算法4-1.1.7分别给出以下代码段打印的值

Posted 2022-07-11 wx5cb71f4b705da

分别给出以下代码段打印的值：
a.double t=9.0;
while (Math.abs(t-9.0/t)>.001)
t=(9.0/t+t)/2.0;
StdOut.printf("%.5f\\n",t);

b. int sum=0;
for (int i=1;i<1000;i++)
for (int j=0;j<i;j++)
sum++;
StdOut.println(sum);
c. int sum=0;
for (int i=1;i<1000;i*=2)
for (int j=0;j<1000;j++)
sum++;
StdOut.println(sum);
代码:

public class Main 
    public static void main(String[] args) 
        //System.out.println(.001);
        double t  =9.0;
        while (Math.abs(t-9.0/t) > .001)
            t = (9.0/t+t) /2.0;
        System.out.printf("%.5f\\n", t);

        int sum = 0;
        for (int i = 0; i < 1000; i++)
            for (int j = 0; j < i; j ++)
                sum++;
        StdOut.println(sum);
        sum = 0;
        for (int i = 1; i < 1000; i *=2)
            for (int j = 0; j < 1000; j ++)
                sum++;
        StdOut.println(sum);
    

答案:

3.00009
499500
10000

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