oracle左外连接不显示右空值
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【中文标题】oracle左外连接不显示右空值【英文标题】:oracle left outer joins not showing right null values 【发布时间】:2010-09-26 15:04:03 【问题描述】:我在 oracle 中创建一个似乎不想加入缺失值的查询时遇到问题
我的桌子是这样的:
table myTable(refnum, contid, type)
values are:
1, 10, 90000
2, 20, 90000
3, 30, 90000
4, 20, 10000
5, 30, 10000
6, 10, 20000
7, 20, 20000
8, 30, 20000
我所关注的领域的细分如下:
select a.refnum from myTable a where type = 90000
select b.refnum from myTable b where type = 10000 and contid in (select contid from myTable where type = 90000)
select c.refnum from myTable c where type = 20000 and contid in (select contid from myTable where type = 90000)
我查询的结果是这样的:
a.refnum, b.refnum, c.refnum
我认为这会起作用:
select a.refnum, b.refnum, c.refnum
from myTable a
left outer join myTable b on (a.contid = b.contid)
left outer join myTable c on (a.contid = c.contid)
where a.id_tp_cd = 90000
and b.id_tp_cd = 10000
and c.id_tp_cd = 20000
所以值应该是:
1, null, 6
2, 4, 7
3, 5, 8
但它只返回:
2, 4, 7
3, 5, 8
我认为左连接会显示左侧的所有值并为右侧创建一个空值。
帮助:(
【问题讨论】:
【参考方案1】:你说的对,左连接将在没有匹配的地方返回空值,但是当你将这个限制添加到你的 where 子句时,你不允许返回这些空值:
and b.id_tp_cd = 10000
and c.id_tp_cd = 20000
您应该可以将它们放在连接的“on”子句中,这样只会返回右侧的相关行。
select a.refnum, b.refnum, c.refnum
from myTable a
left outer join myTable b on (a.contid = b.contid and b.id_tp_cd = 10000)
left outer join myTable c on (a.contid = c.contid and c.id_tp_cd = 20000)
where a.id_tp_cd = 90000
【讨论】:
【参考方案2】:或者使用Oracle语法代替ansi
select a.refnum, b.refnum, c.refnum
from myTable a, mytable b, mytable c
where a.contid=b.contid(+)
and a.contid=c.contid(+)
and a.type = 90000
and b.type(+) = 10000
and c.type(+) = 20000;
REFNUM REFNUM REFNUM
---------- ---------- ----------
1 6
2 4 7
3 5 8
【讨论】:
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