在 Java、Android 上从 Youtube 下载视频的代码
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【中文标题】在 Java、Android 上从 Youtube 下载视频的代码【英文标题】：Code for download video from Youtube on Java, Android 【发布时间】：2011-11-04 09:45:48 【问题描述】：我创建了用于从 Youtube 下载视频的代码，但此代码不适用于 Wi-fi 连接和移动连接。我哪里错了？
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.Enumeration;
import java.util.Vector;
import android.app.Activity;
import android.app.ProgressDialog;
import android.net.Uri;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.widget.MediaController;
import android.widget.VideoView;
public class MyActivity extends Activity
private class ReceivingDataFromYoutube extends AsyncTask<String, Void, Void>
private ProgressDialog dialog = new ProgressDialog(MyActivity.this);
private String result;
protected void onPreExecute()
dialog.setMessage("Downloading...");
dialog.show();
@Override
protected Void doInBackground(String... arg0)
int begin, end;
String tmpstr = null;
try
URL url=new URL("http://www.youtube.com/watch?v=y12-1miZHLs&nomobile=1");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("GET");
InputStream stream=con.getInputStream();
InputStreamReader reader=new InputStreamReader(stream);
StringBuffer buffer=new StringBuffer();
char[] buf=new char[262144];
int chars_read;
while ((chars_read = reader.read(buf, 0, 262144)) != -1)
buffer.append(buf, 0, chars_read);
tmpstr=buffer.toString();
begin = tmpstr.indexOf("url_encoded_fmt_stream_map=");
end = tmpstr.indexOf("&", begin + 27);
if (end == -1)
end = tmpstr.indexOf("\"", begin + 27);
tmpstr = UtilClass.URLDecode(tmpstr.substring(begin + 27, end));
catch (MalformedURLException e)
throw new RuntimeException();
catch (IOException e)
throw new RuntimeException();
Vector url_encoded_fmt_stream_map = new Vector();
begin = 0;
end = tmpstr.indexOf(",");
while (end != -1)
url_encoded_fmt_stream_map.addElement(tmpstr.substring(begin, end));
begin = end + 1;
end = tmpstr.indexOf(",", begin);
url_encoded_fmt_stream_map.addElement(tmpstr.substring(begin, tmpstr.length()));
String result = "";
Enumeration url_encoded_fmt_stream_map_enum = url_encoded_fmt_stream_map.elements();
while (url_encoded_fmt_stream_map_enum.hasMoreElements())
tmpstr = (String)url_encoded_fmt_stream_map_enum.nextElement();
begin = tmpstr.indexOf("itag=");
if (begin != -1)
end = tmpstr.indexOf("&", begin + 5);
if (end == -1)
end = tmpstr.length();
int fmt = Integer.parseInt(tmpstr.substring(begin + 5, end));
if (fmt == 35)
begin = tmpstr.indexOf("url=");
if (begin != -1)
end = tmpstr.indexOf("&", begin + 4);
if (end == -1)
end = tmpstr.length();
result = UtilClass.URLDecode(tmpstr.substring(begin + 4, end));
this.result=result;
break;
try
URL u = new URL(result);
HttpURLConnection c = (HttpURLConnection) u.openConnection();
c.setRequestMethod("GET");
/* c.setRequestProperty("Youtubedl-no-compression", "True");
c.setRequestProperty("User-Agent", "YouTube");*/
c.setDoOutput(true);
c.connect();
FileOutputStream f=new FileOutputStream(new File("/sdcard/3.flv"));
InputStream in=c.getInputStream();
byte[] buffer=new byte[1024];
int sz = 0;
while ( (sz = in.read(buffer)) > 0 )
f.write(buffer,0, sz);
f.close();
catch (MalformedURLException e)
new RuntimeException();
catch (IOException e)
new RuntimeException();
return null;
protected void onPostExecute(Void unused)
dialog.dismiss();
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
new ReceivingDataFromYoutube().execute();
【问题讨论】：
您好，您能分享一下您是如何解决这个问题的吗？如何下载 youtube 视频？ @Денис Нагибин 嘿，你能告诉我它是如何工作的，因为我现在想知道它是如何工作的......我只是复制你的代码，但它在“UtilClass”上给出错误。 这个 UtilClass.URLDecode() 在你的函数中是什么，你能解释一下.. 我不明白 老兄，你写了 UtilClass。你愿意分享这门课吗？ 你能回答我的那个问题吗***.com/questions/26398325/… 【参考方案1】：三个步骤：
查看YouTube的源代码（html），你会得到这样的链接http%253A%252F%252Fo-o.preferred.telemar-cnf1.v18.lscache6.c.youtube.com%252Fvideoplayback ...
