如何在春季oauth2中获取访问令牌

Posted 2023-02-27

【中文标题】如何在春季oauth2中获取访问令牌

【英文标题】：How to get access token in spring oauth2

【发布时间】：2016-04-19 19:12:53

【问题描述】：

下面是我用来合并 spring-security-oauth2 的 security.xml 文件。

<?xml version="1.0" encoding="UTF-8" ?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:oauth="http://www.springframework.org/schema/security/oauth2"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:sec="http://www.springframework.org/schema/security" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/security/oauth2 http://www.springframework.org/schema/security/spring-security-oauth2-2.0.xsd
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
    http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.2.xsd 
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd ">


<!-- @author Nagesh.Chauhan([e-mail]) -->
<!-- This is default url to get a token from OAuth -->
<http pattern="/oauth/token" create-session="stateless"
    authentication-manager-ref="clientAuthenticationManager"
    xmlns="http://www.springframework.org/schema/security">
    <intercept-url pattern="/oauth/token" access="IS_AUTHENTICATED_FULLY" />
    <anonymous enabled="false" />
    <http-basic entry-point-ref="clientAuthenticationEntryPoint" />
    <!-- include this only if you need to authenticate clients via request 
        parameters -->
    <custom-filter ref="clientCredentialsTokenEndpointFilter"
        after="BASIC_AUTH_FILTER" />
    <access-denied-handler ref="oauthAccessDeniedHandler" />
</http>

<!-- This is where we tells spring security what URL should be protected 
    and what roles have access to them -->
<http pattern="/api/**" create-session="never"
    entry-point-ref="oauthAuthenticationEntryPoint"
    access-decision-manager-ref="accessDecisionManager"
    xmlns="http://www.springframework.org/schema/security">
    <anonymous enabled="false" />
    <intercept-url pattern="/api/**" access="ROLE_APP" />
    <custom-filter ref="resourceServerFilter" before="PRE_AUTH_FILTER" />
    <access-denied-handler ref="oauthAccessDeniedHandler" />
</http>


<bean id="oauthAuthenticationEntryPoint"
    class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
    <property name="realmName" value="test" />
</bean>

<bean id="clientAuthenticationEntryPoint"
    class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
    <property name="realmName" value="test/client" />
    <property name="typeName" value="Basic" />
</bean>

<bean id="oauthAccessDeniedHandler"
    class="org.springframework.security.oauth2.provider.error.OAuth2AccessDeniedHandler" />

<bean id="clientCredentialsTokenEndpointFilter"
    class="org.springframework.security.oauth2.provider.client.ClientCredentialsTokenEndpointFilter">
    <property name="authenticationManager" ref="clientAuthenticationManager" />
</bean>

<bean id="accessDecisionManager" class="org.springframework.security.access.vote.UnanimousBased"
    xmlns="http://www.springframework.org/schema/beans">
    <constructor-arg>
        <list>
            <bean class="org.springframework.security.oauth2.provider.vote.ScopeVoter" />
            <bean class="org.springframework.security.access.vote.RoleVoter" />
            <bean class="org.springframework.security.access.vote.AuthenticatedVoter" />
        </list>
    </constructor-arg>
</bean>

<authentication-manager id="clientAuthenticationManager"
    xmlns="http://www.springframework.org/schema/security">
    <authentication-provider user-service-ref="clientDetailsUserService" />
</authentication-manager>


<!-- This is simple authentication manager, with a hardcoded user/password 
    combination. We can replace this with a user defined service to get few users 
    credentials from DB -->
<authentication-manager alias="authenticationManager"
    xmlns="http://www.springframework.org/schema/security">
    <authentication-provider>
        <user-service>
            <user name="beingjavaguys" password="spring@java" authorities="ROLE_APP" />
        </user-service>
    </authentication-provider>
</authentication-manager>

<bean id="clientDetailsUserService"
    class="org.springframework.security.oauth2.provider.client.ClientDetailsUserDetailsService">
    <constructor-arg ref="clientDetails" />
</bean>


<!-- This defined token store, we have used inmemory tokenstore for now 
    but this can be changed to a user defined one -->
<bean id="tokenStore"
    class="org.springframework.security.oauth2.provider.token.InMemoryTokenStore" />

<!-- This is where we defined token based configurations, token validity 
    and other things -->
<bean id="tokenServices"
    class="org.springframework.security.oauth2.provider.token.DefaultTokenServices">
    <property name="tokenStore" ref="tokenStore" />
    <property name="supportRefreshToken" value="true" />
    <property name="accessTokenValiditySeconds" value="120" />
    <property name="clientDetailsService" ref="clientDetails" />
</bean>

<bean id="userApprovalHandler"
    class="org.springframework.security.oauth2.provider.approval.TokenServicesUserApprovalHandler">
    <property name="tokenServices" ref="tokenServices" />
</bean>

<oauth:authorization-server
    client-details-service-ref="clientDetails" token-services-ref="tokenServices"
    user-approval-handler-ref="userApprovalHandler">
    <oauth:authorization-code />
    <oauth:implicit />
    <oauth:refresh-token />
    <oauth:client-credentials />
    <oauth:password />
</oauth:authorization-server>

<oauth:resource-server id="resourceServerFilter"
    resource-id="test" token-services-ref="tokenServices" />

<oauth:client-details-service id="clientDetails">
    <!-- client -->
    <oauth:client client-id="restapp"
        authorized-grant-types="authorization_code,client_credentials"
        authorities="ROLE_APP" scope="read,write,trust" secret="secret" />

    <oauth:client client-id="restapp"
        authorized-grant-types="password,authorization_code,refresh_token,implicit"
        secret="restapp" authorities="ROLE_APP" />

</oauth:client-details-service>

<sec:global-method-security
    pre-post-annotations="enabled" proxy-target-class="true">
    <!--you could also wire in the expression handler up at the layer of the 
        http filters. See https://jira.springsource.org/browse/SEC-1452 -->
    <sec:expression-handler ref="oauthExpressionHandler" />
</sec:global-method-security>

<oauth:expression-handler id="oauthExpressionHandler" />
<oauth:web-expression-handler id="oauthWebExpressionHandler" />

到目前为止，为了获取令牌，我必须以以下格式提出请求： [http://localhost:8080/SpringRestSecurityOauth/oauth/token?grant_type=password&client_id=restapp&client_secret=restapp&username=beingjavaguys&password=spring@java]

现在我希望以 json 格式发送查询参数，例如 "grant_type":"密码", "client_id":"restapp", “client_secret”：“restapp”， "用户名":"被 javaguys", “密码”：“spring@java”

我必须在 spring-security.xml 文件中进行哪些更改才能在 json 中发送查询参数？

【参考方案1】：

开箱即用不支持的 AFAIK。为此，您必须编写自己的 REST 服务接口。

但是，您建议的格式似乎也不像受支持的版本那样“类似于 REST”（应使用 GET 请求来检索信息）。至少如果您将其视为检索而不是创建令牌。