在javascript中使用Postcode Anywhere的地址查找器，需要将密钥放在PHP中

Posted 2023-02-23

【中文标题】在javascript中使用Postcode Anywhere的地址查找器，需要将密钥放在PHP中

【英文标题】：Address finder using Postcode Anywhere in javascript, need to put the key in PHP

【发布时间】：2014-02-28 10:23:52

【问题描述】：

我目前正在执行从邮政编码到结帐的地址查找。

我已经让它与我的结帐一起使用，但目前它都是纯 javascript，我真的不能这样做，因为这意味着我的 Postcode Anywhere 密钥也在显示中。

很明显，我需要在服务器端做这件事的一部分（在我的例子中是 php）。但我不太确定这一切有多少以及如何联系起来。我在这里围绕PCA_Find_By_Parts.html JavaScript 示例构建了我当前的解决方案：

http://www.postcodeanywhere.co.uk/support/sample-code.aspx

但对我来说，这似乎不是很安全，正如我提到的那样，钥匙正在展示中。

【参考方案1】：

您将希望在后端 (PHP) 上进行所有“处理”，并使用 Ajax 函数传递相关数据。

这里有一个很好的例子：

https://www.postcodeanywhere.co.uk/address-validation/guide/default.aspx?reg=1

网站上有 PHP 示例：

http://downloads.postcodeanywhere.co.uk/dev/pcaphpsamples.zip
http://downloads.postcodeanywhere.co.uk/dev/pcaphpsamples.zip
http://downloads.postcodeanywhere.co.uk/dev/phpSOAP.zip

您还可以使用以下代码开始：

class PostcodeAnywhere_Interactive_FindByPostcode_v1_00


   //Credit: Thanks to Stuart Sillitoe (http://stu.so/me) for the original PHP that these samples are based on.

   private $Key; //The key to use to authenticate to the service.
   private $Postcode; //The postcode to search with find.
   private $UserName; //The username associated with the Royal Mail license (not required for click licenses).
   private $Data; //Holds the results of the query

   function PostcodeAnywhere_Interactive_FindByPostcode_v1_00($Key, $Postcode, $UserName)
   
      $this->Key = $Key;
      $this->Postcode = $Postcode;
      $this->UserName = $UserName;
   

   function MakeRequest()
   
      $url = "http://services.postcodeanywhere.co.uk/PostcodeAnywhere/Interactive/FindByPostcode/v1.00/xmla.ws?";
      $url .= "&Key=" . urlencode($this->Key);
      $url .= "&Postcode=" . urlencode($this->Postcode);
      $url .= "&UserName=" . urlencode($this->UserName);

      //Make the request to Postcode Anywhere and parse the XML returned
      $file = simplexml_load_file($url);

      //Check for an error, if there is one then throw an exception
      if ($file->Columns->Column->attributes()->Name == "Error") 
      
         throw new Exception("[ID] " . $file->Rows->Row->attributes()->Error . " [DESCRIPTION] " . $file->Rows->Row->attributes()->Description . " [CAUSE] " . $file->Rows->Row->attributes()->Cause . " [RESOLUTION] " . $file->Rows->Row->attributes()->Resolution);
      

      //Copy the data
      if ( !empty($file->Rows) )
      
         foreach ($file->Rows->Row as $item)
         
             $this->Data[] = array('Id'=>$item->attributes()->Id,'StreetAddress'=>$item->attributes()->StreetAddress,'Place'=>$item->attributes()->Place);
         
      
   

   function HasData()
   
      if ( !empty($this->Data) )
      
         return $this->Data;
      
      return false;
   



//Example usage
//-------------
//$pa = new PostcodeAnywhere_Interactive_FindByPostcode_v1_00 ("AA11-AA11-AA11-AA11","WR2 6NJ","David");
//$pa->MakeRequest();
//if ($pa->HasData())
//
//   $data = $pa->HasData();
//   foreach ($data as $item)
//   
//      echo $item["Id"] . "<br/>";
//      echo $item["StreetAddress"] . "<br/>";
//      echo $item["Place"] . "<br/>";
//   
//


http://www.postcodeanywhere.co.uk/support/webservices/PostcodeAnywhere/Interactive/FindByPostcode/v1/default.aspx

在需要时使用 ajax 进行调用：

jQuery.ajax(
    url: "yourScript.php",
    type: 'POST',  
    data: action: 'get_postcode', id: ui.item.id ,
    success: function(data) 
        try 
            var response = jQuery.parseJSON(data);
            jQuery('#pickPostcode').val(response.postcode);
         catch(err) 
    
);

【讨论】：

嗨，是的，我已经厌倦了这些，但它们似乎都围绕着做一个我不能做的表单请求，因为邮政编码查找是在一个表单中，你不应该有一个表单一个表格内。我希望有一个 ajax 类型的解决方案，但我不知道该怎么做？

@David：这是 AJAX 解决方案。如果您不想使用它，它不需要使用表单。

Opps 抱歉没有看到 jquery 位，谢谢尝试一下！