mysql null值的特殊处理
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实例
尝试以下实例:
[email protected]# mysql -u root -p password;
Enter password:*******
mysql> use RUNOOB;
Database changed
mysql> create table tcount_tbl
-> (
-> runoob_author varchar(40) NOT NULL,
-> runoob_count INT
-> );
Query OK, 0 rows affected (0.05 sec)
mysql> INSERT INTO tcount_tbl
-> (runoob_author, runoob_count) values (‘mahran‘, 20);
mysql> INSERT INTO tcount_tbl
-> (runoob_author, runoob_count) values (‘mahnaz‘, NULL);
mysql> INSERT INTO tcount_tbl
-> (runoob_author, runoob_count) values (‘Jen‘, NULL);
mysql> INSERT INTO tcount_tbl
-> (runoob_author, runoob_count) values (‘Gill‘, 20);
mysql> SELECT * from tcount_tbl;
+-----------------+----------------+
| runoob_author | runoob_count |
+-----------------+----------------+
| mahran | 20 |
| mahnaz | NULL |
| Jen | NULL |
| Gill | 20 |
+-----------------+----------------+
4 rows in set (0.00 sec)
mysql>
以下实例中你可以看到 = 和 != 运算符是不起作用的:
mysql> SELECT * FROM tcount_tbl WHERE runoob_count = NULL;
Empty set (0.00 sec)
mysql> SELECT * FROM tcount_tbl WHERE runoob_count != NULL;
Empty set (0.01 sec)
实例
查找数据表中 runoob_count 列是否为 NULL,必须使用IS NULL和IS NOT NULL,如下实例:
mysql> SELECT * FROM tcount_tbl
-> WHERE runoob_count IS NULL;
+-----------------+----------------+
| runoob_author | runoob_count |
+-----------------+----------------+
| mahnaz | NULL |
| Jen | NULL |
+-----------------+----------------+
2 rows in set (0.00 sec)
mysql> SELECT * from tcount_tbl
-> WHERE runoob_count IS NOT NULL;
+-----------------+----------------+
| runoob_author | runoob_count |
+-----------------+----------------+
| mahran | 20 |
| Gill | 20 |
+-----------------+----------------+
2 rows in set (0.00 sec)
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