使用 agsxmpp 库从 xml 节点获取信息

Posted 2023-02-23

【中文标题】使用 agsxmpp 库从 xml 节点获取信息

【英文标题】：get information from xml node using agsxmpp library

【发布时间】：2016-11-25 09:57:05

【问题描述】：

<query xmlns="urn:xmpp:dialogueHistory">
<dialogueHistory id="4d38f289-9">
<MessageID>26164</MessageID>
<messageText>Fhh</messageText>
<msgDate>11/25/2016 6:30:39 AM</msgDate>
<unReadCount>0</unReadCount>
</dialogueHistory>
</query>

获取messageid,messagetext的信息

如何使用 agsxmpp 库从上述 xml 中获取信息

命名空间是agsXMPP.Xml.Dom

【参考方案1】：

您需要指定命名空间。使用 xml linq

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1

    class Program
    
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        
            XDocument doc = XDocument.Load(FILENAME);

            List<XElement> dialogueHistory = doc.Descendants().Where(x => x.Name.LocalName == "dialogueHistory").ToList();
            XNamespace ns = dialogueHistory.FirstOrDefault().GetDefaultNamespace();

            var results = dialogueHistory.Select(x => new 
                id = (string)x.Attribute("id"),
                messageId = (int)x.Element(ns + "MessageID"),
                messageText = (string)x.Element(ns + "messageText"),
                messageDate = (DateTime)x.Element(ns + "msgDate"),
                unReadCount = (int)x.Element(ns + "unReadCount")
            ).ToList();