使用代码解码url（删除代码%2B、%25等）、create a decoder并使用函数Uri.decode(url)替换无效的转义八位字节
使用代码下载流：
URL u = null;
InputStream is = null;
try
u = new URL(url);
is = u.openStream();
HttpURLConnection huc = (HttpURLConnection)u.openConnection(); //to know the size of video
int size = huc.getContentLength();
if(huc != null)
String fileName = "FILE.mp4";
String storagePath = Environment.getExternalStorageDirectory().toString();
File f = new File(storagePath,fileName);
FileOutputStream fos = new FileOutputStream(f);
byte[] buffer = new byte[1024];
int len1 = 0;
if(is != null)
while ((len1 = is.read(buffer)) > 0)
fos.write(buffer,0, len1);
if(fos != null)
fos.close();
catch (MalformedURLException mue)
mue.printStackTrace();
catch (IOException ioe)
ioe.printStackTrace();
finally
try
if(is != null)
is.close();
catch (IOException ioe)
// just going to ignore this one
这就是您在网络上可以找到的大部分内容！！！
【讨论】：
真的为我工作@Денис Нагибин。我有一个私人应用程序，只能在我的手机上下载 youtube 视频。 此方法不再有效。你能看看它并更新它吗？ @SilvioGuedes 嘿，这是可行的，因为我很容易下载文件，但是当我要播放它时，会显示错误“您无法播放视频”。 @SilvioGuedes 嘿，谢谢你的回复，但我在我的应用程序中谈论的是不是其他应用程序。所以这不是完美的答案。 它只是下载一个 108 KB 的文件，无法播放。 huc.getContentLength();总是返回 -1。【参考方案2】：方法1 （推荐）
图书馆YouTubeExtractor
添加到你的 gradle 文件中
allprojects
repositories
maven url "https://jitpack.io"
和依赖关系
compile 'com.github.Commit451.YouTubeExtractor:youtubeextractor:2.1.0'
添加这个小代码，你就完成了。 Demo HERE
public class MainActivity extends AppCompatActivity
private static final String YOUTUBE_ID = "ea4-5mrpGfE";
private final YouTubeExtractor mExtractor = YouTubeExtractor.create();
private Callback<YouTubeExtractionResult> mExtractionCallback = new Callback<YouTubeExtractionResult>()
@Override
public void onResponse(Call<YouTubeExtractionResult> call, Response<YouTubeExtractionResult> response)
bindVideoResult(response.body());
@Override
public void onFailure(Call<YouTubeExtractionResult> call, Throwable t)
onError(t);
;
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// For android youtube extractor library com.github.Commit451.YouTubeExtractor:youtubeextractor:2.1.0'
mExtractor.extract(YOUTUBE_ID).enqueue(mExtractionCallback);
private void onError(Throwable t)
t.printStackTrace();
Toast.makeText(MainActivity.this, "It failed to extract. So sad", Toast.LENGTH_SHORT).show();
private void bindVideoResult(YouTubeExtractionResult result)
// Here you can get download url link
Log.d("OnSuccess", "Got a result with the best url: " + result.getBestAvailableQualityVideoUri());
Toast.makeText(this, "result : " + result.getSd360VideoUri(), Toast.LENGTH_SHORT).show();
您可以在bindVideoResult()方法中获取下载链接。
方法 2
使用这个库android-youtubeExtractor
添加到 gradle 文件中
repositories
maven url "https://jitpack.io"
compile 'com.github.HaarigerHarald:android-youtubeExtractor:master-SNAPSHOT'
这里是获取下载地址的代码。
String youtubeLink = "http://youtube.com/watch?v=xxxx";
YouTubeUriExtractor ytEx = new YouTubeUriExtractor(this)
@Override
public void onUrisAvailable(String videoId, String videoTitle, SparseArray<YtFile> ytFiles)
if (ytFiles != null)
int itag = 22;
// Here you can get download url
String downloadUrl = ytFiles.get(itag).getUrl();
;
ytEx.execute(youtubeLink);
【讨论】：
@试过1种方法？得到了结果.. 但是如何下载视频？ 如果您有下载链接，那么您可以像下载 pdf 图片等一样下载视频。即使您可以使用下载管理器，这也很简单。 这是超级且 100% 工作的代码。我现在可以从 youtube 下载任何视频。谢谢兄弟，你真的很棒 我很高兴听到这个消息 @ArpitPatel 真的，如果我遇到你兄弟，我会欠你一顿午餐。你能告诉我如何下载 DailyMotion 视频吗？请帮助我，我正在制作视频下载器，我想从任何网址下载任何视频【参考方案3】：参考：Youtube Video Download (Android/Java)
private static final HashMap<String, Meta> typeMap = new HashMap<String, Meta>();
initTypeMap();先打电话
class Meta
public String num;
public String type;
public String ext;
Meta(String num, String ext, String type)
this.num = num;
this.ext = ext;
this.type = type;
class Video
public String ext = "";
public String type = "";
public String url = "";
Video(String ext, String type, String url)
this.ext = ext;
this.type = type;
this.url = url;
public ArrayList<Video> getStreamingUrisFromYouTubePage(String ytUrl)
throws IOException
if (ytUrl == null)
return null;
// Remove any query params in query string after the watch?v=<vid> in
// e.g.
