在 SwiftUI 中通过摇动手势(使用 UIKit)设置 EnvironmentObject 不会更新视图

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【中文标题】在 SwiftUI 中通过摇动手势(使用 UIKit)设置 EnvironmentObject 不会更新视图【英文标题】:Setting EnvironmentObject from a Shake Gesture (using UIKit) in SwiftUI doesn't update View 【发布时间】:2020-02-10 19:57:43 【问题描述】:

我希望通过物理摇晃设备来触发 SwiftUI 功能。由于此时 SwiftUI 还没有运动检测功能,所以我需要使用 UIKit 集成和协调器返回一个 Bool 值,该值表示设备已被晃动,从而触发 SwiftUI 功能。

以下代码在识别设备的晃动方面都非常有效(独立的“makeShakerSound()”函数证明了这一点,该函数在晃动时播放声音片段,效果很好)。除了识别抖动的工作代码之外,我还包括了用于从 ContentView 调用 ShakableViewRepresentable(isShaken: $shakeOccurred) 的代码,如下所示。

我创建了一个 EnvironmentObject 来标记设备已被摇动,并使用 objectWillChange 来宣布发生了变化。

我的问题是这样的:当检测到晃动时,晃动的声音效果很好,但是我的 ContentView 没有更新环境对象 myDevice.isShaken 的变化。我认为使用 objectWillChange 可能会解决这个问题,但事实并非如此。我错过了什么?

抱歉 - 我对此有点陌生。

/* CREATE AN ENVIRONMENTAL OBJECT TO INDICATE DEVICE HAS BEEN SHAKEN */

import Combine
import SwiftUI

class MyDevice: ObservableObject 
    // let objectWillChange = ObservableObjectPublisher()
    var isShaken: Bool = false 
        willSet 
            self.objectWillChange.send()
        
    



/* DETECT SHAKE GESTURE AND FLAG THAT SHAKING HAS OCCURRED */

import UIKit
import SwiftUI

struct ShakableViewRepresentable: UIViewControllerRepresentable 

    class Coordinator: NSObject 
        var parent: ShakableViewRepresentable
        init(_ parent: ShakableViewRepresentable) 
            self.parent = parent
        
    

    func makeCoordinator() -> ShakableViewRepresentable.Coordinator 
        Coordinator(self)
    

    func makeUIViewController(context: Context) -> ShakableViewController 
        ShakableViewController()
    
    func updateUIViewController(_ uiViewController: ShakableViewController, context: Context) 


class ShakableViewController: UIViewController 

    override func motionBegan(_ motion: UIEvent.EventSubtype, with event: UIEvent?) 
        guard motion == .motionShake else  return 

         /* SHAKING GESTURE WAS DETECTED */
        myDevice?.isShaken = true       /* ContentView doesn't update! */
        makeShakerSound()       /* This works great */

        /* I’M TRYING TO TRIGGER A FUNCTION IN SWIFTUI BY SHAKING THE DEVICE:  Despite setting the myDevice.isShaken environment object to "true", my ContentView doesn't update when the shaking gesture is detected.   */

    



ContentView.swift

    @EnvironmentObject var myDevice: MyDevice

    var body: some View 
        NavigationView 

            ZStack 

                /* DETECT SHAKE GESTURE - This works */
                ShakableViewRepresentable()
                    .allowsHitTesting(false)

                VStack 
                    /* SHOW CURRENT STATE OF myDevice.isShaken - Doesn't update */
                    Text(self.myDevice.isShaken ? "The device has been shaken" : "No shaking has occurred")
                    Text("Device was shaken: \(self.myDevice.isShaken.description)")
                

/* more views below */

【问题讨论】:

【参考方案1】:

例子

import SwiftUI
import Combine

class MyDevice: ObservableObject 
    //let objectWillChange = ObservableObjectPublisher()
    var isShaken: Bool = false 
        willSet 
            self.objectWillChange.send()
        
    

struct ContentView: View 
    @ObservedObject var model = MyDevice()
    var body: some View 
        VStack 
            Text("\(model.isShaken.description)").onTapGesture 
                self.model.isShaken.toggle()
            

        
    

struct ContentView_Previews: PreviewProvider 
    static var previews: some View 
        ContentView()
    

取消注释

let objectWillChange = ObservableObjectPublisher()

它停止工作。

不要重新定义你自己的 ObservableObjectPublisher()

检查

import SwiftUI
import Combine

class MyDevice: ObservableObject 
    //let objectWillChange = ObservableObjectPublisher()
    var isShaken: Bool = false 
        willSet 
            self.objectWillChange.send()
        
    

struct ContentView: View 
    @EnvironmentObject var model: MyDevice
    var body: some View 
        VStack 
            Text("\(model.isShaken.description)").onTapGesture 
                self.model.isShaken.toggle()
            

        
    

struct ContentView_Previews: PreviewProvider 
    static var previews: some View 
        ContentView().environmentObject(MyDevice())
    

在 SceneDelegate.swift 中

func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) 
        // Use this method to optionally configure and attach the UIWindow `window` to the provided UIWindowScene `scene`.
        // If using a storyboard, the `window` property will automatically be initialized and attached to the scene.
        // This delegate does not imply the connecting scene or session are new (see `application:configurationForConnectingSceneSession` instead).

