如何将 JSON 解码为不同的类型?
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【中文标题】如何将 JSON 解码为不同的类型?【英文标题】:How to decode JSON Into different types? 【发布时间】:2022-01-07 13:13:58 【问题描述】:我有这个本地 JSON 文件,其中包含标题、开始和结束。我想从开始键和结束键创建日期,但标题是字符串,所以我可以创建事件对象。现在我已经将所有内容解码为字符串。所以我试图创建一个自定义初始化,但一个错误不断出现“从初始化程序返回而不初始化所有存储的属性”。不知道我做错了什么
这是我的事件模型和我的 JSONFile
struct Event: Decodable & Equatable
let title : String
let start : Date
let end : Date
//Custom decoding init
init(from decoder : Decoder) throws
let container = try decoder.singleValueContainer()
let stringType = try container.decode(String.self)
switch stringType
case "title":
self.title = try container.decode(String.self)
case "start":
self.start = try container.decode(Date.self)
case "end":
self.end = try container.decode(Date.self)
default:
throw DecodingError.dataCorruptedError(in: container, debugDescription: "Not valid date \(stringType)")
JSON
["title": "Evening Picnic", "start": "November 10, 2018 6:00 PM", "end": "November 10, 2018 7:00 PM", "title": "Nap Break", "start": "November 8, 2018 12:30 PM", "end": "November 8, 2018 1:30 PM", "title": "Football Game", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM", "title": "Evening Cookout with Friends", "start": "November 6, 2018 5:00 PM", "end": "November 6, 2018 10:00 PM", "title": "Roller Derby", "start": "November 7, 2018 12:00 PM", "end": "November 7, 2018 2:30 PM", "title": "Basketball Game", "start": "November 8, 2018 7:30 PM", "end": "November 8, 2018 10:30 PM", "title": "Local Pub with Friends", "start": "November 1, 2018 7:30 PM", "end": "November 1, 2018 11:00 PM", "title": "Dentist Appointment", "start": "November 10, 2018 1:45 PM", "end": "November 10, 2018 2:30 PM", "title": "Free Donuts", "start": "November 9, 2018 3:00 PM", "end": "November 9, 2018 4:00 PM", "title": "TV Show Marathon", "start": "November 9, 2018 4:30 PM", "end": "November 9, 2018 9:00 PM", "title": "Lunch with Friends", "start": "November 8, 2018 11:30 AM", "end": "November 8, 2018 1:00 PM", "title": "SF Coffee Festival","start": "November 6, 2018 6:00 PM","end": "November 6, 2018 9:00 PM", "title": "Beer with Friends", "start": "November 9, 2018 8:00 PM", "end": "November 9, 2018 9:30 PM", "title": "Yoga", "start": "November 1, 2018 6:00 PM", "end": "November 1, 2018 7:30 PM", "title": "Rock Concert", "start": "November 7, 2018 6:30 PM", "end": "November 7, 2018 11:00 PM", "title": "Lunch Meeting", "start": "November 9, 2018 12:30 PM", "end": "November 9, 2018 2:30 PM", "title": "Bicycling with Friends", "start": "November 1, 2018 6:00 AM", "end": "November 1, 2018 9:30 AM", "title": "Birthday Party", "start": "November 10, 2018 12:30 PM", "end": "November 10, 2018 8:30 PM", "title": "Football Tailgate with John", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM"]
【问题讨论】:
参见JSONDecoder.dateDecodingStrategy,或编写自定义解码初始化。不需要第二个结构。无论如何,这种日期格式将很难解码。 我已经在你最后的question中展示了如何将它们解码为日期 我正在尝试创建自定义解码初始化,但似乎无法正确完成。 找一个例子。您的代码甚至与自定义解码 init 的样子都不相近。 我已经再次展示了如何解码您的日期。您其他问题中链接的重复帖子具有完全相同的日期格式。 【参考方案1】:没有不同的类型,所有字典中的所有值始终具有相同的类型String
。
因此singleValueContainer
是错误的方法,根本不需要自定义初始化程序。
要将字符串日期解码为Date
,只需添加适当的日期解码策略
let jsonString = """
["title": "Evening Picnic", "start": "November 10, 2018 6:00 PM", "end": "November 10, 2018 7:00 PM", "title": "Nap Break", "start": "November 8, 2018 12:30 PM", "end": "November 8, 2018 1:30 PM", "title": "Football Game", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM", "title": "Evening Cookout with Friends", "start": "November 6, 2018 5:00 PM", "end": "November 6, 2018 10:00 PM", "title": "Roller Derby", "start": "November 7, 2018 12:00 PM", "end": "November 7, 2018 2:30 PM", "title": "Basketball Game", "start": "November 8, 2018 7:30 PM", "end": "November 8, 2018 10:30 PM", "title": "Local Pub with Friends", "start": "November 1, 2018 7:30 PM", "end": "November 1, 2018 11:00 PM", "title": "Dentist Appointment", "start": "November 10, 2018 1:45 PM", "end": "November 10, 2018 2:30 PM", "title": "Free Donuts", "start": "November 9, 2018 3:00 PM", "end": "November 9, 2018 4:00 PM", "title": "TV Show Marathon", "start": "November 9, 2018 4:30 PM", "end": "November 9, 2018 9:00 