SQL Server计算Jaccard系数—sim(i,j)
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了SQL Server计算Jaccard系数—sim(i,j)相关的知识,希望对你有一定的参考价值。
前些天,在Q群里面看到有人请教这样一个问题:在SQL Server中如何用SQL实现以下计算
由图得知,该问题是如何计算Jaccard系数。Jaccard系数,又称为Jaccard相似系数(Jaccard similarity coefficient)用于比较有限样本集之间的相似性与差异性。Jaccard系数值越大,样本相似度越高。
SQL Server通过intersect实现交集,union实现并集,如下:
intersect交集
计算交集代码段如下:(1 intersect 0 = null,1 intersect 1 = 1,0 intersect 0 = 0)
union并集
计算并集代码段如下:(1 union 0 = 1 0,1 union 1 = 1,0 union 0 = 0)
原理简介:
通过sys.columns表获取表的字段名与字段ID,循环字段名,并根据字段名去取到表中对应的值:如字段名为A,那么取ID为1的值:select A from test where id=1,取ID为2的值:select A from test where id=2,
然后将2个值进行交集与并集,字段循环结束后,得到@str_intersect,@str_union,计算比值:len(@str_intersect)*1.0/len(@str_union)
最终结果如下:
全部代码如下:(建表,见注释部分)
--create table Test(id int,A INT,B INT,C INT,D INT,E INT,F INT) --INSERT INTO TEST SELECT 1,1,1,1,0,0,0 --INSERT INTO TEST SELECT 2,0,1,0,1,0,1 --INSERT INTO TEST SELECT 3,1,1,1,1,0,1 --INSERT INTO TEST SELECT 4,1,1,1,0,1,0 --INSERT INTO TEST SELECT 5,0,1,0,1,1,1 --INSERT INTO TEST SELECT 6,0,0,1,0,1,1 --drop table Test_result --create table Test_result(id int,_1_ numeric(10,4),_2_ numeric(10,4),_3_ numeric(10,4),_4_ numeric(10,4),_5_ numeric(10,4),_6_ numeric(10,4)) --insert into Test_result select 1,null,null,null,null,null,null --insert into Test_result select 2,null,null,null,null,null,null --insert into Test_result select 3,null,null,null,null,null,null --insert into Test_result select 4,null,null,null,null,null,null --insert into Test_result select 5,null,null,null,null,null,null --insert into Test_result select 6,null,null,null,null,null,null SELECT name,column_id into #test FROM SYS.COLUMNS WHERE object_id =object_id('dbo.test') and column_id>1 declare @id_1 int=0,@id_2 int=0,@str_union varchar(max),@a_union int,@sql_union varchar(max),@str_intersect varchar(max),@a_intersect int,@sql_intersect varchar(max) declare @name varchar(20),@column_id int create table #a_union(num int) create table #a_intersect(num int) declare @min_id int=0,@max_id int=0,@global_min_id int=0,@global_max_id int=0 select @min_id=min(id),@max_id=max(id),@global_min_id=min(id),@global_max_id=max(id) from Test while(@min_id<[email protected]_id) begin select @[email protected]_id,@[email protected]_min_id while @id_2<[email protected]_max_id begin select @str_union='',@str_intersect='' while(select count(1) from #test)>0 begin select top 1 @name=name,@column_id=column_id from #test order by column_id select @sql_union='select CASE '+ 'WHEN (select count(1) from ( SELECT '[email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_1)+' union SELECT '[email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_2)+') as a)>1 THEN 1' +' WHEN ISNULL((SELECT '[email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_1)+' UNION SELECT ' [email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_2)+'),0)=0 THEN 0 ELSE 1 END' insert into #a_union exec(@sql_union) SELECT @a_union=num from #a_union delete from #a_union if(@a_union=1) select @[email protected] select @sql_intersect='select CASE WHEN ISNULL((SELECT '[email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_1)+' INTERSECT SELECT ' [email protected]+' FROM TEST WHERE ID='+convert(varchar,@id_2)+'),0)=0 THEN 0 ELSE 1 END' insert into #a_intersect exec(@sql_intersect) SELECT @a_intersect=num from #a_intersect delete from #a_intersect if(@a_intersect=1) select @[email protected] delete from #test where @name=name and @column_id=column_id end insert into #test SELECT name,column_id FROM SYS.COLUMNS WHERE object_id =object_id('dbo.test') and column_id>1 --select @str_union,@str_intersect,@column_id,@id_1,@id_2 if(@id_2=1) update Test_result set _1_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 if(@id_2=2) update Test_result set _2_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 if(@id_2=3) update Test_result set _3_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 if(@id_2=4) update Test_result set _4_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 if(@id_2=5) update Test_result set _5_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 if(@id_2=6) update Test_result set _6_= convert(numeric(10,4),len(@str_intersect)*1.0/len(@str_union)) where [email protected]_1 set @[email protected]_2+1 end set @[email protected]_id+1 end drop table #test drop table #a_union drop table #a_intersect ----------- --create table test_str_column(id int,str_columns varchar(max)) --insert into test_str_column select 1,null --insert into test_str_column select 2,null --insert into test_str_column select 3,null --insert into test_str_column select 4,null --insert into test_str_column select 5,null --insert into test_str_column select 6,null select * into #temp_test_table from test select name,column_id into #tmp_test_columns from sys.columns where object_id=object_id('dbo.test') and column_id>1 declare @id int,@col_name varchar(20),@col_id int,@string_columns varchar(max),@sql_rs varchar(max),@num_1 int create table #tmp_rs(num int) while (select count(1) from #temp_test_table)>0 begin select top 1 @id=id from #temp_test_table order by id set @string_columns='' while(select count(1) from #tmp_test_columns)>0 begin select top 1 @col_name=name,@col_id=column_id from #tmp_test_columns order by column_id select @sql_rs='select '[email protected]_name+' from test where id='+convert(varchar,@id) insert into #tmp_rs exec(@sql_rs) select @num_1=num from #tmp_rs if(@num_1=1) set @[email protected][email protected]_name delete from #tmp_test_columns where @col_name=name and @col_id=column_id delete from #tmp_rs end insert into #tmp_test_columns select name,column_id from sys.columns where object_id=object_id('dbo.test') and column_id>1 update test_str_column set [email protected]_columns where id [email protected] delete from #temp_test_table where @id=id end drop table #temp_test_table drop table #tmp_test_columns drop table #tmp_rs select * from test select * from test_str_column select * from Test_result
以上是关于SQL Server计算Jaccard系数—sim(i,j)的主要内容,如果未能解决你的问题,请参考以下文章
metric笔记:Jaccard 相似系数&Jaccard距离
聚类效果评估内部指标(Jaccard系数FM指数Rand指数)外部指标(DB指数Dunn指数)轮廓系数(Silhouette Coefficient)