错误:实体类必须用@Entity注解

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【中文标题】错误:实体类必须用@Entity注解【英文标题】:error: Entity class must be annotated with @Entity 【发布时间】:2018-07-12 03:23:48 【问题描述】:

我决定将 kotlin 与 Room 库一起使用,但我确实遇到了很多问题,并且厌倦了阅读参考资料和寻找解决方案 我的数据类:

@Entity
data class HistorySong(
        @PrimaryKey
        var SongId: Int =0,

        @ColumnInfo(name = "song_name")
        var songName: String="",

        @ColumnInfo(name = "song_artist")
        var songArtist: String="",

        @ColumnInfo(name = "song_link")
        var songLink: String="",

        @ColumnInfo(name = "image_path")
        var songImagePath: String="",

        @ColumnInfo(name="is_favoutire")
        var songisFavourite: Boolean= false
)

我的道课:

@Dao
 interface HistorySongDao 

       @Delete
       fun deleteSong(historySongDao: HistorySongDao)

       @Insert(onConflict = OnConflictStrategy.REPLACE)
        fun insert(vararg historySongDao: HistorySongDao)

       @Query("SELECT * FROM HistorySong")
        fun loadAllSongs(): Array<HistorySong>


       @Query("SELECT * FROM HistorySong WHERE songId = :mId")
        fun findById(mId: Int): HistorySong

       @Query("SELECT * FROM HistorySong WHERE is_favoutire = :getFavourite ")
        fun getFavourite(getFavourite : Boolean) : Array<HistorySong>



       @Update
       fun updateUsers(vararg historySong: HistorySong)

数据库类:

@Database(entities = arrayOf(QueuedSong::class, HistorySongDao::class), version = 2)
abstract class AppDataBase : RoomDatabase() 
    abstract fun queuedSongDao(): QueuedSongDao
    abstract fun historySongDao(): HistorySongDao

QueuedSong 运行良好,但 historySong 中的问题是:

e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:7: error: Entity class must be annotated with @Entity
public abstract interface HistorySongDao 
                ^
w: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\AppDataBase.java:10: warning: Room cannot create an SQLite connection to verify the queries. Query verification will be disabled. Error: [SQLITE_ERROR] SQL error or missing database (near ")": syntax error)
public abstract class AppDataBase extends android.arch.persistence.room.RoomDatabase 
                ^
w: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySong.java:10: warning: There are multiple good constructors and Room will pick the no-arg constructor. You can use the @Ignore annotation to eliminate unwanted constructors.
public final class HistorySong 
             ^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:15: error: Type of the parameter must be a class annotated with @Entity or a collection/array of it.
    com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao... historySongDao);
                                                                    ^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:11: error: Type of the parameter must be a class annotated with @Entity or a collection/array of it.
    com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao historySongDao);
                                                                 ^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:30: error: com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao is part of com.pro.smartstreamer.Database.QueuedDatabase.AppDataBase but this entity is not in the database. Maybe you forgot to add com.pro.smartstreamer.Database.QueuedDatabase.HistorySong to the entities section of the @Database?
    public abstract void updateUsers(@org.jetbrains.annotations.NotNull()

和:

FAILURE: Build failed with an exception.

* What went wrong:
Execution failed for task ':app:kaptDebugKotlin'.
> Compilation error. See log for more details

我真的找不到解决办法.. 提前致谢

【问题讨论】:

对于初学者,您尝试插入和删除 HistorySongDao 对象而不是 HistorySong 对象。看看修复是否有助于解决其中一些错误。 【参考方案1】:

我通过更改 @Database 的参数(RoomDatabase 类)解决了这个问题,但我没有意识到并将我的 DAO 放在应该是我的实体的位置。

就我而言:

@Database(entities = [WordDao::class],version = 1)

改为:

@Database(entities = [WordEntity::class],version = 1)

所以,当有人收到这个错误时,也许不仅要检查实体的声明位置,还要检查它的使用位置。

【讨论】:

成功了。我真的很新来使用房间。浪费了很多时间。 @felipe 你是个传奇,谢谢你为我指明了正确的方向!!【参考方案2】:

正如第一条评论中所说,您尝试插入和删除 HistorySongDao 对象而不是 HistorySong,您的代码将变为:

@Dao
 interface HistorySongDao 

       @Delete
       fun deleteSong(vararg historySong: HistorySong)

       @Insert(onConflict = OnConflictStrategy.REPLACE)
        fun insert(vararg historySong: HistorySong)

       @Query("SELECT * FROM HistorySong")
        fun loadAllSongs(): Array<HistorySong>

       @Query("SELECT * FROM HistorySong WHERE songId = :mId")
        fun findById(mId: Int): HistorySong

       @Query("SELECT * FROM HistorySong WHERE is_favoutire = :getFavourite ")
        fun getFavourite(getFavourite : Boolean) : Array<HistorySong>

       @Update
       fun updateUsers(vararg historySong: HistorySong)

【讨论】:

【参考方案3】:

将数据库类更新为此

@Database(entities = arrayOf(QueuedSong::class, HistorySong::class), version = 2)
abstract class AppDataBase : RoomDatabase() 
abstract fun queuedSongDao(): QueuedSongDao
abstract fun historySongDao(): HistorySongDao

我将 HistorySongDao.class 更改为 HistorySong.class

【讨论】:

【参考方案4】:

你在你的数据库类中误用了实体。 也许你调用的是 Dao Interface 而不是 Entity 类。

【讨论】:

你能说出答案中的类名吗?对理解会更有帮助。 在此处打开您的数据库类.. @Database (entities =Entity.class, version=1,exportedSchema =false) > 看看这里的实体= 部分,也许您正在调用你的 Dao 界面或其他东西。【参考方案5】:

对我来说这是一个不同的问题:[ 而不是

我说:

@Database(entities = [Sensor.class, Meter.class],version = 2)

代替:

@Database(entities =Sensor.class, Meter.class, version = 2)

【讨论】:

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