Robot Framework 如何获取文本项

Posted 2023-03-23

【中文标题】Robot Framework 如何获取文本项

【英文标题】：Robot Framework How to Get Text Item

【发布时间】：2021-04-04 13:59:27

【问题描述】：

我编写了从字典中提取数据的代码，并希望将信息保留为如下格式。

A = 2018
B = 8
A = 2019
B = 2
A = 2020
B = 3

行数据，我想从下面访问数据点。

[
  
    "A": 2018,
    "B": 8,
    "C": 7,
    "D": 8,
    "E": 0.0,
    "F": 8,
    "G": 8,
    "H": 8,
  ,
  
    "A": 2019,
    "B": 2,
    "C": 5,
    "D": 6,
    "E": 0,
    "F": 9,
    "G": 16,
    "H": 5,
  ,
  
    "A": 2020,
    "B": 3,
    "C": 8,
    "D": 61,
    "E": 0,
    "F": 2,
    "G": 1,
    "H": 2,
  ,
]

请帮我找到解决办法。谢谢

【问题讨论】：

Row data, I want to access the data points from below. 我不知道如何将含义与此联系起来——甚至用 raw 代替 Row。对于E，0.0 和0 的含义有区别吗？请注意How do I ask a Good Question?

【参考方案1】：

    a = [
  
    "A": 2018,
    "B": 8,
    "C": 7,
    "D": 8,
    "E": 0.0,
    "F": 8,
    "G": 8,
    "H": 8,
  ,
  
    "A": 2019,
    "B": 2,
    "C": 5,
    "D": 6,
    "E": 0,
    "F": 9,
    "G": 16,
    "H": 5,
  ,
  
    "A": 2020,
    "B": 3,
    "C": 8,
    "D": 61,
    "E": 0,
    "F": 2,
    "G": 1,
    "H": 2,
  ,
]

b = ""

for item in a:
    b = b + "A:" + str(item["A"]) + "\n" + "B:" + str(item["B"]) + "\n"
    
print(b)

Output: 
A:2018
B:8
A:2019
B:2
A:2020
B:3