金额数字转中文大写

Posted 2023-03-23 蜘蛛流

封装一个方法：

function convertCurrency(money) 
    // 汉字的数字
    let cnNums = [\'零\', \'壹\', \'贰\', \'叁\', \'肆\', \'伍\', \'陆\', \'柒\', \'捌\', \'玖\'];
    // 基本单位
    let cnIntRadice = [\'\', \'拾\', \'佰\', \'仟\'];
    // 对应整数部分扩展单位
    let cnIntUnits = [\'\', \'万\', \'亿\', \'兆\'];
    // 对应小数部分单位
    let cnDecUnits = [\'角\', \'分\', \'毫\', \'厘\'];
    // 整数金额时后面跟的字符
    let cnInteger = \'整\';
    // 整型完以后的单位
    let cnIntLast = \'元\';
    // 最大处理的数字
    let maxNum = 999999999999999.9999;
    // 金额整数部分
    let integerNum;
    // 金额小数部分
    let decimalNum;
    // 输出的中文金额字符串
    let chineseStr = \'\';
    // 分离金额后用的数组，预定义
    let parts;
    if (money == \'\') 
        return \'\';
    
    money = parseFloat(money);
    if (money >= maxNum) 
        // 超出最大处理数字
        return \'\';
    
    if (money == 0) 
        chineseStr = cnNums[0] + cnIntLast + cnInteger;
        return chineseStr;
    
    // 转换为字符串
    money = money.toString();
    if (money.indexOf(\'.\') == -1) 
        integerNum = money;
        decimalNum = \'\';
     else 
        parts = money.split(\'.\');
        integerNum = parts[0];
        decimalNum = parts[1].substr(0, 4);
    
    // 获取整型部分转换
    if (parseInt(integerNum, 10) > 0) 
        let zeroCount = 0;
        let IntLen = integerNum.length;
        for (let i = 0; i < IntLen; i++) 
            let n = integerNum.substr(i, 1);
            let p = IntLen - i - 1;
            let q = p / 4;
            let m = p % 4;
            if (n == \'0\') 
                zeroCount++;
             else 
                if (zeroCount > 0) 
                    chineseStr += cnNums[0];
                
                // 归零
                zeroCount = 0;
                chineseStr += cnNums[parseInt(n)] + cnIntRadice[m];
            
            if (m == 0 && zeroCount < 4) 
                chineseStr += cnIntUnits[q];
            
        
        chineseStr += cnIntLast;
    
    // 小数部分
    if (decimalNum != \'\') 
        let decLen = decimalNum.length;
        for (let i = 0; i < decLen; i++) 
            let n = decimalNum.substr(i, 1);
            if (n != \'0\') 
                chineseStr += cnNums[Number(n)] + cnDecUnits[i];
            
        
    
    if (chineseStr == \'\') 
        chineseStr += cnNums[0] + cnIntLast + cnInteger;
     else if (decimalNum == \'\') 
        chineseStr += cnInteger;
    
    return chineseStr;