Cakephp 1.3：如何迁移到我的文章标签 - 功能

Posted 2023-02-26

【中文标题】Cakephp 1.3：如何迁移到我的文章标签 - 功能

【英文标题】：Cakephp 1.3: How to migrate into my Article Tabel - Function

【发布时间】：2012-01-17 20:45:44

【问题描述】：

我有一个使用另一个 php cms 系统的应用程序，我现在将其转移到 CakePHP 1.3。我已经到了需要将tblnewsarticles 中的所有旧文章转移到我的新CakePHP 表articles 的地步。这些表有不同的字段，但我已经能够将我需要的所有字段映射到我的新表。我在ArticlesController class 中创建了以下临时migrate 函数来为我执行此操作，但无法将数据保存到我的表中。一切似乎都很好，包括我用debug($data) 和debug($articles) 进行了测试，它显示了数据，但我无法保存任何东西。我看不出有什么问题，因此感谢您的帮助...

//TEMPORARY FUNCTION THAT WILL BE DELETED/DEACTIVATED AFTER MIGRATION
function migrate()                
        // FOR TESTING PURPOSES I SET LIMIT=1, BUT I HAVE OVER 4000 ARTICLES TO TRANSFER
    $articles = $this->Article->query(
        "SELECT articleID,subcategoryID,article_title,article_html,article_date,image_extension FROM tblnewsarticles LIMIT 1;"
    );

    foreach($articles as $article)
        $data['Article']['id'] = $article['tblnewsarticles']['articleID'];
        $data['Article']['published'] = 1;
        $data['Article']['title'] = $article['tblnewsarticles']['article_title'];
        $data['Article']['body'] = $article['tblnewsarticles']['article_html'];
        $data['Article']['main_image'] = 'cat_'.$article['tblnewsarticles']['subcategoryID'].'/'.$article['tblnewsarticles']['articleID'].'.'.$article['tblnewsarticles']['image_extension'];
        $data['Article']['category_id'] = $article['tblnewsarticles']['subcategoryID'];
        $data['Article']['user_id'] = 2;
        $data['Article']['created'] = $article['tblnewsarticles']['article_date'];

        if (!empty($data)) 
             $this->Article->create();
             $this->Article->save($data);                       
             $this->Session->setFlash('Migration processed successfully');
        else                      
             $this->Session->setFlash('Unsuccessful');
        
       

======== 这就是我所做的，对我有用 ================

function migrateArticle()

$articles = $this->Article->query(
                    "SELECT articleID,subcategoryID,article_title,article_html,article_date,image_extension FROM tblnewscategories;"
    );

    foreach($articles as $article)

    $categoryID = $article['tblnewsarticles']['subcategoryID'];
    $articleID = $article['tblnewsarticles']['articleID'];
    $articleTitle = $article['tblnewsarticles']['article_title'];
    $articleSlug = str_replace(" ","-",strtolower($articleTitle));
    $articleBody = $article['tblnewsarticles']['article_html'];
    $articleImage = 'cat_'.$article['tblnewsarticles']['subcategoryID'].'/'.$article['tblnewsarticles']['articleID'].'.'.$article['tblnewsarticles']['image_extension'];
    $articleDate = $article['tblnewsarticles']['article_date'];

   $this->Article->query("INSERT INTO categories (id, published, title, slug, body, main_image, category_id, user_id, created) VALUES('$articleID', '1', '$articleTitle', '$articleSlug', '$articleBody', '$articleImage', '$categoryID', '2', '$articleDate');");   
       

【问题讨论】：

为什么不在数据库级别这样做呢？它可能会少得多的代码。

数据库级别？抱歉，您是什么意思？

【参考方案1】：

不要尝试一次加载 4000 条记录，然后单独处理它们。使用复制所有内容的单个数据库查询可能更容易。类似的东西

INSERT INTO articles
    (id, published, title, body,
     main_image,
     category_id, user_id, created)
    SELECT articleID, 1, article_title, article_html,
          CONCAT('cat_', subcategoryID, '/', articleID, '.', image_extension),
          subcategoryID, 2, article_date
    FROM tblnewsarticles;

（当然，未经测试）

【讨论】：

感谢 Arjan，根据您的建议，我能够完成我需要的工作....非常感谢...在 EDIT 中查看我的问题