SwiftUI 按作业层次排序列表

Posted 2023-02-24

【中文标题】SwiftUI 按作业层次排序列表

【英文标题】：SwiftUI sort list by job hierarchy

【发布时间】：2021-12-31 17:44:06

【问题描述】：

我正在尝试按作业层次结构对数组进行排序。

例如我有模型：

struct Employee

   let name: String
   let job: String
   let phone: String
   let mail: Sting

然后我有员工

class EmployeeViewModel: ObservableObject
    
    @Published var employees: [Employee] = [
        Employee(name: "John", job: "Manager", age: 32),
        Employee(name: "Anna", job: "CEO", age: 40),
        Employee(name: "Julia", job: "Junior Developer", age: 25),
        Employee(name: "Kevin", job: "Senior Developer", age: 29)
        
    ]  

我想将它们排序到这样的列表中：

CEO Anna
Manager John
Kevin Senior Developer
Julia Junior Developer

有什么简单的方法吗？

【参考方案1】：

您的 Employee 结构和您的 EmployeeViewModel.employees 不匹配，所以我更改了 Employee 以符合要求。为了使其可排序，Employee 必须符合Comparable 协议。由于您想要一个固定的工作订单，最简单的方法是使用enum 对它们进行排名。此外，Employee 应符合Identifiable 协议，以便在ForEach 中使用它们以用于显示目的。你可以作弊，但最终你需要顺从，所以从一开始就养成习惯。

struct SortByJob: View 
    @StateObject var employeeVM = EmployeeViewModel()
    
    var body: some View 
        List 
            ForEach(employeeVM.employees.sorted())  employee in
                HStack(spacing: 5) 
                    Text(employee.job.description)
                    Text(employee.name)
                
            
        
    


struct Employee: Identifiable, Comparable 
    
    let id = UUID()
    let name: String
    let job: Job
    let age: Int
    
    static func < (lhs: Employee, rhs: Employee) -> Bool 
        lhs.job.rawValue < rhs.job.rawValue
    


enum Job: Int 
    case ceo = 1
    case manager = 2
    case seniorDeveloper = 3
    case juniorDeveloper = 4
    
    // This allows you to return a String from the enum for display purposes.
    var description: String 
        switch self 
        case .ceo:
            return "CEO"
        case .manager:
            return "Manager"
        case .seniorDeveloper:
            return "Senior Developer"
        case .juniorDeveloper:
            return "Junior Developer"