从 Json 数组中提取 JSON 对象到 mysql 8

Posted 2023-02-24

【中文标题】从 Json 数组中提取 JSON 对象到 mysql 8

【英文标题】：Extract JSON Object from Json Array into mysql 8

【发布时间】：2021-11-27 09:54:04

【问题描述】：

[""delivered":0,"deliveryDate":1633537686480,"toUserId":148",""delivered":0,"deliveryDate":1633537687590,"toUserId":226"," "delivered":1,"deliveryDate":1633537687741,"toUserId":160",""delivered":0,"deliveryDate":1633537687863,"toUserId":262",""delivered":0, "deliveryDate":1633537688019,"toUserId":263",""delivered":0,"deliveryDate":1633537688174,"toUserId":264",""delivered":0,"deliveryDate":1633537688325, "toUserId":265"]

我想从下表中提取此 JSON 数组，然后进一步提取我提供 userId 和 deliveryStatus 的 JSON 对象。我该如何实现？

预期结果 当我给 toUserid 148 并且还给了 deliveryStatus= 0

"delivered":0,"deliveryDate":1633537686480,"toUserId":148

【参考方案1】：

您可以使用JSON_TABLE函数将JSON转换为行；然后使用-> 运算符过滤：

SELECT t.id, JSON_PRETTY(j.obj)
FROM t
CROSS JOIN JSON_TABLE(t.delivery_status, '$[*]' COLUMNS(
  obj JSON PATH '$'
)) AS j
WHERE j.obj->'$.delivered' = 0 AND j.obj->'$.toUserId' = 148

【讨论】：

谢谢！为了您的快速回复。对不起，我对 Json 进行了一些更改，例如 ["\"delivered\":0,\"deliveryDate\":1633537686480,\"toUserId\":148","\"delivered\" :0,\"deliveryDate\":1633537687590,\"toUserId\":226","\"delivered\":1,\"deliveryDate\":1633537687741,\"toUserId\":160"," \"delivered\":0,\"deliveryDate\":1633537687863,\"toUserId\":262","\"delivered\":0,\"deliveryDate\":1633537688019,\"toUserId\" :263","\"delivered\":0,\"deliveryDate\":1633537688174,\"toUserId\":264","\"delivered\":0,\"deliveryDate\":1633537688325 ,\"toUserId\":265"]

现在我怎样才能做到这一点，我只想返回结果？

在我发布的查询中更改列名并不难。

不，我的问题是其他问题，我知道更改列名并不难，但谢谢！！

我的问题是，现在我有一个 JSON 数组，但 JsonObject 充当字符串类型，现在由于字符串类型，我无法提取数据，所以这是我的问题