LeetCode --- 1046. Last Stone Weight 解题报告
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You are given an array of integers stones
where stones[i]
is the weight of the ith
stone.
We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x
and y
with x <= y
. The result of this smash is:
- If
x == y
, both stones are destroyed, and - If
x != y
, the stone of weightx
is destroyed, and the stone of weighty
has new weighty - x
.
At the end of the game, there is at most one stone left.
Return the smallest possible weight of the left stone. If there are no stones left, return 0
.
Example 1:
Input: stones = [2,7,4,1,8,1] Output: 1 Exp
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LeetCode --- 1046. Last Stone Weight 解题报告
LeetCode 1046. Last Stone Weight (最后一块石头的重量 )