Java 如何为循环中的每次迭代播放声音？
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【中文标题】Java 如何为循环中的每次迭代播放声音？【英文标题】：Java How would I play a sound for every iteration in a loop? 【发布时间】：2012-03-31 15:59:11 【问题描述】：例子：
For(int i=0; i<4; i++)
playSound("Sound.wav");
我有以下课程：
主要
import java.io.IOException;
import java.util.*;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.UnsupportedAudioFileException;
public class MainClass
public static void main (String [] args)
throws UnsupportedAudioFileException, IOException, LineUnavailableException, InterruptedException
Thread main = new Thread();
Thread sound = new Thread();
main.start();
Scanner in = new Scanner (System.in);
Encode MorseCode = new Encode();
System.out.print("Enter a Phrase: ");
String input = in.next();
String selected = "";
String converted = "";
String morse = "";
for (int i = 0; i < input.length(); i++)
//for every character instantiate a new sound object
playSound ps = new playSound();
//Select the next character
selected = input.charAt(i) +"";
// Convert the character
converted = MorseCode.getEncode(selected);
//Trying to pause the main thread until the sound clip finishes
if(converted == ".")
//set main thread to sleep for duration of sound clip
//main.sleep(ps.getWait()*1000);
main.yield();
//start other thread to complete the task of playing the soudn
sound.start();
ps.playBlip();
main.join();
morse = morse +" "+converted;
converted = "";
System.out.print("Morse Code: "+morse);
编码器
public class Encode
public Encode()
public String getEncode(String toEncode)
String morse = toEncode;
if (toEncode.equalsIgnoreCase("a"))
morse = ".-";
if (toEncode.equalsIgnoreCase("b"))
morse = "-...";
if (toEncode.equalsIgnoreCase("c"))
morse = "-.-.";
if (toEncode.equalsIgnoreCase("d"))
morse = "-..";
if (toEncode.equalsIgnoreCase("e"))
morse = ".";
if (toEncode.equalsIgnoreCase("f"))
morse = "..-.";
if (toEncode.equalsIgnoreCase("g"))
morse = "--.";
if (toEncode.equalsIgnoreCase("h"))
morse = "....";
if (toEncode.equalsIgnoreCase("i"))
morse = "..";
if (toEncode.equalsIgnoreCase("j"))
morse = ".---";
if (toEncode.equalsIgnoreCase("k"))
morse = "-.-";
if (toEncode.equalsIgnoreCase("l"))
morse = ".-..";
if (toEncode.equalsIgnoreCase("m"))
morse = "--";
if (toEncode.equalsIgnoreCase("n"))
morse = "-.";
if (toEncode.equalsIgnoreCase("o"))
morse = "---";
if (toEncode.equalsIgnoreCase("p"))
morse = ".--.";
if (toEncode.equalsIgnoreCase("q"))
morse = "--.-";
if (toEncode.equalsIgnoreCase("r"))
morse = ".-.";
if (toEncode.equalsIgnoreCase("s"))
morse = "...";
if (toEncode.equalsIgnoreCase("t"))
morse = "-";
if (toEncode.equalsIgnoreCase("u"))
morse = "..-";
if (toEncode.equalsIgnoreCase("v"))
morse = "...-";
if (toEncode.equalsIgnoreCase("w"))
morse = ".--";
if (toEncode.equalsIgnoreCase("x"))
morse = "-..-";
if (toEncode.equalsIgnoreCase("y"))
morse = "-.--";
if (toEncode.equalsIgnoreCase("z"))
morse = "--..";
if (toEncode.equalsIgnoreCase("0"))
morse = "-----";
if (toEncode.equalsIgnoreCase("1"))
morse = ".----";
if (toEncode.equalsIgnoreCase("2"))
morse = "..---";
if (toEncode.equalsIgnoreCase("3"))
morse = "...--";
if (toEncode.equalsIgnoreCase("4"))
morse = "....-";
if (toEncode.equalsIgnoreCase("5"))
morse = ".....";
if (toEncode.equalsIgnoreCase("6"))
morse = "-....";
if (toEncode.equalsIgnoreCase("7"))
morse = "--...";
if (toEncode.equalsIgnoreCase("8"))
morse = "---..";
if (toEncode.equalsIgnoreCase("9"))
morse = "----.";
if (toEncode.equalsIgnoreCase("."))
morse = ".-.-";
if (toEncode.equalsIgnoreCase(","))
morse = "--..--";
if (toEncode.equalsIgnoreCase("?"))
morse = "..--..";
return morse;
播放声音
import java.io.File;
import java.io.IOException;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.Audiosystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineEvent;
import javax.sound.sampled.LineListener;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.UnsupportedAudioFileException;
public class playSound
public playSound()
public void playBlip() throws UnsupportedAudioFileException, IOException, LineUnavailableException
File soundFile = new File("blip.wav");
AudioInputStream sound = AudioSystem.getAudioInputStream(soundFile);
DataLine.Info info = new DataLine.Info(Clip.class, sound.getFormat());
Clip clip = (Clip) AudioSystem.getLine(info);
clip.open(sound);
clip.addLineListener( new LineListener()
public void update(LineEvent event)
if (event.getType() == LineEvent.Type.STOP)
event.getLine().close();
System.exit(0);
);
clip.start();
clip.drain();
clip.close();
public int getSoundDurationForThreadWait() throws UnsupportedAudioFileException, IOException, LineUnavailableException
File soundFile = new File("blip.wav");
AudioInputStream sound = AudioSystem.getAudioInputStream(soundFile);
DataLine.Info info = new DataLine.Info(Clip.class, sound.getFormat());
Clip clip = (Clip) AudioSystem.getLine(info);
clip.open(sound);
//making this method return milliseconds since threads waits are in this unit
return (int) (clip.getMicrosecondLength()/1000);
问题 程序只播放一次声音。我怀疑存在线程阻塞问题。
期望的结果：
输入短语：你好
按照摩尔斯电码的预期播放音频
【问题讨论】：
@Osw 它只播放一次。我认为theres线程问题。主线程应该等到每个音频播放，但它存在于第一次播放之后。 我看不到您实际在等待音频播放的任何地方，因此它不会全部播放。 @Lattyware 你能提供答案来帮助我吗？非常感谢 “按照摩尔斯电码的方式播放音频” 对于瞬时声波发生器，请参阅Beeper。将字母转换为开/关时间代码是另一回事，但我可能会使用javax.swing.Timer 或 java.util.Timer
【参考方案1】：
具体的问题是你的playBlip()方法被设计成在整个程序到达声音片段的结尾时终止：
clip.addLineListener( new LineListener()
public void update(LineEvent event)
if (event.getType() == LineEvent.Type.STOP)
event.getLine().close();
System.exit(0); // <------------ terminate the JVM
);
但总的来说，我认为您应该更仔细地检查您的方法；除了混淆之外，您有很多似乎没有任何用途的代码。例如，您有两个Thread 实例main 和sound，它们的设计目的是完全不做任何事情：调用main.start() 将启动一个立即退出的新线程。
【讨论】：
好的，所以我删除了 System.exit(0)。应该如何处理线程来处理播放声音？ @***：你为什么要这样做？drain 是同步的；这似乎正是你想要的。您想等到声音播放完毕，不是吗？
Ruakh 是的，这正是我想要的，我只是不确定 api 处理的是什么。以上是关于Java 如何为循环中的每次迭代播放声音？的主要内容，如果未能解决你的问题，请参考以下文章