Firebase 云功能无法正确记录
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【中文标题】Firebase 云功能无法正确记录【英文标题】:Firebase cloud function doesn't log correctly 【发布时间】:2020-11-19 04:08:01 【问题描述】:我在每两分钟运行一次的 firebase 函数上运行 pubsub 计划函数。 我尝试记录快照循环收集的事件,但有些事情不正常。
exports.check_event_ended_notification = functions.pubsub.schedule('every 2 minutes').onRun((context) =>
let default_lineup = "default";
let events = [];
return admin.database().ref("Events").once('value')
.then(snapshot =>
console.log(("EVENTS number : " + snapshot.numChildren()));
snapshot.forEach(event_snapshot =>
let event_key = event_snapshot.key;
let event = event_snapshot.val();
events.push(event_key);
console.log("EVENT_UID : " + event_key);
console.log(("EVENTS : " + events));
// iterate through all events and check if they're marked as ended
// if not, check if ended
let event_status = event[['ended_status']];
if (event_status === '0')
// get event date
let event_day = event[['date']]['0'];
let event_month = event[['date']]['1'];
let event_year = event[['date']]['2'];
let event_full_date = event_year + "-" + event_month + "-" + event_day;
// get today date
let today = new Date();
let today_day = today.getDate();
let today_month = (today.getMonth() + 1);
let today_year = today.getFullYear();
let today_full_date = today_year + "-" + today_month + "-" + today_day;
//create date objects to compare
let event_date = new Date(event_full_date);
let today_date = new Date(today_full_date);
// if event date is in the past
// check to see if its marked as ended.
if (event_date.getTime() < today_date.getTime())
console.log("EVENT : past event : " + event_key);
if (event[['ended_status']] === "0")
console.log("EVENT : ended 0 : " + event_key);
//mark as ended
// admin.database().ref("Events/"+event_key+"/ended_status").set("1");
//create notifications for participation artists
for (let artist_key in event[['lineup']])
console.log("ARTIST before: " + artist_key);
if (artist_key !== default_lineup)
console.log("ARTIST after: " + artist_key);
let approved_invitation = event[['lineup']][artist_key]['approved_invitation'];
let handshake_status = event[['lineup']][artist_key]['handshake_status'];
let quit = event[['lineup']][artist_key]['quit'];
let removed = event[['lineup']][artist_key]['removed'];
let event_publish_status = event[['publish_status']];
let owner_uid = event[['owner_uid']];
if (approved_invitation === '1' && handshake_status === '1' && quit === '0' && removed === '0' && event_publish_status === '1')
return admin.database().ref("Notifications/" + artist_key + "/" + owner_uid + "/" + event['uid']).push(
notification_type: "ended",
seen_status: "0",
timestamp: new Date().getTime()
)
return null;
)
)
虽然开头的 numChildren() 日志显示快照下有 4 个孩子(这是正确的),但 foreach() 方法似乎只运行了两次,收集前两个孩子并将它们添加到“事件”列表。
在此之后日志停止:
2020-07-29T14:22:00.593Z ? check_event_ended_notification: EVENTS number : 4
2020-07-29T14:22:00.593Z ? check_event_ended_notification: EVENT_UID : 3853c2db-f31a-4f46-8c1b-740ca4e3407b
2020-07-29T14:22:00.593Z ? check_event_ended_notification: EVENTS : 3853c2db-f31a-4f46-8c1b-740ca4e3407b
2020-07-29T14:22:00.594Z ? check_event_ended_notification: EVENT_UID : 4253c2db-f31a-4f46-8c1b-740ca4e3407s
2020-07-29T14:22:00.594Z ? check_event_ended_notification: EVENTS : 3853c2db-f31a-4f46-8c1b-740ca4e3407b,4253c2db-f31a-4f46-8c1b-740ca4e3407s
【问题讨论】:
【参考方案1】:您没有正确管理 Cloud Function 的生命周期。正如doc 中所述,您需要“通过返回 JavaScript 承诺来解析执行异步处理的函数(也称为“后台函数”)。
另外,在一个云函数中,不推荐使用on()
方法,它设置了一个监听器,而是once()
一个,它“只监听一个指定事件类型的事件,然后停止听。”。
所以以下应该可以解决问题:
exports.check_event_ended_notification = functions.pubsub.schedule('every 2 minutes').onRun((context) =>
let default_lineup = "default";
let events = [];
return admin.database().ref("Events").once('value') // Note the return here
.then(snapshot =>
snapshot.forEach(event_snapshot =>
let event_key = event_snapshot.key;
let event = event_snapshot.val();
events.push(event_key)
console.log("EVENT_UID : " + event_key);
console.log(("EVENTS : " + events));
);
// Do something with events... We don't have enough details
return null; // Or return a promise
);
);
根据您的评论更新
如果你想在forEach()
中写入数据库(这是一个异步过程),你应该使用Promise.all()
,以便在所有并行调用异步push()
时返回一个promise方法完成。
这里是代码的框架,你应该适应所有的细节:
exports.check_event_ended_notification = functions.pubsub.schedule('every 2 minutes').onRun((context) =>
let default_lineup = "default";
let events = [];
return admin.database().ref("Events/").once('value')
.then(snapshot =>
const promises = [];
snapShot.forEach(event_snapshot =>
let event_key = event_snapshot.key;
let event = event_snapshot.val();
events.push(event_key)
console.log("EVENT_UID : " + event_key);
console.log(("EVENTS : " + events));
promises.push(
admin.database().ref("Notifications/" + artist_key + "/" + owner_uid + "/" + event['uid']).push(
notification_type: "ended",
seen_status: "0",
timestamp: new Date().getTime()
)
);
);
return Promise.all(promises); // This returns a promise!!
);
);
【讨论】:
最后的'return null'是否应该出现在forEach循环的末尾或之后? 我使用了return null;
,因为我不知道你真正想用events
数组做什么。如果在forEach()
之后调用异步方法(例如将events
数组写入另一个数据库节点),则需要返回此方法返回的承诺。为了更准确地了解正确管理 Cloud Function 生命周期的重要性,我建议您观看 Firebase 视频系列中有关“javascript Promises”的 3 个视频:firebase.google.com/docs/functions/video-series
感谢您的推荐,这是我的第一个 js 项目,所以我可能应该学习更多。此外,我使用包含您的建议的完整代码编辑了帖子。
我已经用代码框架更新了答案,您应该适应所有细节。另外,看看我在之前评论中提到的最后一个视频,它涵盖了Promise.all()
的使用
是的,我看到了视频,我解决了。非常感谢大家的帮助。以上是关于Firebase 云功能无法正确记录的主要内容,如果未能解决你的问题,请参考以下文章
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