是否有数学计算可以通过谷歌的 Elevation API 定义点 A 和点 B 之间是否存在可见性?
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【中文标题】是否有数学计算可以通过谷歌的 Elevation API 定义点 A 和点 B 之间是否存在可见性?【英文标题】:Is there a mathematical calculation to define if there is visibility between a point A and a point B via google's Elevation API? 【发布时间】:2020-07-31 19:51:18 【问题描述】:有没有办法通过 google API 获取海拔剖面数据来检查两点之间是否存在视线?
例如我可以通过此链接获得海拔剖面:https://maps.googleapis.com/maps/api/elevation/json?path=36.578581,-118.291994|36.23998,-116.83171&samples=10&key=YOUR_API_KEY
结果是一个 10 点的 json,位于两点之间,其地面高程,例如:
"results" : [
"elevation" : 4411.94189453125,
"location" :
"lat" : 36.578581,
"lng" : -118.291994
,
"resolution" : 19.08790397644043
,
"elevation" : 1658.561645507812,
"location" :
"lat" : 36.54183904164596,
"lng" : -118.1291141726249
,
"resolution" : 9.543951988220215
,
"elevation" : 1085.295776367188,
"location" :
"lat" : 36.50487579522382,
"lng" : -117.966389550823
,
"resolution" : 9.543951988220215
,
"elevation" : 1491.4912109375,
"location" :
"lat" : 36.46769177008888,
"lng" : -117.8038207060907
,
"resolution" : 9.543951988220215
,
"elevation" : 1583.762817382812,
"location" :
"lat" : 36.43028747728768,
"lng" : -117.6414082023003
,
"resolution" : 9.543951988220215
,
"elevation" : 488.8834228515625,
"location" :
"lat" : 36.39266342953181,
"lng" : -117.4791525957044
,
"resolution" : 9.543951988220215
,
"elevation" : 933.0382080078125,
"location" :
"lat" : 36.35482014117158,
"lng" : -117.3170544349424
,
"resolution" : 9.543951988220215
,
"elevation" : 1657.123779296875,
"location" :
"lat" : 36.31675812816988,
"lng" : -117.1551142610472
,
"resolution" : 9.543951988220215
,
"elevation" : 1074.835205078125,
"location" :
"lat" : 36.27847790807609,
"lng" : -116.9933326074523
,
"resolution" : 9.543951988220215
,
"elevation" : -84.51690673828125,
"location" :
"lat" : 36.23998,
"lng" : -116.83171
,
"resolution" : 9.543951988220215
],
"status" : "OK"
是否有数学公式可以检查A点和B点是否可以看到?
我需要用 php 编写代码。
谢谢大家。
【问题讨论】:
你说这10个点在A点和B点之间,那么它们都和经过A点和B点的线在同一条线上吗? 是的,这些点在同一条线上。 【参考方案1】:鉴于您正在处理沿直线的 2 个点,我认为处理此问题的最简单方法是从 2D 角度查看它,其中 x 轴指的是您的样本编号,y-轴是指您的海拔高度。
然后我们假设如果结果 n 处的高程高于直线,则视线被破坏。
地点:
(x1, y1) = (1, 4411.94)
(x2, y2) = (10, -84.51)
这是一张绘制结果的图片,并在其上绘制了从一点到另一点的线:
我们可以看到样本 8 和 9 的视线被破坏了。
下面是找到相同的代码。它使用直线的基本方程:y = mx + c
$results_json = json_decode('"results":["elevation":4411.94189453125,"location":"lat":36.578581,"lng":-118.291994,"resolution":19.08790397644043,"elevation":1658.561645507812,"location":"lat":36.54183904164596,"lng":-118.1291141726249,"resolution":9.543951988220215,"elevation":1085.295776367188,"location":"lat":36.50487579522382,"lng":-117.966389550823,"resolution":9.543951988220215,"elevation":1491.4912109375,"location":"lat":36.46769177008888,"lng":-117.8038207060907,"resolution":9.543951988220215,"elevation":1583.762817382812,"location":"lat":36.43028747728768,"lng":-117.6414082023003,"resolution":9.543951988220215,"elevation":488.8834228515625,"location":"lat":36.39266342953181,"lng":-117.4791525957044,"resolution":9.543951988220215,"elevation":933.0382080078125,"location":"lat":36.35482014117158,"lng":-117.3170544349424,"resolution":9.543951988220215,"elevation":1657.123779296875,"location":"lat":36.31675812816988,"lng":-117.1551142610472,"resolution":9.543951988220215,"elevation":1074.835205078125,"location":"lat":36.27847790807609,"lng``":-116.9933326074523,"resolution":9.543951988220215,"elevation":-84.51690673828125,"location":"lat":36.23998,"lng":-116.83171,"resolution":9.543951988220215],"status":"OK"');
$x1 = 0;
$x2 = count($results_json->results);
$y1 = $results_json->results[0]->elevation;
$y2 = $results_json->results[$x2 - 1]->elevation; // last result in results array
$m = ($y2 - $y1) / ($x2 - $x1); // slope of the line
$c = $y2 - ($m * $x2);
$i = 0;
foreach ($results_json->results as $result)
$elevation_of_straight_line = ($m * $i) + $c;
$elevation_of_result = $result->elevation;
if ($elevation_of_result > $elevation_of_straight_line)
echo 'line of sight broken';
echo 'Elevation of sample index '.$i.' = '.$elevation_of_result;
echo 'Elevation of line of sight = '.$elevation_of_straight_line;
$i++;
这消除了从 3D 角度看待这个问题所带来的复杂性。尽管对于地球曲率起作用的情况,这有其缺点。 这也应该可以扩展到任意数量的样本。
【讨论】:
嗨罗斯,谢谢,我有一个问题:视线的最后一个标高点与最后一个点的地面标高不同 嘿 Uccio,是的,我也注意到了这一点。根据谷歌的文档:“地球表面上所有位置的海拔数据都可用,包括海底的深度位置(返回负值)”developers.google.com/maps/documentation/elevation/intro 似乎有点奇怪,纬度低于可见水平,但我想这是可能的以上是关于是否有数学计算可以通过谷歌的 Elevation API 定义点 A 和点 B 之间是否存在可见性?的主要内容,如果未能解决你的问题,请参考以下文章