Django REST 框架:“BasePermissionMetaclass”对象不可迭代
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【中文标题】Django REST 框架:“BasePermissionMetaclass”对象不可迭代【英文标题】:Django REST Framework: 'BasePermissionMetaclass' object is not iterable 【发布时间】:2019-05-08 00:33:13 【问题描述】:Python/Django n00b 从 javascript 迁移过来。
尝试使用 Django REST 框架添加 API 端点,我希望最终能够使用 PATCH 请求的主体更新用户,但现在我只希望它不会引发 500 错误。
我已将此添加到 urlpatterns:
url(r'update/$', views.UpdateView.as_view(), name="update_user"),
这应该带来这种观点:
from django.contrib.auth.models import User
from rest_framework.generics import UpdateAPIView
from .serializers import UserSerializer
class UpdateView(UpdateAPIView):
queryset = User.objects.all()
serializer_class = UserSerializer
UserSerializer 如下所示:
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = ('username', 'pk', 'status')
似乎每次我访问该路线时都会得到这个:
TypeError at /api/update/
'BasePermissionMetaclass' object is not iterable
我不知道自己在做什么 - 以前有人见过吗?
更新:完整追溯:
Internal Server Error: /api/update/
Traceback (most recent call last):
File "path/to/myapp/env/lib/python2.7/site-packages/django/core/handlers/exception.py", line 41, in inner
response = get_response(request)
File "path/to/myapp/env/lib/python2.7/site-packages/django/core/handlers/base.py", line 187, in _get_response
response = self.process_exception_by_middleware(e, request)
File "path/to/myapp/env/lib/python2.7/site-packages/django/core/handlers/base.py", line 185, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "path/to/myapp/env/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 58, in wrapped_view
return view_func(*args, **kwargs)
File "path/to/myapp/env/lib/python2.7/site-packages/django/views/generic/base.py", line 68, in view
return self.dispatch(request, *args, **kwargs)
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 495, in dispatch
response = self.handle_exception(exc)
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 455, in handle_exception
self.raise_uncaught_exception(exc)
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 483, in dispatch
self.initial(request, *args, **kwargs)
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 401, in initial
self.check_permissions(request)
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 333, in check_permissions
for permission in self.get_permissions():
File "path/to/myapp/env/lib/python2.7/site-packages/rest_framework/views.py", line 280, in get_permissions
return [permission() for permission in self.permission_classes]
TypeError: 'BasePermissionMetaclass' object is not iterable
【问题讨论】:
显示完整的回溯。 很可能,您定义了一个权限(为班级或通过设置)并且没有将其添加为列表 显示来自设置模块的PERMISSION_CLASSES
配置。
@SachinKukreja - 你是说这个吗? ~~~~ REST_FRAMEWORK = 'DEFAULT_AUTHENTICATION_CLASSES': ( 'rest_framework.authentication.TokenAuthentication', ), 'DEFAULT_PERMISSION_CLASSES': ( 'rest_framework.permissions.IsAdminUser' ), ~~~~
【参考方案1】:
您在DEFAULT_PERMISSION_CLASSES
值中输入了错误的逗号,因此 Django 将其视为字符串,而不是元组。
解决方案:
REST_FRAMEWORK =
...
'DEFAULT_PERMISSION_CLASSES': ( 'rest_framework.permissions.IsAdminUser', ),
...
【讨论】:
哇——就是这样!非常感谢 - 已经坚持了几天了 - 如此简单的解决方案! 惊人的答案!谢谢!【参考方案2】:我遇到了同样的问题,但是找错了地方。我制作了具有权限的mixin类并且有代码
permission_classes = (
permissions.IsAuthenticated
)
但应该是
permission_classes = (
permissions.IsAuthenticated,
# ^
# a comma here
)
所以不要忘记寻找其他具有权限的类。我希望它会对某人有所帮助。
【讨论】:
对于任何想知道更改是什么的人,您必须在权限后添加一个逗号。IsAuthenticated..我花了几分钟才弄清楚:) idk 为什么我花了 15 分钟才意识到这条评论甚至存在......【参考方案3】:作为可能在这里搜索的其他人的参考,这也可能是一个问题..
from django.contrib.auth.models import User
from rest_framework.generics import UpdateAPIView
from .serializers import UserSerializer
class UpdateView(UpdateAPIView):
queryset = User.objects.all()
serializer_class = UserSerializer
permission_classes = IsAuthenticated
应该改为:
from django.contrib.auth.models import User
from rest_framework.generics import UpdateAPIView
from .serializers import UserSerializer
class UpdateView(UpdateAPIView):
queryset = User.objects.all()
serializer_class = UserSerializer
permission_classes = [IsAuthenticated]
【讨论】:
【参考方案4】:Junst 万一this 也可以解决。至少解决了我的问题
【讨论】:
【参考方案5】:只是为了完成@ihafurr 的回答。
permission_classes
应该是可迭代的,因为该变量是由 :func:viewsets.ModelViewSet.get_permission
调用的 (https://www.cdrf.co/3.12/rest_framework.viewsets/ModelViewSet.html):
def get_permissions(self):
return [permission() for permission in self.permission_classes]
将此类方法的最后一行更改为以下内容可以克服可迭代性要求。
return [permission() for permission in self.permission_classes] if isinstance(self.permission_classes], Iterable) else [self.permission_classes]
Iterable
来自哪里
try:
from collections.abc import Iterable # for Python >= 3.6
except ImportError:
from collections import Iterable
【讨论】:
【参考方案6】:@permission_classes((AllowAny,))
您必须确保 逗号
【讨论】:
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