如何在 Django 中使用 .object 查询数据库
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【中文标题】如何在 Django 中使用 .object 查询数据库【英文标题】:How to Query DB using .object in Django 【发布时间】:2017-07-07 02:04:01 【问题描述】:我的类别很少。说电子产品和玩具。我在商场里有多家商店。商店使用外键(类别)保存。现在在导航栏中.. 我想根据他们的类别列出商店。感谢期待
models.py
class ShopCategories(models.Model):
category = models.CharField(max_length=50, unique=True,)
def __str__(self):
return self.category
class NewShop(models.Model):
category = models.ForeignKey(ShopCategories)
name = models.CharField(max_length=100, unique=True)
tagline = models.CharField(max_length=50, default='Enter tagline here2')
description = models.TextField(default='enter shop description')
def __str__(self):
return self.name
views.py
def basefile(request):
shop_cat = NewShop.objects.filter(category_id=1)
shop_name = NewShop.objects.filter(name=shop_cat)
return render_to_response('base.html', 'Shopname':shop_name, 'Shopcat':shop_cat)
base.html
% for category_id in Shopcat %
<li><a href="#"> Shopname </a></l>
% endfor %
【问题讨论】:
我们需要您详细说明您的需求。我的意思是,您是否需要一个根据类别选择显示商店列表的下拉菜单? @BrianOcampo .. 没错。取决于类别选择和类别下的商店列表的下拉列表 【参考方案1】:要获取所有商店,请使用以下查询。
shopcat = NewShop.objects.filter(category__category="category name")
base.html
% for shop in shopcat %
<li><a href="#"> shop.name </a></l>
% endfor %
【讨论】:
【参考方案2】:试试这个:
urls.py
urlpatterns = [
...
url(r'^get_shops_by_category/(?P<id_category>\d+)/$', views.get_shops_by_category, name = "get_shops_by_category"),
]
views.py
def basefile(request):
categories = ShopCategories.objects.all()
shop_name = NewShop.objects.filter(name=shop_cat)
return render_to_response('base.html', 'Shopname':shop_name, 'categories': categories)
def get_shops_by_category(request, **kwargs):
categories = ShopCategories.objects.all()
current_category = ShopCategories.objects.get(id = kwargs['id_category']
shops = NewShop.objects.filter(category = current_category)
return render_to_response('base.html', 'shops': shops, 'categories': categories, 'current_category' current_category)
base.html
...
<select>
% for category in categories %
% if current_category %
<option value=" category.id "> category.category </option>
% else %
<option value=" category.id " onclick="location.href = '% url 'your_app:your_url' category.id %'"> category.category </option>
% endfor %
</select>
% if shops %
<table>
<thead>
<tr>
<th>Shop name</th>
<th>Actions</th>
</tr>
</thead>
<tbody>
% for shop in shops %
<tr>
<td> shop.name </td>
<td><!-- Buttons or links, ect ... --></td>
</tr>
% endfor %
</tbody>
</table>
% endif %
...
【讨论】:
【参考方案3】:谢谢各位。我知道这不是最好的方法,但我能够以这种方式解决它
models.py
class ShopCategories(models.Model):
category = models.CharField(max_length=50, unique=True)
def __str__(self):
return self.category
class NewShop(models.Model):
category = models.ForeignKey(ShopCategories)
name = models.CharField(max_length=100, unique=True)
tagline = models.CharField(max_length=50, default='Enter tagline here2')
description = models.TextField(default='enter shop description')
def __str__(self):
return self.name
views.py
def basefile(request):
cat1 = NewShop.objects.filter(category_id=1)
cat2 = NewShop.objects.filter(category_id=2)
cat3 = NewShop.objects.filter(category_id=3)
cat4 = NewShop.objects.filter(category_id=4)
shop_name1 = ShopCategories.objects.filter(id=1)
shop_name2 = ShopCategories.objects.filter(id=2)
shop_name3 = ShopCategories.objects.filter(id=3)
shop_name4 = ShopCategories.objects.filter(id=4)
return render_to_response('base.html', 'Shop_cat1':cat1, 'Shop_cat2':cat2, 'Shop_cat3':cat3,
'Shop_cat4':cat4,'shop_name1':shop_name1, 'shop_name2':shop_name2,
'shop_name3':shop_name3, 'shop_name4':shop_name4)
base.html
% for shop_name1 in shop_name1 %
<li>
<h3> shop_name1 </h3>
</li>
% endfor %
% for Shop_cat1 in Shop_cat1 %
<li><a href="#"> Shop_cat1 </a></li>
% endfor %
【讨论】:
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