如何在THREE.js中克隆Line对象的Mesh？

Posted 2021-05-03

我试图创建一个10行的for循环。但是line.Clone（）给了我一个错误，因为它没有找到任何要克隆的网格物体？如果您知道如何访问线的网格，请告诉我。

这是一些代码：

forward_RT(){

    var spotLight = new THREE.SpotLight( 0xffffff ); //White Color
    spotLight.position.set( 150, 500, -210 );
    scene_Main.add( spotLight );

    var material = new THREE.LineBasicMaterial( { color: 0xff0000 } );
    var geometry = new THREE.Geometry();
    geometry.vertices.push(new THREE.Vector3( spotLight.position.x, spotLight.position.y, spotLight.position.z) );
    geometry.vertices.push(new THREE.Vector3( ray_End_pos_X, ray_End_pos_Y, ray_End_pos_Z) );

    var line = new THREE.Line( geometry, material );

    for(var i=0; i<10; i++){
        //Also tried 
        //var newLine = line.clone(); & scene_Main.add(newLine);
        scene.add(line.clone());

        ray_End_pos_X += 50;
    }
}

答案

您的代码有几个问题（例如，您增加了ray_End_pos_X但不在循环中使用它）。我怀疑你可能只需要在每次迭代期间改变几何。

我会选择克隆几何和共享材料的新线。我快速检查，这工作：

    var rayX = 0, rayY=0, rayZ = 0;

    var material = new THREE.LineBasicMaterial( { color: 0xff0000 } );
    var geometry = new THREE.Geometry();
    geometry.vertices.push(new THREE.Vector3( spotLight.position.x, spotLight.position.y, spotLight.position.z) );
    geometry.vertices.push(new THREE.Vector3( rayX, rayY, rayZ) );

    for(var i=0; i<10; i++) {
        var newLine = new THREE.Line(geometry.clone(), material);
        newLine.geometry.vertices[1].x = rayX;
        this.context.scene.add(newLine);
        rayX += 0.1;
    }

这就是它的外观（红线，其余部分无关紧要）：