当我的 textInputLayout 为空时如何出错

Posted 2023-04-18

【中文标题】当我的 textInputLayout 为空时如何出错

【英文标题】：How to put an error when my textInputLayout is empty

【发布时间】：2020-12-20 17:17:37

【问题描述】：

我正在用textInputLayout进行小数加法，问题是在调用isEmpty()时显示错误，以防字段为空，没有出现这个选项。

我想这样做

 button.setOnClickListener 


            val numberOne = textInputLayout.editText?.text.toString().toDouble()
            val numberTwo = textInputLayout2.editText?.text.toString().toDouble()
            val reult = numberOne + numberTwo

            if (numberOne./*no appears isEmpty*/)
              textInputLayout.error = ("enter number")
            else
                if (numberTwo./*no appears isEmpty*/)
                    textInputLayout2.error = ("enter number")
                else 
                    textView.text = reult.toString()
                
            
        

xmlns

 <com.google.android.material.textfield.TextInputLayout
        android:id="@+id/textInputLayout"
        android:layout_
        android:layout_
        android:layout_marginTop="60dp"
        android:hint="@string/numero"
        app:layout_constraintEnd_toEndOf="parent"
        app:errorEnabled="true"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="parent"
        style="@style/Widget.MaterialComponents.TextInputLayout.OutlinedBox">

        <com.google.android.material.textfield.TextInputEditText
            android:layout_
            android:layout_ />
    </com.google.android.material.textfield.TextInputLayout>

    <com.google.android.material.textfield.TextInputLayout
        android:id="@+id/textInputLayout2"
        style="@style/Widget.MaterialComponents.TextInputLayout.OutlinedBox"
        android:layout_
        android:layout_
        android:layout_marginTop="120dp"
        android:hint="@string/numero2"
        app:errorEnabled="true"
        app:layout_constraintEnd_toEndOf="parent"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="parent">

        <com.google.android.material.textfield.TextInputEditText
            android:layout_
            android:layout_ />
    </com.google.android.material.textfield.TextInputLayout>

 

 

【参考方案1】：

你可以使用类似的东西：

        <com.google.android.material.textfield.TextInputLayout>

            <com.google.android.material.textfield.TextInputEditText
                android:inputType="numberDecimal"
                .../>

您可以通过以下方式检查值：

val double: Double? = textInputLayout.editText?.text.toString().toDoubleOrNull()
val double2: Double? = textInputLayout2.editText?.text.toString().toDoubleOrNull()
    
if (double != null)
      //Double1 is a number
      textInputLayout.error = ""
      if (double2 != null)
         //Double2 is a number
          textInputLayout2.error = ""
          textview.text = (double+double2).toString()
        else 
          //Double2 is not a number
          textInputLayout2.error = "Error"
           textview.text = ""
       
  else 
     //Double1 is not a number
     textInputLayout.error = "Error"
     textview.text = ""
 

【讨论】：

准备好反映错误但我不知道如何添加数字并显示结果

把你的逻辑移到//Number is double

我这样做了：val double: Double? = number1.editText?.text.toString().toDoubleOrNull() double?.let // Number is double... ?: (number1.setError("Enter number") ) val double2: Double? = number1.editText?.text.toString().toDoubleOrNull() double2?.let // Number is double... ?: (number2.setError("Enter number") )

我是这样做的，所以错误出现在两个字段中，对不起我是初学者

@JorgeLeonardo 以更简单的方式重写了答案

【参考方案2】：

numberOne 和 numberTwo 是双精度 val numberOne = textInputLayout.editText?.text.toString().toDouble()

isEmpty() 是一个字符串函数 尝试 numberOne.toString().isEmpty() 和 numberTwo 相同

【讨论】：

好的，那么您可以尝试将 num1,num2 声明为字符串，然后将结果转换为双精度值，例如 val numberOne = textInputLayout.editText?.text.toString() val numberTwo = textInputLayout2.editText?。 text.toString() val reult = numberOne.toDouble() + numberTwo.toDouble();