如何记住登录 Google 帐户 Android
Posted
技术标签:
【中文标题】如何记住登录 Google 帐户 Android【英文标题】：How to Remember Sign In in Google Account Android 【发布时间】：2016-03-27 08:02:40 【问题描述】：登录活动 请帮助我只是想在后台记住登录应用程序，以便当他重新打开应用程序时自动打开下一个活动而不是登录活动。
package xxx.xxxxx.xxxxxx;
/**
* Created by Yoyo on 12/21/2015.
*/
import android.app.ProgressDialog;
import android.content.Intent;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.view.Menu;
import android.view.MenuItem;
import android.widget.ImageView;
import android.widget.TextView;
import android.widget.Toast;
import com.google.android.gms.auth.api.Auth;
import com.google.android.gms.auth.api.signin.GoogleSignInAccount;
import com.google.android.gms.auth.api.signin.GoogleSignInOptions;
import com.google.android.gms.auth.api.signin.GoogleSignInResult;
import com.google.android.gms.common.ConnectionResult;
import com.google.android.gms.common.SignInButton;
import com.google.android.gms.common.api.GoogleApiClient;
import com.google.android.gms.common.api.GoogleApiClient.ConnectionCallbacks;
import com.google.android.gms.common.api.GoogleApiClient.OnConnectionFailedListener;
import com.google.android.gms.common.api.ResultCallback;
import com.google.android.gms.common.api.Status;
public class Login extends AppCompatActivity implements OnConnectionFailedListener, View.OnClickListener, ConnectionCallbacks
GoogleApiClient mGoogleApiClient;
GoogleSignInOptions gso;
SignInButton signIn_btn;
private static final int RC_SIGN_IN = 0;
ProgressDialog progress_dialog;
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
buidNewGoogleApiClient();
setContentView(R.layout.login);
customizeSignBtn();
setBtnClickListeners();
progress_dialog = new ProgressDialog(this);
progress_dialog.setMessage("Signing in....");
/*
Configure sign-in to request the user's ID, email address, and basic profile.
User's ID and basic profile are included in DEFAULT_SIGN_IN.
create and initialize GoogleApiClient object to use Google Sign-In API and the options specified by gso..
*/
private void buidNewGoogleApiClient()
gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestEmail()
.build();
mGoogleApiClient = new GoogleApiClient.Builder(this)
.enableAutoManage(this, this )
.addApi(Auth.GOOGLE_SIGN_IN_API, gso)
.build();
/*
Customize sign-in button. The sign-in button can be displayed in
multiple sizes and color schemes. It can also be contextually
rendered based on the requested scopes. For example. a red button may
be displayed when Google+ scopes are requested, but a white button
may be displayed when only basic profile is requested. Try adding the
Plus.SCOPE_PLUS_LOGIN scope to see the difference.
*/
private void customizeSignBtn()
signIn_btn = (SignInButton) findViewById(R.id.sign_in_button);
signIn_btn.setSize(SignInButton.SIZE_STANDARD);
signIn_btn.setScopes(gso.getScopeArray());
/*
Set on click Listeners on the sign-in sign-out and disconnect buttons
*/
private void setBtnClickListeners()
// Button listeners
signIn_btn.setOnClickListener(this);
findViewById(R.id.sign_out_button).setOnClickListener(this);
findViewById(R.id.disconnect_button).setOnClickListener(this);
protected void onStart()
super.onStart();
mGoogleApiClient.connect();
protected void onStop()
super.onStop();
if (mGoogleApiClient.isConnected())
mGoogleApiClient.disconnect();
@Override
public boolean onCreateOptionsMenu(Menu menu)
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
@Override
public boolean onOptionsItemSelected(MenuItem item)
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings)
return true;
return super.onOptionsItemSelected(item);
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data)
super.onActivityResult(requestCode, resultCode, data);
// Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
if (requestCode == RC_SIGN_IN)
if (resultCode != RESULT_OK)
progress_dialog.dismiss();
GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
getSignInResult(result);
@Override
public void onClick(View v)
switch (v.getId())
case R.id.sign_in_button:
Toast.makeText(this, "start sign process", Toast.LENGTH_SHORT).show();
gSignIn();
break;
case R.id.sign_out_button:
Toast.makeText(this, "Google Sign Out", Toast.LENGTH_SHORT).show();
gSignOut();
break;
case R.id.disconnect_button:
Toast.makeText(this, "Google Access Revoked", Toast.LENGTH_SHORT).show();
gRevokeAccess();
break;
private void gSignIn()
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
startActivityForResult(signInIntent, RC_SIGN_IN);
progress_dialog.show();
private void gSignOut()
Auth.GoogleSignInApi.signOut(mGoogleApiClient).setResultCallback(
new ResultCallback<Status>()
@Override
public void onResult(Status status)
updateUI(false);
);
private void gRevokeAccess()
Auth.GoogleSignInApi.revokeAccess(mGoogleApiClient).setResultCallback(
new ResultCallback<Status>()
@Override
public void onResult(Status status)
updateUI(false);
);
private void getSignInResult(GoogleSignInResult result)
if (result.isSuccess())
// Signed in successfully, show authenticated UI.