// http://www.youtube.com/watch?v=0RUPACpf8Vs&feature=youtube_gdata_player
int andIdx = ytUrl.indexOf('&');
if (andIdx >= 0)
ytUrl = ytUrl.substring(0, andIdx);
// Get the HTML response
/* String userAgent = "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:8.0.1)";*/
/* HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.USER_AGENT,
userAgent);
HttpGet request = new HttpGet(ytUrl);
HttpResponse response = client.execute(request);*/
String html = "";
HttpsURLConnection c = (HttpsURLConnection) new URL(ytUrl).openConnection();
c.setRequestMethod("GET");
c.setDoOutput(true);
c.connect();
InputStream in = c.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
str.append(line.replace("\\u0026", "&"));
in.close();
html = str.toString();
// Parse the HTML response and extract the streaming URIs
if (html.contains("verify-age-thumb"))
Log.e("Downloader", "YouTube is asking for age verification. We can't handle that sorry.");
return null;
if (html.contains("das_captcha"))
Log.e("Downloader", "Captcha found, please try with different IP address.");
return null;
Pattern p = Pattern.compile("stream_map\":\"(.*?)?\"");
// Pattern p = Pattern.compile("/stream_map=(.[^&]*?)\"/");
Matcher m = p.matcher(html);
List<String> matches = new ArrayList<String>();
while (m.find())
matches.add(m.group());
if (matches.size() != 1)
Log.e("Downloader", "Found zero or too many stream maps.");
return null;
String urls[] = matches.get(0).split(",");
HashMap<String, String> foundArray = new HashMap<String, String>();
for (String ppUrl : urls)
String url = URLDecoder.decode(ppUrl, "UTF-8");
Log.e("URL","URL : "+url);
Pattern p1 = Pattern.compile("itag=([0-9]+?)[&]");
Matcher m1 = p1.matcher(url);
String itag = null;
if (m1.find())
itag = m1.group(1);
Pattern p2 = Pattern.compile("signature=(.*?)[&]");
Matcher m2 = p2.matcher(url);
String sig = null;
if (m2.find())
sig = m2.group(1);
else
Pattern p23 = Pattern.compile("signature&s=(.*?)[&]");
Matcher m23 = p23.matcher(url);
if (m23.find())
sig = m23.group(1);
Pattern p3 = Pattern.compile("url=(.*?)[&]");
Matcher m3 = p3.matcher(ppUrl);
String um = null;
if (m3.find())
um = m3.group(1);
if (itag != null && sig != null && um != null)
Log.e("foundArray","Adding Value");
foundArray.put(itag, URLDecoder.decode(um, "UTF-8") + "&"
+ "signature=" + sig);
Log.e("foundArray","Size : "+foundArray.size());
if (foundArray.size() == 0)
Log.e("Downloader", "Couldn't find any URLs and corresponding signatures");
return null;
ArrayList<Video> videos = new ArrayList<Video>();
for (String format : typeMap.keySet())
Meta meta = typeMap.get(format);
if (foundArray.containsKey(format))
Video newVideo = new Video(meta.ext, meta.type,
foundArray.get(format));
videos.add(newVideo);
Log.d("Downloader", "YouTube Video streaming details: ext:" + newVideo.ext
+ ", type:" + newVideo.type + ", url:" + newVideo.url);
return videos;
private class YouTubePageStreamUriGetter extends AsyncTask<String, String, ArrayList<Video>>
ProgressDialog progressDialog;
@Override
protected void onPreExecute()
super.onPreExecute();
progressDialog = ProgressDialog.show(webViewActivity.this, "",
"Connecting to YouTube...", true);
@Override
protected ArrayList<Video> doInBackground(String... params)
ArrayList<Video> fVideos = new ArrayList<>();
String url = params[0];
try
ArrayList<Video> videos = getStreamingUrisFromYouTubePage(url);
/* Log.e("Downloader","Size of Video : "+videos.size());*/
if (videos != null && !videos.isEmpty())
for (Video video : videos)
Log.e("Downloader", "ext : " + video.ext);
if (video.ext.toLowerCase().contains("mp4") || video.ext.toLowerCase().contains("3gp") || video.ext.toLowerCase().contains("flv") || video.ext.toLowerCase().contains("webm"))
