如何根据 JSON 数据和过滤参数过滤列表视图?
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【中文标题】如何根据 JSON 数据和过滤参数过滤列表视图?【英文标题】:How to filter a list view based on JSON data and filter parameters? 【发布时间】:2015-10-02 22:07:56 【问题描述】:我正在尝试在 android 中创建一个带有过滤器的ListView
。
我们有两个下拉菜单,角色和性别,以及一个搜索按钮。
当用户单击搜索按钮时,我只想显示与所选下拉值相关的数据。
例如,如果我分别从“角色”和“性别”中选择“工程师”和“男性”,那么它应该只显示“角色”中有工程师和“性别”中有男性的数据。
从以下 JSON 文件中,应该显示的唯一记录是“BHARGAV”。
"contacts": [
"id": "c200",
"name": "Bhargav",
"email": "ab@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"role" : "Engineer",
"phone":
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
,
"id": "c201",
"name": "Johnny",
"email": "johnny@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"role" : "CharteredAccountant",
"phone":
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
,
"id": "c202",
"name": "Leonardo Dicaprio",
"email": "leonardo_dicaprio@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"role" : "Doctor",
"phone":
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
]
这是我的代码
public class MainActivity extends ListActivity
private ProgressDialog pDialog;
// URL to get contacts JSON
private static String url = "http://api.examplesite.com/contacts/";
// JSON Node names
private static final String TAG_CONTACTS = "contacts";
private static final String TAG_ID = "id";
private static final String TAG_NAME = "name";
private static final String TAG_EMAIL = "email";
private static final String TAG_ADDRESS = "address";
private static final String TAG_GENDER = "gender";
private static final String TAG_ROLE = "role";
private static final String TAG_PHONE = "phone";
private static final String TAG_PHONE_MOBILE = "mobile";
private static final String TAG_PHONE_HOME = "home";
private static final String TAG_PHONE_OFFICE = "office";
// contacts JSONArray
JSONArray contacts = null;
// Hashmap for ListView
ArrayList<HashMap<String, String>> contactList;
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
contactList = new ArrayList<HashMap<String, String>>();
ListView lv = getListView();
// Listview on item click listener
lv.setOnItemClickListener(new OnItemClickListener()
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id)
// getting values from selected ListItem
String name = ((TextView) view.findViewById(R.id.name))
.getText().toString();
String cost = ((TextView) view.findViewById(R.id.email))
.getText().toString();
String description = ((TextView) view.findViewById(R.id.mobile))
.getText().toString();
// Starting single contact activity
Intent in = new Intent(getApplicationContext(),
SingleContactActivity.class);
in.putExtra(TAG_NAME, name);
in.putExtra(TAG_EMAIL, cost);
in.putExtra(TAG_PHONE_MOBILE, description);
startActivity(in);
);
// Calling async task to get json
new GetContacts().execute();
/**
* Async task class to get json by making HTTP call
* */
private class GetContacts extends AsyncTask<Void, Void, Void>
@Override
protected void onPreExecute()
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(MainActivity.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();
@Override
protected Void doInBackground(Void... arg0)
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null)
try
JSONObject jsonObj = new JSONObject(jsonStr);
// Getting JSON Array node
contacts = jsonObj.getJSONArray(TAG_CONTACTS);
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++)
JSONObject c = contacts.getJSONObject(i);
String id = c.getString(TAG_ID);
String name = c.getString(TAG_NAME);
String email = c.getString(TAG_EMAIL);
String address = c.getString(TAG_ADDRESS);
String gender = c.getString(TAG_GENDER);
String role = c.getString(TAG_ROLE);
// Phone node is JSON Object
JSONObject phone = c.getJSONObject(TAG_PHONE);
String mobile = phone.getString(TAG_PHONE_MOBILE);
String home = phone.getString(TAG_PHONE_HOME);
String office = phone.getString(TAG_PHONE_OFFICE);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(TAG_ID, id);
contact.put(TAG_NAME, name);
contact.put(TAG_EMAIL, email);
contact.put(TAG_PHONE_MOBILE, mobile);
// adding contact to contact list
contactList.add(contact);
catch (JSONException e)
e.printStackTrace();
else
Log.e("ServiceHandler", "Couldn't get any data from the url");
return null;
@Override
protected void onPostExecute(Void result)
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
MainActivity.this, contactList,
R.layout.list_item, new String[] TAG_NAME, TAG_EMAIL,
TAG_PHONE_MOBILE , new int[] R.id.name,
R.id.email, R.id.mobile );
setListAdapter(adapter);
它没有按预期工作。
怎么了?我怎样才能正确地实现它?
【问题讨论】:
我不完全确定您想要实现什么目标以及您在这里无法做到什么。 我正在尝试从 JSON 文件中获取列表视图,但不是所有来自 JSON 文件的数据我只想要从 json 文件中选择的数据 我知道如何解析 JSON...这里我也有 listview 但我有所有数据的 listview 但我只想要选定的数据所以我该怎么做? 你让自己成为一个模型对象,只包含你想要的 JSON 文件中的数据,然后你解析你的 JSON(你也可以看看 GSON 库),然后你传递那个对象或列表对象到您的列表视图的适配器。 【参考方案1】:您可以在 for 循环中设置 if 条件,从 JSON 中获取所有数据并在适配器中设置,如下所示...
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++)
JSONObject c = contacts.getJSONObject(i);
if(c.getString(TAG_GENDER).equalsIgnoreCase((String) Role.getSelectedItem()) && c.getString(TAG_ROLE).equalsIgnoreCase((String) Gender.getSelectedItem()))
String id = c.getString(TAG_ID);
String name = c.getString(TAG_NAME);
String email = c.getString(TAG_EMAIL);
String address = c.getString(TAG_ADDRESS);
String gender = c.getString(TAG_GENDER);
String role = c.getString(TAG_ROLE);
// Phone node is JSON Object
JSONObject phone = c.getJSONObject(TAG_PHONE);
String mobile = phone.getString(TAG_PHONE_MOBILE);
String home = phone.getString(TAG_PHONE_HOME);
String office = phone.getString(TAG_PHONE_OFFICE);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(TAG_ID, id);
contact.put(TAG_NAME, name);
contact.put(TAG_EMAIL, email);
contact.put(TAG_PHONE_MOBILE, mobile);
// adding contact to contact list
contactList.add(contact);
【讨论】:
【参考方案2】:从服务器获取所有数据并填写contactList
list 后,您需要将数据与用户给定的条件进行比较。
简单地迭代 contactList
并检查用户给定的值
检查下面的伪代码
ArrayList<HashMap<String, String>> finalList = new ArrayList<HashMap<String, String>>();
for (int i = 0; i < contactList.length(); i++)
HashMap<String, String> map = contactList.get(i);
if(map.TAG_NAME == "BHARGAV" && map.TAG_GENDER == "MALE")
finalList.add(map);
现在使用这个 'finalList' 来显示值
提示:创建模型/自定义类来保存数据比 Hashmap
更好。
【讨论】:
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