GoogleSignInAccount acct = result.getSignInAccount();
TextView user_name= (TextView)findViewById(R.id.userName);
TextView email_id= (TextView)findViewById(R.id.emailId);
user_name.setText("UserName: "+ acct.getDisplayName());
email_id.setText("Email Id: " + acct.getEmail());
updateUI(true);
SharedPreferences sharedPreferences = getSharedPreferences("APP", MODE_PRIVATE);
SharedPreferences.Editor editor = sharedPreferences.edit();
editor.putBoolean("isLogin", true);
editor.putString("name", //Name),
editor.putString("e_mail",
editor.putString("ID", //ID);
editor.commit());
progress_dialog.dismiss();
else
// Signed out, show unauthenticated UI.
updateUI(false);
private void updateUI(boolean signedIn)
if (signedIn)
findViewById(R.id.sign_in_button).setVisibility(View.GONE);
findViewById(R.id.sign_out_and_disconnect).setVisibility(View.VISIBLE);
else
findViewById(R.id.sign_in_button).setVisibility(View.VISIBLE);
findViewById(R.id.sign_out_and_disconnect).setVisibility(View.GONE);
@Override
public void onConnected(Bundle bundle)
@Override
public void onConnectionSuspended(int i)
@Override
public void onConnectionFailed(ConnectionResult connectionResult)
Activity 的登录 xml 文件登录 xml
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_
android:layout_
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
app:layout_behavior="@string/appbar_scrolling_view_behavior"
tools:context="num.app.xxx.xxxx.xxxx.Login"
tools:showIn="@layout/Login">
<com.google.android.gms.common.SignInButton
android:id="@+id/sign_in_button"
android:layout_
android:layout_ />
<LinearLayout
android:id="@+id/sign_out_and_disconnect"
android:layout_
android:layout_
android:orientation="vertical"
android:visibility="gone"
tools:visibility="visible"
android:layout_centerHorizontal="true"
android:layout_alignParentTop="true"
android:layout_alignParentBottom="true">
<TextView
android:id="@+id/userName"
android:layout_
android:layout_
android:text=" user name:"
android:layout_marginTop="15dp"
android:layout_marginLeft="10dp"
android:textColor="@android:color/black"
android:textSize="14sp"
/>
<TextView
android:id="@+id/emailId"
android:layout_
android:layout_
android:text="email id:"
android:textColor="@android:color/black"
android:layout_below="@+id/userName"
android:layout_marginTop="15dp"
android:layout_marginLeft="10dp"
android:textSize="14sp"
/>
<Button
android:id="@+id/sign_out_button"
android:layout_
android:layout_
android:layout_gravity="center_vertical"
android:text="Google Sign out"/>
<Button
android:id="@+id/disconnect_button"
android:layout_
android:layout_
android:layout_gravity="center_vertical"
android:text="revoke Google Access"/>
</LinearLayout>
</RelativeLayout>
//在上述活动之前启动活动
Thread timer = new Thread()
public void run()
try
sleep(1000);
catch(InterruptedException e)
e.printStackTrace();
finally
Intent openStartingPoint = new Intent("android.intent.action.Login");
startActivity(openStartingPoint);
finish();
;
timer.start();
【问题讨论】：
获取到的信息，可以保存在SharedPreference，避免再次登录。并且如果用户注销了应用，可以清除SharedPreference的数据。
@NigamPatro 你能在编码中做一些修改来告诉我该怎么做吗？
您的应用程序中有启动画面吗？
@NigamPatro 是的，最初的活动是启动登录活动的启动画面
那么，你看不懂哪一部分？
【参考方案1】：
我会避免将令牌保存在共享首选项中，而是尝试按照此处所述执行静默登录：http://android-developers.blogspot.de/2015/12/api-updates-for-sign-in-with-google.html
这样做的好处是可以让您验证用户是否仍然登录，并最终让您提示他请求重新登录。
这里有一些代码（基本上改编自链接中的示例）：
public void silentLogin()
OptionalPendingResult<GoogleSignInResult> pendingResult = Auth.GoogleSignInApi.silentSignIn(googleApiClient);
if (pendingResult != null)
handleGooglePendingResult(pendingResult);
else
//no result from silent login. Possibly display the login page again
private void handleGooglePendingResult(OptionalPendingResult<GoogleSignInResult> pendingResult)
if (pendingResult.isDone())
// There's immediate result available.
