从边界计算区域
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【中文标题】从边界计算区域【英文标题】:Calculate region from bounds 【发布时间】:2017-04-17 17:11:44 【问题描述】:我需要将(谷歌地图)边界对象转换为区域对象。
样本边界:
northeast:
lat: 47.5085913,
lng: 19.2656781
,
southwest:
lat: 47.4179006,
lng: 19.0494985
示例区域:
// centre of bounds
latitude,
longitude,
// delta of the centre in order to fit the original bounds
latitudeDelta,
longitudeDelta,
到目前为止我所取得的成就:
const bounds2region = bounds =>
const earthRadiusInKM = 6371 // km
const radiusInKM = 1
const aspectRatio = 1
const [ latitude, longitude ] = bounds2center(bounds)
const radiusInRad = radiusInKM / earthRadiusInKM
const longitudeDelta = rad2deg(radiusInRad / Math.cos(deg2rad(latitude)))
const latitudeDelta = aspectRatio * rad2deg(radiusInRad)
return
latitude,
longitude,
latitudeDelta,
longitudeDelta,
const bounds2center = bounds =>
toArrayIfObject(bounds)
.reduce((coordinate1, coordinate2) =>
const c1 = toArrayIfObject(coordinate1)
const c2 = toArrayIfObject(coordinate2)
return [
average([c1[0], c2[0]]),
average([c1[1], c2[1]]),
]
)
const average = numbers => numbers.reduce((sum, n) => sum + n, 0) / numbers.length
const deg2rad = n => n * Math.PI / 180
const rad2deg = n => n / Math.PI * 180
const toArrayIfObject = object => typeof object === 'object' ? Object.values(object) : object
它部分工作:它将地图移动到边界的中心,但裁剪或缩小太多。我不确定如何设置增量(latitudeDelta
、longitudeDelta
)。我想我需要为aspectRatio
计算一个值,而不是将其设置为1
。
【问题讨论】:
【参考方案1】:好的,经过更多的冲浪后,我设法修补了一个解决方案:
const earthRadiusInMetre = 6371e3
const boundsToRegion = (bounds, aspectRatio = 1, margin = 1) =>
const [ latitude, longitude ] = boundsToCenter(bounds)
const R = (calculateDistance(bounds[0], latitude, longitude )) * margin
return
latitude,
longitude,
...calculateRegionDelta( latitude , R, aspectRatio),
const calculateRegionDelta = ( latitude , radiusInMetre, aspectRatio = 1) =>
const radiusInRad = radiusInMetre / earthRadiusInMetre
const longitudeDelta = rad2deg(radiusInRad / Math.cos(deg2rad(latitude)))
const latitudeDelta = aspectRatio * rad2deg(radiusInRad)
return
latitudeDelta,
longitudeDelta,
const boundsToCenter = bounds =>
bounds.reduce((coordinate1, coordinate2) => [
average([coordinate1.latitude, coordinate2.latitude]),
average([coordinate1.longitude, coordinate2.longitude]),
])
const calculateDistance = (coord1, coord2) =>
const R = earthRadiusInMetre
const lat1 = coord1.latitude
const lat2 = coord2.latitude
const lon1 = coord1.longitude
const lon2 = coord2.longitude
const φ1 = deg2rad(lat1)
const φ2 = deg2rad(lat2)
const Δφ = deg2rad(lat2 - lat1)
const Δλ = deg2rad(lon2 - lon1)
const a = Math.sin(Δφ / 2) * Math.sin(Δφ / 2) + Math.cos(φ1) * Math.cos(φ2) * Math.sin(Δλ / 2) * Math.sin(Δλ / 2)
const c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a))
return R * c
const deg2rad = n => n * Math.PI / 180
const rad2deg = n => n / Math.PI * 180
const average = numbers => numbers.reduce((sum, n) => sum + n, 0) / numbers.length
函数boundsToRegion
接受一个包含2 个坐标的数组作为bounds
、一个aspect ratio
和一个margin
参数。
例子:
const bounds = Object.values(boundsObject).map(coordinate => (
latitude: coordinate.lat,
longitude: coordinate.lng,
))
const region = boundsToRegion(bounds, aspectRatio, 2)
资源:set-the-bounds-of-a-mapview
【讨论】:
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