Postgres 列不存在

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【中文标题】Postgres 列不存在【英文标题】:Postgres column does not exist 【发布时间】:2014-11-07 00:29:33 【问题描述】:

其他人编写了一个有效的 SQL Server 查询,我负责将其移植到 Postgres。

除了非常基本的 SQL 命令之外,我真的不了解这两个数据库(我正在学习本教程并将继续学习,但我希望尽快解决这个问题)。

无论如何,我得到了第 4 行中的错误,

错误:timeloggedtoday.date_logged 列不存在

认为来自第 89 行附近的部分(标有 **),但我无法弄清楚语法应该是什么——我尝试复制 WITH/AS文档中的部分,但要么我仍然犯错,要么错误在其他地方。下面可能有很多重复/无关的代码,但我认为最好将它们全部包含在内,因为当我更改为 Postgres 语法时,很容易引入其他错误。

编辑:

如果我删除了有问题的部分,错误将变为

错误:timelogged1daysago.date_logged 列不存在

这是下一批类似的代码,让我相信我在命名临时表时犯了一些语法错误(正确的术语?)但我看不出有什么问题,而且很难找到相关部分在文档中...谷歌搜索“With”或“As”毫无帮助。

SELECT users.author,
       users.display_name,
       timeloggedToday.date_logged "DATE_LOGGED_TODAY",
       timeloggedToday.time_in_hours "TIME_IN_HOURS_TODAY",
       timeloggedToday.difference_days "DIFFERENCE_DAYS_TODAY",
       CASE
           WHEN Ifnull(timeloggedToday.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timeloggedToday.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_TODAY",
       timelogged1daysago.date_logged "DATE_LOGGED_1DAYSAGO",
       timelogged1daysago.time_in_hours "TIME_IN_HOURS_1DAYSAGO",
       timelogged1daysago.difference_days "DIFFERENCE_DAYS_1DAYSAGO",
       CASE
           WHEN Ifnull(timelogged1daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged1daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_1DAYSAGO",
       timelogged2daysago.date_logged "DATE_LOGGED_2DAYSAGO",
       timelogged2daysago.time_in_hours "TIME_IN_HOURS_2DAYSAGO",
       timelogged2daysago.difference_days "DIFFERENCE_DAYS_2DAYSAGO",
       CASE
           WHEN Ifnull(timelogged2daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged2daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_2DAYSAGO",
       timelogged3daysago.date_logged "DATE_LOGGED_3DAYSAGO",
       timelogged3daysago.time_in_hours "TIME_IN_HOURS_3DAYSAGO",
       timelogged3daysago.difference_days "DIFFERENCE_DAYS_3DAYSAGO",
       CASE
           WHEN Ifnull(timelogged3daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged3daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_3DAYSAGO",
       timelogged4daysago.date_logged "DATE_LOGGED_4DAYSAGO",
       timelogged4daysago.time_in_hours "TIME_IN_HOURS_4DAYSAGO",
       timelogged4daysago.difference_days "DIFFERENCE_DAYS_4DAYSAGO",
       CASE
           WHEN Ifnull(timelogged4daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged4daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_4DAYSAGO",
       timelogged5daysago.date_logged "DATE_LOGGED_5DAYSAGO",
       timelogged5daysago.time_in_hours "TIME_IN_HOURS_5DAYSAGO",
       timelogged5daysago.difference_days "DIFFERENCE_DAYS_5DAYSAGO",
       CASE
           WHEN Ifnull(timelogged5daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged5daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_5DAYSAGO",
       timelogged6daysago.date_logged "DATE_LOGGED_6DAYSAGO",
       timelogged6daysago.time_in_hours "TIME_IN_HOURS_6DAYSAGO",
       timelogged6daysago.difference_days "DIFFERENCE_DAYS_6DAYSAGO",
       CASE
           WHEN Ifnull(timelogged6daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged6daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_6DAYSAGO",
       timelogged7daysago.date_logged "DATE_LOGGED_7DAYSAGO",
       timelogged7daysago.time_in_hours "TIME_IN_HOURS_7DAYSAGO",
       timelogged7daysago.difference_days "DIFFERENCE_DAYS_7DAYSAGO",
       CASE
           WHEN Ifnull(timelogged7daysago.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timelogged7daysago.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_7DAYSAGO",
       lastReportedTime.last_time_logged
FROM
  (SELECT lower_child_name AS "author",
          cwd_user.display_name
   FROM cwd_membership
   LEFT JOIN cwd_user ON (cwd_membership.lower_child_name = cwd_user.user_name
                          AND cwd_user.directory_id = cwd_membership.directory_id)
   WHERE lower_parent_name = 'jira-developers'
     AND cwd_membership.directory_id = 10100) users
**LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '0 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timeloggedToday ON timeloggedToday.lower_user_name = users.author**
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-1 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged1daysago ON timelogged1daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-2 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged2daysago ON timelogged2daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-3 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged3daysago ON timelogged3daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-4 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged4daysago ON timelogged4daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-5 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged5daysago ON timelogged5daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-6 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged6daysago ON timelogged6daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '-7 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timelogged7daysago ON timelogged7daysago.lower_user_name = users.author
LEFT JOIN
  (SELECT app_user.lower_user_name,
          Max(startdate) AS "last_time_logged"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   GROUP BY app_user.lower_user_name) lastReportedTime ON lastReportedTime.lower_user_name = users.author