GoogleSignInResult signInResult = pendingResult.get();
onSilentSignInCompleted(signInResult);
else
// There's no immediate result ready, waits for the async callback.
pendingResult.setResultCallback(new ResultCallback<GoogleSignInResult>()
@Override
public void onResult(@NonNull GoogleSignInResult signInResult)
onSilentSignInCompleted(signInResult, callback);
);
private void onSilentSignInCompleted(GoogleSignInResult signInResult)
GoogleSignInAccount signInAccount = signInResult.getSignInAccount();
if (signInAccount != null)
// you have a valid sign in account. Skip the login.
else
// you don't have a valid sign in account. Eventually display the login page again
【讨论】：
【参考方案2】：你可以试试这个：
用户登录成功后，您可以通过调用 GoogleSignInAccount 的 getIdToken() 方法将 id 令牌保存到 SharedPreferences。当用户重新打开时，您可以检查 id 令牌是否正在退出，然后忽略登录屏幕。
private void getSignInResult(GoogleSignInResult result)
if (result.isSuccess())
// Signed in successfully, show authenticated UI.
GoogleSignInAccount acct = result.getSignInAccount();
String id_token = acct.getIdToken(); //add this code here to save it by use SharedPreferences
TextView user_name= (TextView)findViewById(R.id.userName);
TextView email_id= (TextView)findViewById(R.id.emailId);
user_name.setText("UserName: "+ acct.getDisplayName());
email_id.setText("Email Id: " + acct.getEmail());
updateUI(true);
progress_dialog.dismiss();
else
// Signed out, show unauthenticated UI.
updateUI(false);
//save user login state id_token
private void saveLoginState(String id_token)
SharedPreferences sharedpreferences = getSharedPreferences("YOUR_PREFERENCE_NAME", Context.MODE_PRIVATE);
SharedPreferences.Editor editor = sharedpreferences.edit();
editor.putString("GG_LOGED", id_token);
editor.commit();
【讨论】：
让我试试这个，然后我会回复你。 我想在登录时，然后下次打开应用程序时，它不会要求再次登录，而是显示下一个活动页面以显示其名称。你能帮我做吗？ @RajKaran 你试试这个代码保存到 SharedPreferences： @RajKaran 刚刚更新了我上面的代码，所以你可以再试一次 查看我何时登录并获取所有详细信息，但是当我从内存中清除应用程序并再次启动应用程序时，它再次显示登录页面，我不想再次看到使用谷歌登录但我从登录中获得的所有详细信息。就像当你登录谷歌帐户并关闭它并清除内存时，你可以看到新闻提要而不是登录过程。【参考方案3】：用户登录后，您可以使用此代码将数据存储在SharedPreference中
SharedPreferences sharedPreferences = getSharedPreferences("APP", MODE_PRIVATE);
SharedPreferences.Editor editor = sharedPreferences.edit();
editor.putBoolean("isLogin", true);
editor.putString("name", //Name);
editor.putString("e_mail",//Email);
editor.putString("ID", //ID);
editor.commit();
在启动画面中你可以这样做
boolean isLoggedIn = sharedPreferences.getBoolean("isLogin", false);
这里isLoggedIn是用户是否登录状态的值。您需要在 SplashScreen 中处理此问题并按此操作。
【讨论】：
我已经对其进行了编辑并添加了启动登录活动的启动活动代码，现在我很困惑将上面的代码放在哪里 我已经放了 boolean isLoggedIn = sharedPreferences.getBoolean("isLogin", false);" in finally but Where to put below code SharedPreferences sharedPreferences = getSharedPreferences("APP", MODE_PRIVATE); SharedPreferences.Editor editor = sharedPreferences.edit(); editor.putBoolean("isLogin", true); editor.putString("name", //Name); editor.putString( "e_mail",//Email); editor.putString("ID", //ID); editor.commit(); 在方法getSignInResult里面if条件。
editor.commit()的分号有问题； //显示错误 ')' 预期我已经放了括号但仍然错误
@RajKaran 将此代码 editor.putString("e_mail", editor.putString("ID", //ID); editor.putString("ID", //ID); 修改为 editor.putString("name", acct.getDisplayName()); editor.putString("e_mail", acct.getEmail()); editor.putString("ID", acct.getIdToken()); editor.commit();以上是关于如何记住登录 Google 帐户 Android的主要内容，如果未能解决你的问题，请参考以下文章
Flutter Authentication 从登录屏幕到登录屏幕使用 Google 登录和注销
如何在使用 Google 登录按钮时不将 Google 帐户添加到 Android 手机