如何从C#中的地址获取纬度和经度

Posted 2023-02-23

【中文标题】如何从C#中的地址获取纬度和经度

【英文标题】：how to get latitude and longitude from address in C#

【发布时间】：2011-09-28 10:49:12

【问题描述】：

我想根据地址获取经纬度。我已经对其进行了设置，因此它可以捕获将其显示为曼彻斯特的用户位置。

我想写一个 if 语句…………；

if there is an address 

// set lat/long from address

这里是完整的编码；

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using GeoCoding.Google;
using GeoCoding;
using System.Web.Configuration;

namespace MVCFacebookTestApp.Models


    public class Home
    
        //public string UserID  get; set; 
        public string FBID  get; set; 
        public string AccessToken  get; set; 
        public string FName  get; set; 
        public string LName  get; set; 
        public string Gender  get; set; 
        public DateTime? DOB  get; set; 
        public string Email  get; set; 
        public DateTime DateLiked  get; set; 
        public string ImageURL  get; set; 
        //public string TestString  get; set; 
        //public string TestString2  get; set; 
        public bool IsLiked  get; set; 
        //public string ImgUrl  get; set; 

        private Home() 
            //Console.WriteLine(GoogleAPIKey);
        

        public static Home NotLiked()
        
            Home h = new Home();
            h.IsLiked = false;
            return h;
        

        public static Home Liked()
        
            Home h = new Home();
            h.IsLiked = true;
            return h;
        

        public void AddUser(string facebookID, string accessToken, string fName, string lName, DateTime dob, string email, DateTime dateLiked, string gender, string imageURL, string locationID, string locationValue)
        

            Entities context = new Entities();
            //DBNameDataContext myDB = new DBNameDataContext();

            IEnumerable<User> users = context.Users.Where(u => u.FacebookID == facebookID);


            if (users.Count() == 0)
            
                //UserID = userID;
                FBID = facebookID;
                AccessToken = accessToken;
                FName = fName;
                LName = lName;
                DOB = dob;
                Email = email;
                DateLiked = dateLiked;
                Gender = gender;
                ImageURL = imageURL;


                User newUser = new User();

                //newUser.UserID = 1;
                newUser.FacebookID = facebookID;
                newUser.AccessToken = accessToken;
                newUser.FName = fName;
                newUser.LName = lName;
                newUser.Gender = gender;
                newUser.DOB = DOB;
                newUser.Email = email;
                newUser.DateLiked = dateLiked;
                newUser.ImageURL = imageURL;

                context.Users.AddObject(newUser);
                context.SaveChanges();
            
            else if (users.Count() == 1)
            
                User user0 = users.First();

                if (user0.Gender != gender)
                
                    user0.Gender = gender;
                

                if (user0.FName != fName)
                
                    user0.FName = fName;
                

                if (user0.LName != lName)
                
                    user0.LName = lName;
                

                if (user0.DOB != dob)
                
                    user0.DOB = dob;
                

                if (user0.Email != email)
                
                    user0.Email = email;
                

                if (user0.DateLiked != dateLiked)
                
                    user0.DateLiked = dateLiked;
                

                if (user0.ImageURL != imageURL)
                
                    user0.ImageURL = imageURL;
                

                context.SaveChanges();

                FBID = user0.FacebookID;
                AccessToken = user0.AccessToken;
                FName = user0.FName;
                LName = user0.LName;
                DOB = user0.DOB;
                Email = user0.Email;
                DateLiked = user0.DateLiked;
                Gender = user0.Gender;
                ImageURL = user0.ImageURL;
            
            else
            
                throw new ApplicationException();
            

            //LOCATION...

            //LocationID = locationID;
            //FBID = facebookID;
            //Latitude = latitude;
            //Langitude = langitude;
            //Description = description;

            //IEnumerable<User> users = context.Users.Where(u => u.FacebookID == facebookID);

            IEnumerable<Location> locations = context.Locations.Where(l => l.FacebookID == facebookID);


            
                Location newLocation = new Location();

                newLocation.FacebookID = locationID;
                newLocation.Latitude = "";
                newLocation.Langitude = "";
                newLocation.Description = locationValue;
                IGeoCoder geoCoder = new GoogleGeoCoder(GoogleAPIKey);
                Address[] addresses = geoCoder.GeoCode(locationValue);


                context.Locations.AddObject(newLocation);
                context.SaveChanges();
            

            if (Address= true)
            
                langtitude = ;;
            
        

        public string GoogleAPIKey
            

            get
            
                return WebConfigurationManager.AppSettings["GoogleAPIKey"];
            

        

    

【参考方案1】：

你的问题不是很清楚，但我想你想要这样的东西：

IGeoCoder geoCoder = new GoogleGeoCoder(GoogleAPIKey);
Address[] addresses = geoCoder.GeoCode(locationValue);

// I believe the API never returns a null reference...
if (addresses.Length != 0)

    // Let's assume the first one is good enough
    Address address = addresses[0];
    Location location = address.Location;
    // Use location.Latitude and location.Longitude

请注意，为了可测试性，最好注入 IGeoCoder 而不是在您的类中创建它。

【讨论】：

它现在可以工作，但由于某种原因，它在调试时不断将相同的数据添加到数据库中。我怎么能阻止这个？我觉得这条线可能有问题； IEnumerable 位置 = context.Locations.Where(l => l.FacebookID == facebookID);

@PrinceJavaliciouz：老实说，这听起来像是一个完全不同的问题——而且应该在另一个问题中问，最好只 i> 相关的代码位。 （我花了一段时间才在您的问题中找到相关代码 - 请阅读tinyurl.com/so-hints.）

对不起，您之前在查找代码时遇到了问题，我将其全部发布，以防其他人可能需要全部参考。我问了一个新问题。感谢您的链接。会读一读。

@PrinceJavaliciouz：不，“以防万一”发布大量代码并不是一个好方法。找出相关的代码，然后发布所有这些。理想情况下，将其作为一个简短但完整的程序发布 - 并非总是可行，但如果可以的话，那就太好了。