图像上传 CURL 命令到 PHP Curl
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【中文标题】图像上传 CURL 命令到 PHP Curl【英文标题】：Image upload CURL command to PHP Curl 【发布时间】：2016-03-31 07:40:25 【问题描述】：我对 php CURL 很陌生，并试图调用 API 来进行图像上传（一次多个文件）。 API 文档在 CURL 中给出了以下示例。我已经测试过了，它正在工作。
curl -H "Authorization: Bearer 123456789" -i -X POST -F "whitespace=1" \
-F "imageData[]=@/path/to/images/milk.jpg" \
-F "imageData[]=@/path/to/images/peas.jpg" \
https://mytestapi.com/1.0/uploadimages
现在我需要将其转换为 PHP Curl。出于某种原因，我总是收到错误“imageData”参数无效。有人可以帮忙吗
$token = '123456789';
$imgUrl = 'https://mytestapi.com/1.0/uploadimages';
$data_to_post = array();
$data_to_post['whitespace'] = '1';
$data_to_post['imageData[]'] = '@/path/to/images/milk.jpg';
$data_to_post['imageData[]'] = '@/path/to/images/peas.jpg';
$curl = curl_init($imgUrl);
curl_setopt($curl, CURLOPT_HTTPHEADER, ['Authorization: Bearer '.$token]);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl,CURLOPT_POST, 1);
curl_setopt($curl,CURLOPT_POSTFIELDS, $data_to_post);
$data = json_decode(curl_exec($curl));
$responseCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);
curl_close($curl);
var_dump($data);
【问题讨论】：
你会给谁赏金 感谢赏金。如果你愿意，你可以投票 【参考方案1】：尝试给出图片的完整路径而不是'@/path/to/images/milk.jpg';
这里是更新的代码：
$token = '123456789';
$imgUrl = 'https://mytestapi.com/1.0/uploadimages';
$data_to_post = array();
$data_to_post['whitespace'] = '1';
$data_to_post['imageData'][] = "@".$imgUrl.'/path/to/images/milk.jpg';
$data_to_post['imageData'][] = "@".$imgUrl.'/path/to/images/peas.jpg';
$curl = curl_init($imgUrl);
curl_setopt($curl, CURLOPT_HTTPHEADER, ['Authorization: Bearer '.$token]);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl,CURLOPT_POST, 1);
curl_setopt($curl,CURLOPT_POSTFIELDS, $data_to_post);
$data = json_decode(curl_exec($curl));
$responseCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);
curl_close($curl);
var_dump($data);
如果这不起作用，请告诉我。
【讨论】：
不适用于完整路径。无论如何 $imgUrl 是 API URL，所以你的代码将它附加到图像文件名没有意义？无论如何，我现在能够使用 php curl file create 修复它【参考方案2】：我自己解决了这个问题。必须使用 php curl file create 来使其工作，而不是附加 '@'
http://www.php.net/manual/es/function.curl-file-create.php
【讨论】：
【参考方案3】：如何使用 PHP cURL 上传文件
<?php
// Helper function courtesy of https://github.com/guzzle/guzzle/blob/3a0787217e6c0246b457e637ddd33332efea1d2a/src/Guzzle/Http/Message/PostFile.php#L90
function getCurlValue($filename, $contentType, $postname)
// PHP 5.5 introduced a CurlFile object that deprecates the old @filename syntax
// See: https://wiki.php.net/rfc/curl-file-upload
if (function_exists('curl_file_create'))
return curl_file_create($filename, $contentType, $postname);
// Use the old style if using an older version of PHP
$value = "@$this->filename;filename=" . $postname;
if ($contentType)
$value .= ';type=' . $contentType;
return $value;
$filename = '/path/to/file.jpg';
$cfile = getCurlValue($filename,'image/jpeg','cattle-01.jpg');
//NOTE: The top level key in the array is important, as some apis will insist that it is 'file'.
$data = array('file' => $cfile);
$ch = curl_init();
$options = array(CURLOPT_URL => 'http://your/server/api/upload',
CURLOPT_RETURNTRANSFER => true,
CURLINFO_HEADER_OUT => true, //Request header
CURLOPT_HEADER => true, //Return header
CURLOPT_SSL_VERIFYPEER => false, //Don't veryify server certificate
CURLOPT_POST => true,
CURLOPT_POSTFIELDS => $data
);
curl_setopt_array($ch, $options);
$result = curl_exec($ch);
$header_info = curl_getinfo($ch,CURLINFO_HEADER_OUT);
$header_size = curl_getinfo($ch, CURLINFO_HEADER_SIZE);
$header = substr($result, 0, $header_size);
$body = substr($result, $header_size);
curl_close($ch);
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>File Upload results</title>
</head>
<body>
<p>Raw Result: <?=$result?>
<p>Header Sent: <?=$header_info?></p>
<p>Header Received: <?=$header?></p>
<p>Body: <?=$body?></p>
</body>
</html>
【讨论】：
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