转置列 Oracle sql

Posted 2023-05-09

【中文标题】转置列 Oracle sql

【英文标题】：Transpose columns Oracle sql

【发布时间】：2021-06-29 12:27:47

【问题描述】：

我们在下面的结构中有一个 oracle 表。

要求是创建一个 sql 以生成以下格式的报告。 如您所见，最近 6 个月的曝光应该转置为行。 在某些情况下，我们还缺少需要处理的年份和月份数据。 感谢您检查并提出建议。

谢谢， 普拉迪普。

【参考方案1】：

使用 lag() 。 . .使用窗口函数获取最后一行：

select pa.*
from (select pa.*,
             lag(exposure, 1) over (partition by dealid order by rundate) as exposure_1,
             lag(exposure, 2) over (partition by dealid order by rundate) as exposure_2,
             lag(exposure, 3) over (partition by dealid order by rundate) as exposure_3,
             lag(exposure, 4) over (partition by dealid order by rundate) as exposure_4,
             lag(exposure, 5) over (partition by dealid order by rundate) as exposure_5,
             row_number() over (partition by dealid order by rundate desc) as seqnum
      from poolagreements pa
     ) pa
where seqnum = 1;

【讨论】：

感谢戈登的建议。我尝试了以下没有任何运气.. 出现 ORA-00933 错误。你能检查和建议吗？ select t.* from (select t.*, lag(exposure, 1) over (partition by dealid order by rundate) as exposure_1, lag(exposure, 2) over (partition by dealid order by rundate) as exposure_2, row_number() over (partition by dealid order by rundate desc) as seqnum from poolagreements t ) poolagreements t where seqnum = 1;

@Prdp 。 . .表名应该在question 中。假设是poolagreements，我更新了答案。