Retrofit-IllegalArgumentException：意外的 url

Posted 2023-02-24

【中文标题】Retrofit-IllegalArgumentException：意外的 url

【英文标题】：Retrofit-IllegalArgumentException: unexpected url

【发布时间】：2016-02-13 23:42:39

【问题描述】：

我想使用 Retrofit 将视频文件（从图库中选择）上传到服务器。但它不起作用并抛出异常“java.lang.IllegalArgumentException: unexpected url: 192.168.1.7”。我的代码如下所示。PostFile.java：

public final class PostFile 
    public static final MediaType MEDIA_TYPE_MARKDOWN
      = MediaType.parse("vide/mp4");

    private final OkHttpClient client = new OkHttpClient();

    public void run(String path) throws Exception 
        File file = new File(path);

        Request request = new Request.Builder()
            .url("192.168.1.7/")
            .post(RequestBody.create(MEDIA_TYPE_MARKDOWN, file))
            .build();

        Response response = client.newCall(request).execute();
        if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);

        System.out.println(response.body().string());
    

PostFile：

public class MainActivity extends Activity 
    private static int RESULT_LOAD_IMG = 1;
    String decodableString;

    @Override
    protected void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    

    public void loadImagefromGallery(View view) 
        // Create intent to Open Image applications like Gallery, Google Photos
        Intent galleryIntent = new Intent(Intent.ACTION_PICK,
                android.provider.MediaStore.Video.Media.EXTERNAL_CONTENT_URI);
        // Start the Intent
        startActivityForResult(galleryIntent, RESULT_LOAD_IMG);
    

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) 
        super.onActivityResult(requestCode, resultCode, data);
        try 
            // When an Image is picked
            if (requestCode == RESULT_LOAD_IMG && resultCode == RESULT_OK
                    && null != data) 
                // Get the Image from data

                Uri selectedVideo = data.getData();

                String[] filePathColumn =  MediaStore.Video.Media.DATA ;
                // Get the cursor
                Cursor cursor = getContentResolver().query(selectedVideo,
                        filePathColumn, null, null, null);
                // Move to first row
                cursor.moveToFirst();

                int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
                decodableString = cursor.getString(columnIndex);
                cursor.close();
                new PostFile().run(decodableString);
                Log.i("mohsen","done");
             else 
                Toast.makeText(this, "You haven't picked any video",
                        Toast.LENGTH_LONG).show();
            
         catch (Exception e) 
            e.printStackTrace();
            Toast.makeText(this, "Something went wrong", Toast.LENGTH_LONG)
                    .show();
        
    

Wampserver 正在我的计算机上运行 Apache Server 2.4.4。 请注意，我不知道这段代码是否正确，我只是试图让它几乎盲目地工作。

【参考方案1】：

将您的网址修改为http://192.168.1.7。它应该可以完美运行。

【讨论】：

感谢您回答我的问题，但我只是赞成您的回答并接受另一个答案，只是为了提前几秒钟给出答案。再次感谢您。

【参考方案2】：

尝试改变

    .url("192.168.1.7/")

到

    .url("http://192.168.1.7")