使用 Windows 服务进行轮询

Posted 2023-05-07

【中文标题】使用 Windows 服务进行轮询

【英文标题】：Polling using Windows Service

【发布时间】：2017-01-22 23:52:32

【问题描述】：

通过查看一些示例，我参考了Polling Service - C# 进行投票。

这是我的代码。

public partial class Service1 : ServiceBase

    private readonly PollingService _pollingService = new PollingService();

    public Service1()
    
        InitializeComponent();
    

    protected override void OnStart(string[] args)
    
        _pollingService.StartPolling();
    

    protected override void OnStop()
    
       _pollingService.StopPolling();
    


public class PollingService

    private Thread _workerThread;
    private AutoResetEvent _finished;
    private const int _timeout = 60 * 1000;
    string command = "5120000000000000000000000000000";


    public void StartPolling()
    
        _workerThread = new Thread(Poll);
        _finished = new AutoResetEvent(false);
        _workerThread.Start();
    

    private void Poll()
    
        while (!_finished.WaitOne(_timeout))
        
            //do the task
            using (TcpClient newclient = new TcpClient())
            
                IAsyncResult ar = newclient.BeginConnect("192.168.0.151", 4000, null, null);
                if (!ar.AsyncWaitHandle.WaitOne(TimeSpan.FromSeconds(2), false))
                
                    return;
                

                NetworkStream ns = newclient.GetStream();
                byte[] outbytes = HexStringToByteArray(command);
                ns.Write(outbytes, 0, outbytes.Length);
            
        
    

    public void StopPolling()
    
        _finished.Set();
        _workerThread.Join();
    

    public static byte[] HexStringToByteArray(string hexString)
    
        if (hexString.Length % 2 > 0)
        
            throw new Exception("Invalid command.");
        
        byte[] result = new byte[hexString.Length / 2];
        try
        
            for (int i = 0; i < result.Length; i++)
            
                result[i] = Convert.ToByte(hexString.Substring(2 * i, 2), 16);
            
        
        catch (Exception)
        
            throw;
        
        return result;
    

我已经成功安装了。但是，当我尝试启动服务时，我收到了Windows could not start the service on Local Computer. Error 5: Access is denied。我试过使用这里给出的解决方案Error 5 : Access Denied when starting windows service，但是它不起作用。

【参考方案1】：

我通过使用一些更新的代码将服务属性从 This Account 更改为 Local System Account 找到了解决方案。

 using (TcpClient newclient = new TcpClient("192.168.0.151", 4000))
 
     NetworkStream ns = newclient.GetStream();
     byte[] outbytes = Encoding.ASCII.GetBytes(command);
     ns.Write(outbytes, 0, outbytes.Length);
     ns.Close();
     newclient.Close();