
# 定位九宫格元素
jiu = \'resourceId("com.tencent.mobileqq:id/name").index(6)\'
loc = driver.find_element_by_android_uiautomator(jiu).location
print("获取九宫格坐标位置:%s"%loc)
s = driver.find_element_by_android_uiautomator(jiu).size
print("获取九宫格宽和高:%s"%s)
3.给每个圆圈编号从左到右1,2,3依次第二行4,5,6第三行7,8,9
gongge = {}
gongge[1] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6)
gongge[2] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6)
gongge[3] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6)
gongge[4] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6*3)
gongge[5] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6*3)
gongge[6] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6*3)
gongge[7] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6*5)
gongge[8] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6*5)
gongge[9] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6*5)
print gongge
偏移量
(备注下,这个地方,后面的appium有更新了,现在不用偏移量,直接用坐标就可以了,踩坑的小伙伴注意下,下面代码是很久之前写的,现在没维护了)
1.这里有个坑,press里面的参数是元素的坐标位置,但是move_to里面的是相对于前面一个元素的偏移位置。所以需要单独写一个函数,计算偏移量。
def pianyi(a=1,b=2):
\'\'\'计算从a点到b点的偏移量\'\'\'
g1 = gongge[a]
g2 = gongge[b]
r = (None, g2[1]-g1[1], g2[2]-g1[2])
return r
2.另外press和move_to里面都有三个参数,第一个参数默认为None,所以我返回的参数里面第一个写None.
移动手指
1.解锁思路:先press按住第一个点,再wait等待,接着移动带第二个点,再wait,最后release释放手指,perform执行
2.比如我要画出一个Z形状,依次经过的点1,2,3,5,7,8,9
参考代码
# coding:utf-8
from appium import webdriver
from appium.webdriver.common.touch_action import TouchAction
from time import sleep
desired_caps = {
\'platformName\': \'Android\',
\'deviceName\': \'127.0.0.1:62001\',
\'platformVersion\': \'4.4.2\',
\'appPackage\': \'com.tencent.mobileqq\',
\'appActivity\': \'com.tencent.mobileqq.activity.SplashActivity\',
\'noReset\': "true"
}
driver = webdriver.Remote(\'http://127.0.0.1:4723/wd/hub\', desired_caps)
sleep(5)
jiu = \'resourceId("com.tencent.mobileqq:id/name").index(6)\'
loc = driver.find_element_by_android_uiautomator(jiu).location
print("获取九宫格坐标位置:%s"%loc)
s = driver.find_element_by_android_uiautomator(jiu).size
print("获取九宫格宽和高:%s"%s)
# 获取九个点的坐标
gongge = {}
gongge[1] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6)
gongge[2] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6)
gongge[3] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6)
gongge[4] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6*3)
gongge[5] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6*3)
gongge[6] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6*3)
gongge[7] = (None, loc["x"]+s["width"]/6, loc["y"]+s["height"]/6*5)
gongge[8] = (None, loc["x"]+s["width"]/6*3, loc["y"]+s["height"]/6*5)
gongge[9] = (None, loc["x"]+s["width"]/6*5, loc["y"]+s["height"]/6*5)
print gongge
def pianyi(a=1,b=2):
\'\'\'计算从a点到b点的偏移量\'\'\'
g1 = gongge[a]
g2 = gongge[b]
r = (None, g2[1]-g1[1], g2[2]-g1[2])
return r
# 执行解锁
TouchAction(driver).press(*gongge[1]).wait(300).move_to(*pianyi(1,2)).wait(300).move_to(*pianyi(2,3)).wait(
300).move_to(*pianyi(3,5)).wait(300).move_to(*pianyi(5,7)).wait(300).move_to(*pianyi(7,8)).wait(300).move_to(*pianyi(8,9)).wait(
300).release().perform()
(备注下,这个地方,后面的appium有更新了,现在不用偏移量,直接用坐标就可以了,踩坑的小伙伴注意下,代码是很久之前写的,现在没维护了)
在学习过程中有遇到疑问的,可以appium+python QQ群交流:330467341