PM", "title": "Lunch with Friends", "start": "November 8, 2018 11:30 AM", "end": "November 8, 2018 1:00 PM", "title": "SF Coffee Festival","start": "November 6, 2018 6:00 PM","end": "November 6, 2018 9:00 PM", "title": "Beer with Friends", "start": "November 9, 2018 8:00 PM", "end": "November 9, 2018 9:30 PM", "title": "Yoga", "start": "November 1, 2018 6:00 PM", "end": "November 1, 2018 7:30 PM", "title": "Rock Concert", "start": "November 7, 2018 6:30 PM", "end": "November 7, 2018 11:00 PM", "title": "Lunch Meeting", "start": "November 9, 2018 12:30 PM", "end": "November 9, 2018 2:30 PM", "title": "Bicycling with Friends", "start": "November 1, 2018 6:00 AM", "end": "November 1, 2018 9:30 AM", "title": "Birthday Party", "start": "November 10, 2018 12:30 PM", "end": "November 10, 2018 8:30 PM", "title": "Football Tailgate with John", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM"]
"""
struct Event : Decodable
let title : String
let start, end : Date
let formatter = DateFormatter()
formatter.locale = Locale(identifier: "en_US_POSIX")
formatter.dateFormat = "MMMM dd, yyyy h:mm a"
do
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .formatted(formatter)
let result = try decoder.decode([Event].self, from: Data(jsonString.utf8))
print(result)
catch
print(error)
【讨论】:
太棒了!我确实尝试过它并且它工作,在相当新的 swift 中,所以其中一些概念对我来说仍然很难掌握。不过非常感谢!说真的,我无法表达我的感激之情!【参考方案2】:-> 首先你需要接受正确的 JSON 数据
let json = """
"data" : ["title": "Evening Picnic", "start": "November 10, 2018 6:00 PM", "end": "November 10, 2018 7:00 PM", "title": "Nap Break", "start": "November 8, 2018 12:30 PM", "end": "November 8, 2018 1:30 PM", "title": "Football Game", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM", "title": "Evening Cookout with Friends", "start": "November 6, 2018 5:00 PM", "end": "November 6, 2018 10:00 PM", "title": "Roller Derby", "start": "November 7, 2018 12:00 PM", "end": "November 7, 2018 2:30 PM", "title": "Basketball Game", "start": "November 8, 2018 7:30 PM", "end": "November 8, 2018 10:30 PM", "title": "Local Pub with Friends", "start": "November 1, 2018 7:30 PM", "end": "November 1, 2018 11:00 PM", "title": "Dentist Appointment", "start": "November 10, 2018 1:45 PM", "end": "November 10, 2018 2:30 PM", "title": "Free Donuts", "start": "November 9, 2018 3:00 PM", "end": "November 9, 2018 4:00 PM", "title": "TV Show Marathon", "start": "November 9, 2018 4:30 PM", "end": "November 9, 2018 9:00 PM", "title": "Lunch with Friends", "start": "November 8, 2018 11:30 AM", "end": "November 8, 2018 1:00 PM", "title": "SF Coffee Festival","start": "November 6, 2018 6:00 PM","end": "November 6, 2018 9:00 PM", "title": "Beer with Friends", "start": "November 9, 2018 8:00 PM", "end": "November 9, 2018 9:30 PM", "title": "Yoga", "start": "November 1, 2018 6:00 PM", "end": "November 1, 2018 7:30 PM", "title": "Rock Concert", "start": "November 7, 2018 6:30 PM", "end": "November 7, 2018 11:00 PM", "title": "Lunch Meeting", "start": "November 9, 2018 12:30 PM", "end": "November 9, 2018 2:30 PM", "title": "Bicycling with Friends", "start": "November 1, 2018 6:00 AM", "end": "November 1, 2018 9:30 AM", "title": "Birthday Party", "start": "November 10, 2018 12:30 PM", "end": "November 10, 2018 8:30 PM", "title": "Football Tailgate with John", "start": "November 3, 2018 6:00 PM", "end": "November 3, 2018 10:00 PM"]
"""
-> 那么你需要创建一个可编码的类或结构
struct Main: Codable
var data: [MYStruct]?
// MARK: - Datum
struct MYStruct: Codable
var title, start, end: String?
-> 如果键 "start": "November 3, 2018 6:00 PM" 这里的 "start" 延迟你可以像这样使用codingKey
struct MYStruct: Codable
var title, start, end: String?
enum CodingKeys: String, CodingKey
case title = "title" // key name as string
case startDate = "start"
case endDate = "end"
-> 然后创建一个 JSON 解码器来解码 jsonData
override func viewDidLoad()
super.viewDidLoad()
let jsonData = Data(json.utf8)
let decoder = JSONDecoder()
let loadedData = try? decoder.decode(Main.self, from: jsonData) // 1st parameter object name 2nd parameter JsonData
print(loadedData?.data?[0].title)
-> 请记住,您的 json 始终是正确的策略,并以
结尾-> 总是应该在密钥对值中
-> 输出
Optional("Evening Picnic")
【讨论】:
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