Oracle SQL count() 每小时

Posted 2023-05-09

【中文标题】Oracle SQL count() 每小时

【英文标题】：Oracle SQL count() per hour

【发布时间】：2013-12-18 00:15:12

【问题描述】：

我有一个查询，显示每个承运人每小时的发货量。我按小时计算，但在报告下一小时的数据之前，它会显示零，直到前一小时完成。本质上，希望从左到右阅读，如果承运人在那一小时内没有发货，则为 NULL。

代码：

    select router_destination_code, 
count(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end) as "Hour 1",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end) as "Hour 2",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end) as "Hour 3",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end) as "Hour 4",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end) as "Hour 5",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end) as "Hour 6"
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then router_destination_code else NULL end,
count(Router_Destination_code) desc;

输出：

戈登·林诺夫提出的新问题

select router_destination_code, 
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end) as "Hour 1",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end) as "Hour 2",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end) as "Hour 3",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end) as "Hour 4",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end) as "Hour 5",
sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end) as "Hour 6"
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 2 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 3 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 4 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 5 end,
case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 6 end,
count(Router_Destination_code) desc;

【问题讨论】：

请提供样本输入和期望的结果。你的问题不清楚。

@GordonLinoff 我在下面回复了您的回答，一切似乎都很好！我在下面回复。

【参考方案1】：

不要使用count(. . .)，而是使用sum(. . .)，如：

sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00'
         then 1 end) as "Hour 1"

编辑：

为了清楚起见，查询应该是：

select router_destination_code, 
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end) as "Hour 1",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 1 end) as "Hour 2",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 1 end) as "Hour 3",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 1 end) as "Hour 4",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 1 end) as "Hour 5",
       sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 1 end) as "Hour 6"
from booker.routing_container_history
where app_last_updated_by_module in ('ManualSlam', 'slam') and
      app_last_updated_date_utc between 'dec/07/2013 00:00:00' and 'dec/14/2013 00:00:00'
group by router_destination_code
order by sum(case when to_char(app_last_updated_date_utc, 'HH24') = '00' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '01' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '02' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '03' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '04' then 1 end),
         sum(case when to_char(app_last_updated_date_utc, 'HH24') = '05' then 1 end),
         count(Router_Destination_code) desc;

【讨论】：

你在哪里有 1，我不想再 'router_destination_code' 吗？做总和？基本上我想要 HH24 = 01 时 router_destination_code 的总和，等等 02,03 等。谢谢。

我使用了你的建议，但是，现在它不是 0，而是 NULL..Updated question with new query。

会在那个时间范围内对所有的数据求和，还是取平均值？谢谢。

@Spartacus38 。 . .它将在时间范围内汇总，就像您的原始查询在时间范围内计算所有内容一样。

@Spartacus38 。 . .您可以将else 0 添加到每个case 语句中。