ext = video.ext.toLowerCase();
fVideos.add(new Video(video.ext,video.type,video.url));
return fVideos;
catch (Exception e)
e.printStackTrace();
Log.e("Downloader", "Couldn't get YouTube streaming URL", e);
Log.e("Downloader", "Couldn't get stream URI for " + url);
return null;
@Override
protected void onPostExecute(ArrayList<Video> streamingUrl)
super.onPostExecute(streamingUrl);
progressDialog.dismiss();
if (streamingUrl != null)
if (!streamingUrl.isEmpty())
//Log.e("Steaming Url", "Value : " + streamingUrl);
for (int i = 0; i < streamingUrl.size(); i++)
Video fX = streamingUrl.get(i);
Log.e("Founded Video", "URL : " + fX.url);
Log.e("Founded Video", "TYPE : " + fX.type);
Log.e("Founded Video", "EXT : " + fX.ext);
//new ProgressBack().execute(new String[]streamingUrl, filename + "." + ext);
public void initTypeMap()
typeMap.put("13", new Meta("13", "3GP", "Low Quality - 176x144"));
typeMap.put("17", new Meta("17", "3GP", "Medium Quality - 176x144"));
typeMap.put("36", new Meta("36", "3GP", "High Quality - 320x240"));
typeMap.put("5", new Meta("5", "FLV", "Low Quality - 400x226"));
typeMap.put("6", new Meta("6", "FLV", "Medium Quality - 640x360"));
typeMap.put("34", new Meta("34", "FLV", "Medium Quality - 640x360"));
typeMap.put("35", new Meta("35", "FLV", "High Quality - 854x480"));
typeMap.put("43", new Meta("43", "WEBM", "Low Quality - 640x360"));
typeMap.put("44", new Meta("44", "WEBM", "Medium Quality - 854x480"));
typeMap.put("45", new Meta("45", "WEBM", "High Quality - 1280x720"));
typeMap.put("18", new Meta("18", "MP4", "Medium Quality - 480x360"));
typeMap.put("22", new Meta("22", "MP4", "High Quality - 1280x720"));
typeMap.put("37", new Meta("37", "MP4", "High Quality - 1920x1080"));
typeMap.put("33", new Meta("38", "MP4", "High Quality - 4096x230"));
编辑 2：
此代码有时无法正常工作
同源政策
https://en.wikipedia.org/wiki/Same-origin_policy
https://en.wikipedia.org/wiki/Cross-origin_resource_sharing
problem of Same-origin policy. Essentially, you cannot download this file from www.youtube.com because they are different domains. A workaround of this problem is [CORS][1].
参考：https://superuser.com/questions/773719/how-do-all-of-these-save-video-from-youtube-services-work/773998#773998
url_encoded_fmt_stream_map // traditional: contains video and audio stream
adaptive_fmts // DASH: contains video or audio stream
每一个都是逗号分隔的数组，我称之为“流对象”。每个“流对象”都会包含这样的值
url // direct HTTP link to a video
itag // code specifying the quality
s // signature, security measure to counter downloading
每个 URL 都将被编码，因此您需要对其进行解码。现在是棘手的部分。
YouTube 的视频至少有 3 个安全级别
unsecured // as expected, you can download these with just the unencoded URL
s // see below
RTMPE // uses "rtmpe://" protocol, no known method for these
RTMPE 视频通常用于官方全长电影，并受 SWF 验证类型 2 保护。自 2011 年以来一直存在，尚未进行逆向工程。
“s”类型的视频是最难下载的。您通常会在 VEVO 视频等上看到这些内容。它们以签名开头，例如
AA5D05FA7771AD4868BA4C977C3DEAAC620DE020E.0F421820F42978A1F8EAFCDAC4EF507DB5 然后用这样的函数对签名进行加扰
function mo(a)
a = a.split("");
a = lo.rw(a, 1);
a = lo.rw(a, 32);
a = lo.IC(a, 1);
a = lo.wS(a, 77);
a = lo.IC(a, 3);
a = lo.wS(a, 77);
a = lo.IC(a, 3);
a = lo.wS(a, 44);
return a.join("")
这个函数是动态的，它通常每天都在变化。为了使其更加困难，该函数托管在诸如
之类的 URL 上http://s.ytimg.com/yts/jsbin/html5player-en_US-vflycBCEX.js
这就引入了同源策略的问题。本质上，您无法从 www.youtube.com 下载此文件，因为它们是不同的域。此问题的解决方法是 CORS。使用 CORS，s.ytimg.com 可以添加此标头
Access-Control-Allow-Origin: http://www.youtube.com
它允许从 www.youtube.com 下载 javascript。他们当然不这样做。此解决方法的一种解决方法是使用 CORS 代理。这是一个代理，它以以下标头响应所有请求
Access-Control-Allow-Origin: *
所以，既然您已经代理了您的 JS 文件，并使用该函数来打乱签名，您可以在查询字符串中使用它来下载视频。
【讨论】：
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