将数据传递给服务 - android？

Posted 2023-05-07

【中文标题】将数据传递给服务 - android？

【英文标题】：Pass data to service - android?

【发布时间】：2016-08-21 11:58:43

【问题描述】：

我的 Activity 中有一个 AsyncTask，我调用 AsyncTask ：

CallServicesSetQuestion task = new CallServicesSetQuestion();
task.execute(rb);

然后：

public class CallServicesSetQuestion extends AsyncTask<RequestPackage,String,String>

    @Override
    protected void onPreExecute() 
        super.onPreExecute();
    

    @Override
    protected String doInBackground(RequestPackage... params) 
        Intent response = new Intent(_Context, SendComment_Service.class);
        response.putExtra("params", params[0]);<===== HERE
        _Context.startService(response);


        return content;
    

    @Override
    protected void onPostExecute(String result) 
        super.onPostExecute(result);
    

我需要将 RequestPackage 发送到服务，但我不能。我怎么不能发送它。

这是我的请求包：

public class RequestPackage 
    private String uri;
    private String method = "GET";
    private Map<String,String> params = new HashMap<>();

    public String getUri() 
        return uri;
    

    public void setUri(String uri) 
        this.uri = uri;
    

    public String getMethod() 
        return method;
    

    public void setMethod(String method) 
        this.method = method;
    

    public Map<String, String> getParams() 
        return params;
    

    public void setParams(Map<String, String> params) 
        this.params = params;
    

    public void setParam(String key,String value)
        params.put(key,value);
    
    public String getEncodedParams()
        StringBuilder sb = new StringBuilder();
        for (String key:params.keySet()) 
            String value = null;
            try 
                value = URLEncoder.encode(params.get(key),"UTF-8");
             catch (UnsupportedEncodingException e) 
                e.printStackTrace();
            
            if (sb.length()>0)
                sb.append("&");
            
            sb.append(key + "=" + value);
        
        return sb.toString();
    

【问题讨论】：

这里 response.putExtra("params", params[0]);我无法将 RequestPackage 发送到服务。

【参考方案1】：

我觉得你需要把它序列化

public class RequestPackage implements Serializable  .. 


Intent response = new Intent(_Context, SendComment_Service.class);
Bundle bundle = new Bundle();
bundle.putSerializable("params", params[0]);
response.putExtras(bundle);
_Context.startService(response);

【参考方案2】：

Make Request Package Serializable or parseable Like this then you can send

public class RequestPackage implements Serializable
 
    private String uri;
    private String method = "GET";
    private Map<String,String> params = new HashMap<>();

    public String getUri() 
        return uri;
    

    public void setUri(String uri) 
        this.uri = uri;
    

    public String getMethod() 
        return method;
    

    public void setMethod(String method) 
        this.method = method;
    

    public Map<String, String> getParams() 
        return params;
    

    public void setParams(Map<String, String> params) 
        this.params = params;
    

    public void setParam(String key,String value)
        params.put(key,value);
    
    public String getEncodedParams()
        StringBuilder sb = new StringBuilder();
        for (String key:params.keySet()) 
            String value = null;
            try 
                value = URLEncoder.encode(params.get(key),"UTF-8");
             catch (UnsupportedEncodingException e) 
                e.printStackTrace();
            
            if (sb.length()>0)
                sb.append("&");
            
            sb.append(key + "=" + value);
        
        return sb.toString();
    

【讨论】：

如何从服务中获取数据？

您可以使用Handler从服务中获取数据

非常感谢。在您的指导下，我使用此链接javacodegeeks.com/2014/01/…。