Jarvis OJ - DD-Hello -Writeup

Posted M4x@10.0.0.55

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Jarvis OJ - DD-Hello -Writeup

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题目:

分析:

第一次做这道题时,file查看发现是OS X和ios的可执行文件,就果断放弃了

后来又一想,OS X是基于FreeBSD的,那Mach-O文件和elf应该也有相通之处,于是就尝试用IDA打开文件,居然真的打开了

函数较少,并且都可F5出伪代码,逐个分析,整理如下:

关键代码:

  if ( !(result & 1) )
  {
    i = 0;
    while ( i < 55 )
    {
      key[(signed __int64)i] -= 2;
      key[(signed __int64)i] ^= k;
      ++i;
      ++k;
    }

 

key[]是已知的,i是循环变量,因此只需要找到k的值,从伪代码看不出什么

但k肯定是固定的,因此首先尝试爆破,脚本如下:

for kk in range(0, 256):
    key = [0x41, 0x10, 0x11, 0x11, 0x1B, 0x0A, 0x64, 0x67, 0x6A, 0x68, 0x62, 0x68, 0x6E, 0x67, 0x68, 0x6B, 0x62, 0x3D, 0x65, 0x6A, 0x6A, 0x3D, 0x68, 0x4, 0x5, 0x8, 0x3, 0x2, 0x2, 0x55, 0x8, 0x5D, 0x61, 0x55, 0x0A, 0x5F, 0x0D, 0x5D, 0x61, 0x32, 0x17, 0x1D, 0x19, 0x1F, 0x18, 0x20, 0x4, 0x2, 0x12, 0x16, 0x1E, 0x54, 0x20, 0x13, 0x14, 0x0, 0x0]
    try:
        k = kk
        i = 0
        while i < 55:
            key[i] -= 2
            key[i] ^= k
            
            i += 1
            k += 1
            
        ans = \'\'
        for c in key:
            ans += chr(c)
        
        print ans
        
    except:
        pass

 

运行并提取flag如下:


后来请教了学长,从汇编代码里找出了k的值,就不用爆破了

于是k即为dummy_functionwelcome_function的地址差值右移两位在与key[0]亦或,从IDA中可以看出dummy_functionwelcome_function的地址

得到新的非爆破脚本如下:

key = [0x41, 0x10, 0x11, 0x11, 0x1B, 0x0A, 0x64, 0x67, 0x6A, 0x68, 0x62, 0x68, 0x6E, 0x67, 0x68, 0x6B, 0x62, 0x3D, 0x65, 0x6A, 0x6A, 0x3D, 0x68, 0x4, 0x5, 0x8, 0x3, 0x2, 0x2, 0x55, 0x8, 0x5D, 0x61, 0x55, 0x0A, 0x5F, 0x0D, 0x5D, 0x61, 0x32, 0x17, 0x1D, 0x19, 0x1F, 0x18, 0x20, 0x4, 0x2, 0x12, 0x16, 0x1E, 0x54, 0x20, 0x13, 0x14, 0x0, 0x0]

k = ((0x0000000100000CB0 - 0x0000000100000C90) >> 2) ^ key[0]
i = 0
while i < 55:
    key[i] -= 2
    key[i] ^= k
    
    i += 1
    k += 1
    
ans = \'\'
for c in key:
    ans += chr(c)

print ans[1: ]

 

运行

于是flag即为DDCTF-5943293119a845e9bbdbde5a369c1f50@didichuxing.com

 

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