在 SwiftUI for macOS 应用程序中获取点击手势的鼠标/指针位置
Posted
技术标签:
【中文标题】在 SwiftUI for macOS 应用程序中获取点击手势的鼠标/指针位置【英文标题】:Get mouse/pointer position for tap gestures in SwiftUI for macOS apps 【发布时间】:2021-03-03 19:52:55 【问题描述】:由于 SwiftUI 中的DragGesture
,目前我们可以在拖动手势期间轻松跟踪视图内的指针位置,因为该手势公开了起始位置和相对于给定坐标空间的平移:
struct Example: View
@GestureState private var startPosition: CGPoint = .zero
@GestureState private var translation: CGSize = .zero
var body: some View
Rectangle()
.fill(Color.black)
.frame(width: 600, height: 400)
.coordinateSpace(name: "rectangle")
.overlay(coordinates)
.gesture(dragGesture)
var dragGesture: some Gesture
DragGesture(minimumDistance: 5, coordinateSpace: .named("rectangle"))
.updating($startPosition) (value, state, _) in
state = value.startLocation
.updating($translation) (value, state, _) in
state = value.translation
var coordinates: some View
Text("\(startPosition.x) \(startPosition.y) \(translation.width) \(translation.height)")
.foregroundColor(.white)
.font(Font.body.monospacedDigit())
相反,TapGesture
没有提供任何关于点击位置的信息,它只在点击发生时发出信号:
var tapGesture: some Gesture
TapGesture()
.onEnded _ in
print("A tap occurred")
有没有一种简单的方法可以在点击手势发生时获取指针位置?
我在网上找到了一些解决方案,但它们通常需要大量样板文件或不方便。
一些 UIKit 的包装器认为可以解决问题,知道吗?
【问题讨论】:
这可能会有用***.com/questions/56513942/… 您也可以通过拖动手势获取点击位置 【参考方案1】:编辑
我通过尝试同时使用手势找到了更好的解决方案。该解决方案与 SwiftUI 手势完美集成,并且与其他现有手势类似:
import SwiftUI
struct ClickGesture: Gesture
let count: Int
let coordinateSpace: CoordinateSpace
typealias Value = SimultaneousGesture<TapGesture, DragGesture>.Value
init(count: Int = 1, coordinateSpace: CoordinateSpace = .local)
precondition(count > 0, "Count must be greater than or equal to 1.")
self.count = count
self.coordinateSpace = coordinateSpace
var body: SimultaneousGesture<TapGesture, DragGesture>
SimultaneousGesture(
TapGesture(count: count),
DragGesture(minimumDistance: 0, coordinateSpace: coordinateSpace)
)
func onEnded(perform action: @escaping (CGPoint) -> Void) -> _EndedGesture<ClickGesture>
ClickGesture(count: count, coordinateSpace: coordinateSpace)
.onEnded (value: Value) -> Void in
guard value.first != nil else return
guard let location = value.second?.startLocation else return
guard let endLocation = value.second?.location else return
guard ((location.x-1)...(location.x+1)).contains(endLocation.x),
((location.y-1)...(location.y+1)).contains(endLocation.y) else
return
action(location)
extension View
func onClickGesture(
count: Int,
coordinateSpace: CoordinateSpace = .local,
perform action: @escaping (CGPoint) -> Void
) -> some View
gesture(ClickGesture(count: count, coordinateSpace: coordinateSpace)
.onEnded(perform: action)
)
func onClickGesture(
count: Int,
perform action: @escaping (CGPoint) -> Void
) -> some View
onClickGesture(count: count, coordinateSpace: .local, perform: action)
func onClickGesture(
perform action: @escaping (CGPoint) -> Void
) -> some View
onClickGesture(count: 1, coordinateSpace: .local, perform: action)
以前的解决方法
基于评论中链接的this SO question,我调整了适用于 macOS 的 UIKit 解决方案。
除了更改类型之外,我还添加了一个计算来计算 macOS 坐标系样式中的位置。仍然有一个丑陋的力量展开,但我不知道足够的 AppKit 来安全地删除它。
如果您想在一个视图上同时使用多个手势,则应在其他手势修饰符之前使用此修饰符。
目前CoordinateSpace
参数仅适用于.local
和.global
,但不适用于.named(Hashable)
。
如果您对其中一些问题有解决方案,我会更新答案。
代码如下:
public extension View
func onTapWithLocation(count: Int = 1, coordinateSpace: CoordinateSpace = .local, _ tapHandler: @escaping (CGPoint) -> Void) -> some View
modifier(TapLocationViewModifier(tapHandler: tapHandler, coordinateSpace: coordinateSpace, count: count))
fileprivate struct TapLocationViewModifier: ViewModifier
let tapHandler: (CGPoint) -> Void
let coordinateSpace: CoordinateSpace
let count: Int
func body(content: Content) -> some View
content.overlay(
TapLocationBackground(tapHandler: tapHandler, coordinateSpace: coordinateSpace, numberOfClicks: count)
)
fileprivate struct TapLocationBackground: NSViewRepresentable
let tapHandler: (CGPoint) -> Void
let coordinateSpace: CoordinateSpace
let numberOfClicks: Int
func makeNSView(context: NSViewRepresentableContext<TapLocationBackground>) -> NSView
let v = NSView(frame: .zero)
let gesture = NSClickGestureRecognizer(target: context.coordinator, action: #selector(Coordinator.tapped))
gesture.numberOfClicksRequired = numberOfClicks
v.addGestureRecognizer(gesture)
return v
final class Coordinator: NSObject
let tapHandler: (CGPoint) -> Void
let coordinateSpace: CoordinateSpace
init(handler: @escaping ((CGPoint) -> Void), coordinateSpace: CoordinateSpace)
self.tapHandler = handler
self.coordinateSpace = coordinateSpace
@objc func tapped(gesture: NSClickGestureRecognizer)
let height = gesture.view!.bounds.height
var point = coordinateSpace == .local
? gesture.location(in: gesture.view)
: gesture.location(in: nil)
point.y = height - point.y
tapHandler(point)
func makeCoordinator() -> TapLocationBackground.Coordinator
Coordinator(handler: tapHandler, coordinateSpace: coordinateSpace)
func updateNSView(_: NSView, context _: NSViewRepresentableContext<TapLocationBackground>)
【讨论】:
以上是关于在 SwiftUI for macOS 应用程序中获取点击手势的鼠标/指针位置的主要内容,如果未能解决你的问题,请参考以下文章
SwiftUI for MacOS 窗口,带圆角,不带标题栏
(SwiftUI, MacOS 11.0) 如何在 SecureTextFeild 中检测焦点?