java 242.有效的Anagram.java

Posted 2021-05-08

public class Solution {
    public boolean isAnagram(String s, String t) {
        if (s == null || t == null) return false;
        int len1 = s.length();
        int len2 = t.length();
        if (len1 != len2) return false;
        int[] vector = new int[26];
        for (int i = 0; i < len1; i++) {
            vector[s.charAt(i) - 'a']++;
            vector[t.charAt(i) - 'a']--;
        }
        for (int i : vector) {
            if(i != 0) {
                return false;
            }
        }
        return true;
    }
}