在 Python 中按值转换和格式化字典列表

Posted 2023-02-15

【中文标题】在 Python 中按值转换和格式化字典列表

【英文标题】：convert and format list of dictionaries in Pyton by values

【发布时间】：2022-01-04 02:25:58

【问题描述】：

希望有人能帮我查字典：

    data = [
  
    "firstname" : "David",
    "lastname"  : "Brown",
    "class"       : [ "economy" ]
  ,
  
    "firstname" : "Alina",
    "lastname"  : "Hoper",
    "class"       : [ "economy", "business" ]
  ,
  
    "firstname" : "Bill",
    "lastname"  : "Flow",
    "class"       : [ "business" ]
  ,
  
    "firstname" : "James",
    "lastname"  : "Frank",
    "class"       : [ "economy" ]
  
]

作为输出，我需要看看谁买了经济舱，谁买了商务舱： 排序=按类升序，在类内部按名字升序。所以先做生意，再做经济。而阿丽娜在这两门课上都名列前茅，因为她买了这两门课。

business: Alina Hoper, Bill Flow, ...
economy: Alina Hoper, David Brown, ...

我尝试编写函数，但现在不明白从哪里开始排序以及如何按类转换字典和分组数据：

def analyze(customers_data):
    data = ""
    data += "  \n".format(customers_data["firstname"], customers_data["lastname"])
    data += " \n".format(customers_data["aff"])
    return data

for d in orders:
    print(analyze(d))

希望有人能帮忙

【参考方案1】：

您应该首先获取经济/商业客户的列表，然后打印这些列表中的名称：

data = [
  
    "firstname" : "David",
    "lastname"  : "Brown",
    "class"       : [ "economy" ]
  ,
  
    "firstname" : "Alina",
    "lastname"  : "Hoper",
    "class"       : [ "economy", "business" ]
  ,
  
    "firstname" : "Bill",
    "lastname"  : "Flow",
    "class"       : [ "business" ]
  ,
  
    "firstname" : "James",
    "lastname"  : "Frank",
    "class"       : [ "economy" ]
  
]

business_custom = [dic for dic in data if "business" in dic["class"]]
eco_custom = [dic for dic in data if "economy" in dic["class"]]

business_names = ', '.join(sorted([f"dic['firstname'] dic['lastname']" for dic in business_custom]))
economy_names = ', '.join(sorted([f"dic['firstname'] dic['lastname']" for dic in eco_custom]))

print(f"business: business_names")
print(f"economy: economy_names")

输出：

business : Alina Hoper, Bill Flow
economy : Alina Hoper, David Brown, James Frank

编辑：如果你事先不知道类名，你可以创建一组类：

class_set = set()
for dic in data:
    for c in dic['class']:
        class_set.add(c)

for c in sorted(list(class_set)):
    custom = [dic for dic in data if c in dic["class"]]
    names = ', '.join(sorted([f"dic['firstname'] dic['lastname']" for dic in custom]))
    print(f"c: names")

【讨论】：

非常感谢。它有助于。我还尝试打开按 lastanme 排序，它有效，但认为它不正确：names = ', '.join(sorted([f"dic['firstname'] dic['lastname']" for dic in custom], key=lambda x: x[6])) >>> 它显示了我想要的方式，但如果我做对了，它会按第 6 个值（字母）排序。可能你有一个提示如何输入单词而不是字母。我试过 ['lastname'] 但它显示：字符串索引必须是整数

您可以通过定义custom = [dic for dic in sorted(data, key=lambda x:x['lastname']) if c in dic["class"]]直接按姓氏对客户进行排序（删除names中的排序以避免列表随后按名字排序）