Python socket.error:[Errno 104] 对等方重置连接
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【中文标题】Python socket.error:[Errno 104] 对等方重置连接【英文标题】:Python socket.error: [Errno 104] Connection reset by peer 【发布时间】:2016-03-03 01:23:47 【问题描述】:我有一个代码,其中有 13 个客户端必须连接到服务器。然后服务器对客户端提供的数据进行一些计数。之后角色转身——服务器成为客户端,客户端成为接收数据的服务器。
问题是,当尝试进行第一次连接时,即 13 个客户端尝试连接到服务器时,我不断收到此错误:[Errno 104] Connection reset by peer
。我尝试了一些解决方法,例如尝试在第二个间隔内连接 5 次,但没有任何效果。
这是我的代码:
server.py
>import socket, pickle, numpy as np
import struct
import math
while 1:
HOST = ''
PORT = 50007
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(13)
adresses = []
ports = []
i = 0
print("receiving...")
while i < 13:
i += 1
#wait to accept a connection - blocking call
conn, addr = s.accept()
print ('Connected with ', addr)
adresses.append(addr[0])
buf = b''
while len(buf) < 4:
buf += conn.recv(4 - len(buf))
length = struct.unpack('>I', buf)[0]
data = b''
l = length
while l > 0:
d = conn.recv(l)
l -= len(d)
data += d
if not data: break
M = np.loads(data)
if i == 1:
L = M[0]
else:
L += M[0]
ports.append(M[1])
conn.close()
s.close()
L /= 993040
packet = pickle.dumps(L)
length = struct.pack('>I', len(packet))
packet = length + packet
print("sending...")
for kl, addr in enumerate(adresses):
HOST = addr
PORT = 50007 + ports[kl]
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
s.sendall(packet)
s.close()
client.py
>def connection(centers, kl):
HOST = "192.168.143.XX"
PORT = 50007
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.settimeout(3600)
try:
s.connect((HOST, PORT)) # HERE IS AN ERROR
s.settimeout(None)
packet = pickle.dumps([centers, kl]) ## ???
length = struct.pack('>I', len(packet))
packet = length + packet
s.sendall(packet) # OR HERE IS AN ERROR
s.close()
except Exception as e:
print(e)
print('error ', kl)
s.close()
return np.zeros(centers.shape)
HOST = ''
PORT = 50007 + kl
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(2)
i = 0
while i < 1:
#wait to accept a connection - blocking call
conn, addr = s.accept()
i += 1
print ('Connected with ', addr)
buf = b''
while len(buf) < 4:
buf += conn.recv(4 - len(buf))
length = struct.unpack('>I', buf)[0]
data = b''
l = length
while l > 0:
d = conn.recv(l)
l -= len(d)
data += d
if not data: break
new_centers = np.loads(data)
conn.close()
s.close()
return new_centers
aa = 0
for k in range(99):
print(k)
centers = some_function(centers)
time.sleep(60)
centers1 = connection(centers, i)
aa = 0
while not (centers1.any()) and aa < 5:
time.sleep(1)
centers1 = connection(centers, i)
aa += 1
centers = centers1
问题是所有 13 个客户端都必须连接到服务器,否则将无法进行下一次迭代。 我正在使用 Python 3.4。 请帮忙。
更新:
我已添加线程,但错误仍然存在:
[Errno 104] 对等方重置连接
server.py
>import socket, pickle, numpy as np
import struct
import math
from multiprocessing.pool import ThreadPool
def clientthread(conn, L):
buf = b''
while len(buf) < 4:
buf += conn.recv(4 - len(buf))
length = struct.unpack('>I', buf)[0]
data = b''
l = length
while l > 0:
d = conn.recv(l)
l -= len(d)
data += d
M = np.loads(data)
return(M)
j = 0
while 1:
HOST = ''
PORT = 50007
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(2)
#print('0')
adresses = []
ports = []
i = 0
print("receiving...")
while i < 13:
i += 1
#wait to accept a connection - blocking call
conn, addr = s.accept()
print ('Connected with ', addr)
adresses.append(addr[0])
pool = ThreadPool(processes=13)
async_result = pool.apply_async(clientthread, (conn, i,))
M = async_result.get()
conn.close()
if i == 1:
L = M[0]
else:
L += M[0]
ports.append(M[1])
s.close()
L /= 993040
packet = pickle.dumps(L)
length = struct.pack('>I', len(packet))
packet = length + packet
for kl, addr in enumerate(adresses):
HOST = addr
PORT = 50007 + ports[kl]
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
s.sendall(packet)
s.close()
【问题讨论】:
【参考方案1】:客户端似乎已连接到服务器,但在尝试发送数据时遇到“[Errno 104] Connection reset by peer
”异常。第一次,Python 引发“[Errno 104] Connection reset by peer”异常,然后第二次,您将在客户端收到“[Errno 32] Broken pipe”异常。
这可能意味着服务器已启动并正在侦听端口(否则,您将得到“[Errno 111] Connection refused" exception on the client side
”。这也意味着服务器在关闭连接之前崩溃,因为如果连接在服务器端关闭在客户端发送数据之前,客户端会遇到“[Errno 32] Broken pipe
”异常。
“对等方重置连接”是 TCP/IP 等价物,相当于将电话重新挂上。这比仅仅不回复,留下一个悬而未决更有礼貌。但这并不是真正礼貌的 TCP/IP 话务员所期望的 FIN-ACK。 (From another *** answer)
【讨论】:
【参考方案2】:您将不得不在服务器上使用线程。 简单解释见:http://www.binarytides.com/python-socket-server-code-example/ 给出的简单示例的内容是:
import socket
import sys
from thread import *
HOST = '' # Symbolic name meaning all available interfaces
PORT = 8888 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created'
#Bind socket to local host and port
try:
s.bind((HOST, PORT))
except socket.error as msg:
print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
sys.exit()
print 'Socket bind complete'
#Start listening on socket
s.listen(10)
print 'Socket now listening'
#Function for handling connections. This will be used to create threads
def clientthread(conn):
#Sending message to connected client
conn.send('Welcome to the server. Type something and hit enter\n') #send only takes string
#infinite loop so that function do not terminate and thread do not end.
while True:
#Receiving from client
data = conn.recv(1024)
reply = 'OK...' + data
if not data:
break
conn.sendall(reply)
#came out of loop
conn.close()
#now keep talking with the client
while 1:
#wait to accept a connection - blocking call
conn, addr = s.accept()
print 'Connected with ' + addr[0] + ':' + str(addr[1])
#start new thread takes 1st argument as a function name to be run, second is the tuple of arguments to the function.
start_new_thread(clientthread ,(conn,))
s.close()
【讨论】:
我已经尝试过了,但问题是首先我必须从所有客户端接收数据。然后我必须做一些重新计算(实际上是计算数据的平均值)并将其发回。函数clientthred
不能返回任何东西。如何处理?顺便说一句,在 Python3 中它是 threading.Thread(target=clientthread, args=(conn,)).start()
而不是 start_new_thread(clientthread ,(conn,))
【参考方案3】:
我在尝试从 python 连接到远程 redis 实例时遇到了这个确切的错误,因为我错误地让 Fiddler 运行并且它干扰了请求。
【讨论】:
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