编辑:更简单的查询

我想我已经编辑掉了一些无关的东西,希望能找到这个错误。无论如何,这个较短的查询至少给了我同样的错误,所以也许这更容易帮助我调试:

SELECT users.author,
       users.display_name,
       timeloggedToday.date_logged "DATE_LOGGED_TODAY",
       timeloggedToday.time_in_hours "TIME_IN_HOURS_TODAY",
       timeloggedToday.difference_days "DIFFERENCE_DAYS_TODAY",
       CASE
           WHEN Ifnull(timeloggedToday.time_in_hours, 0) = 0 THEN 'No Time Logged'
           WHEN timeloggedToday.time_in_hours < 3.0 THEN 'User has not logged sufficient time'
           ELSE 'user has logged sufficient time'
       END "STATUS_TODAY",
       lastReportedTime.last_time_logged
FROM
  (SELECT lower_child_name AS "author",
          cwd_user.display_name
   FROM cwd_membership
   LEFT JOIN cwd_user ON (cwd_membership.lower_child_name = cwd_user.user_name
                          AND cwd_user.directory_id = cwd_membership.directory_id)
   WHERE lower_parent_name = 'jira-developers'
     AND cwd_membership.directory_id = 10100) users
LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
     AND startdate - Now() = INTERVAL '0 days'
   GROUP BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now()),
            worklog.startdate
   ORDER BY app_user.lower_user_name,
            to_char(startdate, '%Y-%m-%d'),
            Date(Now())) timeloggedToday ON timeloggedToday.lower_user_name = users.author

LEFT JOIN
  (SELECT app_user.lower_user_name,
          Max(startdate) AS "last_time_logged"
   FROM worklog
   LEFT JOIN app_user ON worklog.author = app_user.user_key
   GROUP BY app_user.lower_user_name) lastReportedTime ON lastReportedTime.lower_user_name = users.author

【问题讨论】:

显示\d timeloggedtoday的输出 多么可怕的查询。我相信它可以做得比这更令人愉快。带有一些示例数据的sqlfiddle.com 将非常有帮助。 是的,不是我写的。好吓人。不过,这是非常重复的,所以它并不像看起来那么糟糕。 @AlexDvoretsky,对不起,我对这一切都很陌生,不明白你在问什么。 @thumbtackthief 他要求您连接psql 命令行客户端并运行\d timeloggedtoday 以显示表定义。当然,既然没有这样的表不工作;您需要 \d worklog\d app_user 来显示基础表。 命令行客户端不适合我。我会继续努力让它发挥作用。 【参考方案1】:

编辑: 引用的大写正在破坏查询。在下面第二次失败的输出中,您可以看到 Postgres 不喜欢大写字母。除非你强制使用 " 引号,否则它习惯于将所有内容都小写。

--fails
select a
from
(select 1 as "A") as t;

--fails
select A
from
(select 1 as "A") as t;

--works
select "A"
from
(select 1 as "A") as t;

psql:new.sql:5: ERROR:  column "a" does not exist
LINE 1: select a
               ^
psql:new.sql:10: ERROR:  column "a" does not exist
LINE 1: select A
               ^
 A 
───
 1
(1 row)


select ...
timeloggedToday.date_logged "DATE_LOGGED_TODAY",
-- should be: timeloggedToday."DATE_LOGGED" "DATE_LOGGED_TODAY",

...

LEFT JOIN
  (SELECT app_user.lower_user_name,
          to_char(startdate, '%Y-%m-%d') AS "DATE_LOGGED",
          Sum(timeworked) / 3600 "TIME_IN_HOURS",
          startdate - Now() "DIFFERENCE_DAYS"
   ...
  ) timeloggedToday ON timeloggedToday.lower_user_name = users.author;

我会考虑去掉大写和引号。只会让人头疼。作为旁注,您可以通过以下方式编写一次左连接:

-- instead of enumerating each possible interval  
WHERE to_char(Now() - INTERVAL '8 days', '%Y-%m-%d') < to_char(startdate, '%Y-%m-%d')
-- select the interval
now()::date - start_date as diff
-- then build up your columns like:
case(case when diff=0 then date_logged else null end) as date_logged_today
case(case when diff=1 then date_logged else null end) as date_logged_yesterday
-- and so on ...

你也可以做

CASE
   WHEN Ifnull(timeloggedToday.time_in_hours, 0) = 0 THEN 'No Time Logged'
   WHEN timeloggedToday.time_in_hours < 3.0 THEN 'User has not logged sufficient time' 
   ELSE 'user has logged sufficient time'
 END "STATUS_TODAY",

变成一个函数来摆脱繁琐的冗余。

【讨论】:

我很可能误解了这一点,但我认为问题在于没有正确创建 timeloggedToday 的别名。 (timelogged1daysago 也会触发相同的错误,其他类似的别名也会触发相同的错误,但它首先会触发 timeloggedToday,我几乎可以肯定它们将是相同的语法错误原因) 是的,你是对的。当我第一次看到它时,我以为您在查询显示的内容。 嘿,它有效!好吧,我还是收到了一条新的错误消息。抱怨第 8 行中的 Ifnull。不过,我要给你赏金——非常感谢! 在文档中查找 coalesce()

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