Yii2 - 在模型中提交时如何从小部件中获取数据？

Posted 2023-02-26

【中文标题】Yii2 - 在模型中提交时如何从小部件中获取数据？

【英文标题】：Yii2 - How to get the data from a Widget when submiting in a model?

【发布时间】：2017-05-04 18:33:33

【问题描述】：

我正在使用 Widget 裁剪图像并将其上传到 Yii2 的服务器中。Yii2 - Cropper

我已经根据小部件的文档在视图中实现了小部件，并将数据提交给模型，该模型应该将上传文件的名称保存到数据库中的新条目中。但是，它始终将其保存为 Null。

newform.php

<?php
    use yii\helpers\html;
    use yii\widgets\ActiveForm;
    use common\budyaga\cropper\Widget;
    use yii\helpers\Url;
    $this->title='Upload New';
?>
<h1><?= Html::encode($this->title) ?></h1>
<?php $form = ActiveForm::begin(); ?>
<?= $form->field($model, 'title') -> textInput();?>
<?= $form->field($model, 'description') -> textInput(); ?>
<?= $form->field($model, 'link') -> textInput(); ?>
<?= $form->field($model, 'image')-> widget(Widget::className(), [
    'uploadUrl' => Url::toRoute('/admin/uploadPhoto'),
    'width' => 236,
    'height' => 234,
    'cropAreaWidth' => 500,
    'cropAreaHeight' => 500,
    'thumbnailWidth' => 236,
    'thumbnailHeight' => 234,
    ]);?>
<div class="form-group">
    <?= Html::submitButton('Save', ['class' => 'btn btn-primary']); ?>
</div>
<?php ActiveForm::end(); ?>

控制器中的方法

public function actionNews()
    $model = new NewsForm();
    $model->setScenario('addNew');
    if ($model->load(Yii::$app->request->post()) && $model->addNew()) 
        return $this->render('newsmanager');
     else 
        return $this->render('newform', ['model' => $model]);
    

型号

class Newnews extends \yii\db\ActiveRecord
    public static function tableName()
    
        return 'news';
    

    public function rules()
    
       return [
            [['visits', 'user_id'], 'integer'],
            [['user_id'], 'required'],
            [['title', 'image'], 'string', 'max' => 45],
            [['description', 'link'], 'string', 'max' => 255],
            [['user_id'], 'exist', 'skipOnError' => true, 'targetClass' => User::className(), 'targetAttribute' => ['user_id' => 'id']],
       ];
    

    public function attributeLabels()
    
        return [
            'idnew' => 'Idnew',
            'title' => 'Title',
            'description' => 'Description',
            'image' => 'Image',
            'visits' => 'Visits',
            'user_id' => 'User_ID',
            'link' => 'Link',
            'dateu' => 'Dateu'
        ];
    

NewsForm.php

class NewsForm extends Model

    public $image;
    public $title;
    public $description;
    public $link;

    public function rules()
    
        return [
            [['title','description','link'],'required'],
            ['image','safe', 'on'=>'addNew']
        ];
    

    public function addNew()
        if($this->validate())
            $newnew=new Newnew();
            $newnew->title=$this->title;
            $newnew->description=$this->description;
            $newnew->link=$this->link;
            $newnew->image;
            $newnew->user_id=Yii::$app->getUser()->getId();
            $newnew->visits=0;
            $newnew->dateu=date("Y-m-d H:i:s");
            return $newnew->save();
        
    

当我尝试保存数据时，图像中出现 Null。我不知道如何从 wiget 中获取数据以提取模型中图像的名称。如何访问这些数据？

【参考方案1】：

添加NewsForm：

 /**
 * @var UploadedFile
 */
public $imageFile;

在验证规则中：

[['imageFile'], 'file', 'mimeTypes' => 'image/jpeg, image/png', 'maxSize' => 5000000],

在addNew()函数中：

$this->imageFile = UploadedFile::getInstance($this, 'imageFile');
$file = $this->imageFile;
$fname = $file->baseName
$fext = $file->extension
//etc...
//then validate and save file and model as you want.

在视图中：

<?= $form->field($model, 'imageFile ')-> widget(Widget::className(), [
//config...
]);