sqlserver语句改造又想orderby 又想groupby

Posted 2023-03-30

select min(t1.id) id,t1.mrn from dbo.NURSING_RECORD_FORMS t1,EWELL_SYS_USERS t2
where ((t1.total_score>=45 and t1.template_id = 79)) and ward_no = '1000199'
and t1.record_time >='2014-07-14 08:00' and t1.record_time<= '2014-07-15 08:00'
and t1.recorder_code = t2.code group by t1.mrn

上面一段sql 现在是按mrn分组后取id值最小的，现在我想，按mrn区分以后按record_time降序排列以后取第一个，也就是最后记录的那条数据，怎么写？

参考技术A select t.*
from (select t1.*,t2.*,
row_number() over (partition by t1.mrn order by record_time desc) as rn
from dbo.NURSING_RECORD_FORMS t1,EWELL_SYS_USERS t2
where ((t1.total_score>=45 and t1.template_id = 79))
and ward_no = '1000199'
and t1.record_time >='2014-07-14 08:00'
and t1.record_time<= '2014-07-15 08:00'
and t1.recorder_code = t2.code
) t
where rn=1本回答被提问者采纳

今天又看到了华为的文章，我又想感慨一下，华为就是个逗逼