我们如何使用 GROUP BY 加入结果
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【中文标题】我们如何使用 GROUP BY 加入结果【英文标题】:How can we join the results with GROUP BY 【发布时间】:2020-01-15 23:44:17 【问题描述】:我在这里加入三个表,并希望通过方法按组获取结果。当我这样编写查询时
$query=$this->db->query("SELECT p.id, p.customerid, T.u_id, A.u_id, T.agent_name,
P.date as d_date, T.total_profit, A.t_price, A.t_dc
FROM bills P
LEFT JOIN((SELECT *,
bill_details.id as b_id,
bill_details.user_id as u_id,
SUM(bill_details.profit) AS total_profit
FROM bill_details
WHERE DATE(bill_details.bill_date) BETWEEN '$start_date' AND
'$end_date'
AND bill_details.user_id = 406
GROUP BY Date(bill_details.bill_date), bill_details.user_id) T)
ON p.id = T.bill_id
LEFT JOIN((SELECT *,
assigned_result.assigned_result_id as a_id,
assigned_result.user_id as u_id,
SUM(assigned_result.total_price) AS t_price,
SUM(assigned_result.total_dc) AS t_dc
FROM assigned_result
WHERE DATE(assigned_result.date) BETWEEN '$start_date' AND
'$end_date'
AND assigned_result.user_id = 406
GROUP BY Date(assigned_result.date), assigned_result.user_id) A)
ON p.id = A.bill_no
WHERE T.u_id = 406
OR A.u_id = 406");
return $query->result();
如果我在做这样的 group_by 条件GROUP BY T.u_id,A.u_id
我的输出看起来像这样
Name Date Purchase Winning Balance
2019-07-25 240 -240
Ned 2019-07-25 132.60 0.00 132
我希望结果是这样的
Name Date Purchase Winning Balance
Ned 2019-07-25 132.60 240 132
【问题讨论】:
【参考方案1】:使用额外的max()
聚合:
SELECT max(Name) as Name, Date, max(Purchase) as Purchase,
max(Winning) as Winning, max(Balance) as Balance
FROM
(
<YourOriginalQuery>
) q
GROUP BY Date;
【讨论】:
【参考方案2】:您没有使用GROUP BY
显示查询。但是根据您的描述,您可以执行以下任一操作:
GROUP BY
。聚合查询将返回一行。
使用 `GROUP BY COALESCE(T.u_id, A.u_id)
如果这些列在SELECT
中,您可能还需要调整SELECT
子句。
【讨论】:
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