Leetcode 905. Sort Array By Parity

Posted 2021-09-07 SnailTyan

文章作者：Tyan
博客：noahsnail.com  |  CSDN  |  简书

1. Description

2. Solution

**解析：**Version 1，使用前后双指针，每次左边的奇数都跟右边的偶数对换位置。

• Version 1

class Solution:
    def sortArrayByParity(self, nums: List[int]) -> List[int]:
        i = 0
        j = len(nums) - 1
        while i < j:
            while i < len(nums) and nums[i] % 2 == 0:
                i += 1
            while j > -1 and nums[j] % 2 == 1:
                j -= 1
            if i < j:
                nums[i], nums[j] = nums[j], nums[i]
        return nums

Reference

1. https://leetcode.com/problems/sort-array-by-parity/