Oracle SQL 将行转换为列
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【中文标题】Oracle SQL 将行转换为列【英文标题】:Oracle SQL to convert rows to columns 【发布时间】:2021-03-14 15:21:46 【问题描述】:我找不到合适的答案,所以我把它写在这里。我有一个包含以下字段的表格。
ID Amount DocNum DocStatus DueDate
AA 2400 00005 1 10-Jun-2019
AA 1400 00006 4 21-Sep-2019
AA 9000 00028 1 22-Aug-2020
AA 5000 00201 2 31-Aug-2020
AA 6400 00410 1 22-Jan-2021
AA 2000 00511 1 01-Mar-2021
BB 1500 01390 1 01-Jan-2021
我想显示状态为 1 的前 3 个最新文档
ID Document1 Amount1 Document2 Amount2 Document3 Amount3
AA 00511 2000 00410 6400 00028 9000
BB 01390 1500 XX XX XX XX
我以为我可以使用 Pivot 或 Decode 但无法确定其他条件。任何帮助表示赞赏。
【问题讨论】:
【参考方案1】:您可以使用row_number()
和条件聚合:
select id,
max(case when seqnum = 1 then docnum end) as docnum_1,
max(case when seqnum = 1 then amount end) as amount_1,
max(case when seqnum = 2 then docnum end) as docnum_2,
max(case when seqnum = 2 then amount end) as amount_2,
max(case when seqnum = 3 then docnum end) as docnum_3,
max(case when seqnum = 3 then amount end) as amount_3
from (select t.*,
row_number() over (partition by id order by due_date desc) as seqnum
from t
where status = 1
) t
group by id;
【讨论】:
@mathguy 。 . .谢谢。【参考方案2】:alter session set nls_date_format='dd-Mon-yyyy';
with
my_table (id, amount, docnum, docstatus, duedate) as (
select 'AA', 2400, '00005', 1, to_date('10-Jun-2019') from dual union all
select 'AA', 1400, '00006', 4, to_date('21-Sep-2019') from dual union all
select 'AA', 9000, '00028', 1, to_date('22-Aug-2020') from dual union all
select 'AA', 5000, '00201', 2, to_date('31-Aug-2020') from dual union all
select 'AA', 6400, '00410', 1, to_date('22-Jan-2021') from dual union all
select 'AA', 2000, '00511', 1, to_date('01-Mar-2021') from dual union all
select 'BB', 1500, '01390', 1, to_date('01-Jan-2021') from dual
)
select id, "1_DOC" as document1, "1_AMT" as amount1,
"2_DOC" as document2, "2_AMT" as amount2,
"3_DOC" as document3, "3_AMT" as amount3
from (
select id, amount, docnum,
row_number() over (partition by id
order by duedate desc) as rn
from my_table
where docstatus = 1
)
pivot (min(docnum) as doc, min(amount) as amt for rn in (1, 2, 3))
;
ID DOCUMENT1 AMOUNT1 DOCUMENT2 AMOUNT2 DOCUMENT3 AMOUNT3
-- --------- ---------- --------- ---------- --------- ----------
AA 00511 2000 00410 6400 00028 9000
BB 01390 1500
您需要在子查询中完成所有准备工作:过滤docstatus = 1
,按duedate
降序创建RN
排名,然后只选择您需要作为数据透视表的列。除了微不足道的旋转(在子查询中完成所有准备工作之后微不足道)之外,外部查询只需要在 select
子句中小心一点,以正确获取列名。
【讨论】:
【参考方案3】:您可以动态生成所需的 SQL SELECT 语句,以便通过使用 IN 参数创建这样的函数来表示前 2、3、4 ..etc 的行以显示是否前 2、3、4 ..etc并返回SYS_REFCURSOR
类型结果集为
CREATE OR REPLACE FUNCTION Fn_Pivot_Doc_and_Amounts( numcol INT ) RETURN SYS_REFCURSOR IS
v_recordset SYS_REFCURSOR;
v_sql VARCHAR2(32767);
v_cols VARCHAR2(32767);
BEGIN
SELECT LISTAGG( ''||level||' AS "'||level||'"' , ',' )
WITHIN GROUP ( ORDER BY level )
INTO v_cols
FROM dual
CONNECT BY level <= numcol;
v_sql :='SELECT *
FROM(SELECT id,docnum,amount,
ROW_NUMBER() OVER (PARTITION BY id ORDER BY duedate DESC) AS rn
FROM tab t
WHERE docstatus = 1)
PIVOT(
MAX(docnum) AS document,
MAX(amount) AS amount FOR rn IN ( '|| v_cols ||' )
)';
OPEN v_recordset FOR v_sql;
RETURN v_recordset;
END;
然后从 SQL Developer 的控制台调用
SQL> DECLARE
result SYS_REFCURSOR;
BEGIN
:result := Fn_Pivot_Doc_and_Amounts(2); -- 3,4,...
END;
/
SQL> PRINT result;
【讨论】:
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