        // Create the SwiftUI view that provides the window contents.
        let contentView = ContentView().environmentObject(MyDevice())
        //let contentView = ContentView()

        // Use a UIHostingController as window root view controller.
        if let windowScene = scene as? UIWindowScene 
            let window = UIWindow(windowScene: windowScene)
            window.rootViewController = UIHostingController(rootView: contentView)
            self.window = window
            window.makeKeyAndVisible()
        
    

它按预期工作。

好的,使用震动检测器

myDevice?.isShaken = true

永远不会运行,因为 myDevice 是 nil

解决办法

使您的模型全局可用,因为在 SwiftUI 中我们没有工具如何使其可用于 ShakableViewController,或者将其用作其 init 的参数

SwiftDelegate.swift

import UIKit
import SwiftUI

let model = MyDevice()

class SceneDelegate: UIResponder, UIWindowSceneDelegate 

    var window: UIWindow?


    func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) 
        // Use this method to optionally configure and attach the UIWindow `window` to the provided UIWindowScene `scene`.
        // If using a storyboard, the `window` property will automatically be initialized and attached to the scene.
        // This delegate does not imply the connecting scene or session are new (see `application:configurationForConnectingSceneSession` instead).

        // Create the SwiftUI view that provides the window contents.
        let contentView = ContentView().environmentObject(model)
        //let contentView = ContentView()

        // Use a UIHostingController as window root view controller.
        if let windowScene = scene as? UIWindowScene 
            let window = UIWindow(windowScene: windowScene)
            window.rootViewController = UIHostingController(rootView: contentView)
            self.window = window
            window.makeKeyAndVisible()
        
    

    func sceneDidDisconnect(_ scene: UIScene) 
        // Called as the scene is being released by the system.
        // This occurs shortly after the scene enters the background, or when its session is discarded.
        // Release any resources associated with this scene that can be re-created the next time the scene connects.
        // The scene may re-connect later, as its session was not neccessarily discarded (see `application:didDiscardSceneSessions` instead).
    

    func sceneDidBecomeActive(_ scene: UIScene) 
        // Called when the scene has moved from an inactive state to an active state.
        // Use this method to restart any tasks that were paused (or not yet started) when the scene was inactive.
    

    func sceneWillResignActive(_ scene: UIScene) 
        // Called when the scene will move from an active state to an inactive state.
        // This may occur due to temporary interruptions (ex. an incoming phone call).
    

    func sceneWillEnterForeground(_ scene: UIScene) 
        // Called as the scene transitions from the background to the foreground.
        // Use this method to undo the changes made on entering the background.
    

    func sceneDidEnterBackground(_ scene: UIScene) 
        // Called as the scene transitions from the foreground to the background.
        // Use this method to save data, release shared resources, and store enough scene-specific state information
        // to restore the scene back to its current state.
    



ContentView.swift

import SwiftUI
import Combine

struct ShakableViewRepresentable: UIViewControllerRepresentable 

    class Coordinator: NSObject 
        var parent: ShakableViewRepresentable
        init(_ parent: ShakableViewRepresentable) 
            self.parent = parent
        
    

    func makeCoordinator() -> ShakableViewRepresentable.Coordinator 
        Coordinator(self)
    

    func makeUIViewController(context: Context) -> ShakableViewController 
        ShakableViewController()
    
    func updateUIViewController(_ uiViewController: ShakableViewController, context: Context) 


class ShakableViewController: UIViewController 
    override func motionBegan(_ motion: UIEvent.EventSubtype, with event: UIEvent?) 
        guard motion == .motionShake else  return 

        model.isShaken.toggle()
        print(model.isShaken)


    



class MyDevice: ObservableObject 
    //let objectWillChange = ObservableObjectPublisher()
    var isShaken: Bool = false 
        willSet 
            self.objectWillChange.send()
        
    

struct ContentView: View 
    @EnvironmentObject var model: MyDevice
    var body: some View 
        VStack 
            ShakableViewRepresentable()
                               .allowsHitTesting(false)
            Text(self.model.isShaken ? "The device has been shaken" : "No shaking has occurred").onTapGesture 
                self.model.isShaken.toggle()
            

        
    

struct ContentView_Previews: PreviewProvider 
    static var previews: some View 
        ContentView().environmentObject(MyDevice())
    

而且它可以工作,至少在我的设备上 :-)

没有声音,但会打印

true
false
true
false
true

每一次摇一摇的客串

【讨论】:

我注释掉了有问题的代码行。该应用程序编译并成功运行,但不幸的是结果相同 - 当 UIKit 中的摇动手势更新我的环境对象时,ContentView 仍未更新(mydevice?.isShaken = true)。 我也使用 EnvironmentObject 进行了检查...您是否将它暴露给您的 ContentView? 这可能就是我所缺少的。正如我所说,我有点新手,所以如果我错过了一些基本的东西,我很抱歉。在上面的 ContentView 摘录中,我包括“@EnvironmentObject var myDevice: MyDevice”,以及一些调用 self.myDevice 的文本视图。对 myDevice 的更改是在 ShakableViewController: UIViewController 类中进行的(因为 soundFX 代码有效,所以它被成功调用)。我还需要将它暴露给 ContentView 吗? 我更新了答案,看到这一行 let contentView = ContentView().environmentObject(MyDevice()) 别担心,更有经验的 SwiftUI 用户不知道它是如何工作的 :-) 一开始缺少(或非常不清楚)来自 Apple 的文档。

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