SQL 代码在转换为 JPQL 代码时不起作用（ORA-00904 错误代码）

Posted 2023-03-16

【中文标题】SQL 代码在转换为 JPQL 代码时不起作用（ORA-00904 错误代码）

【英文标题】：SQL code does not work when converted to JPQL code (ORA-00904 error code)

【发布时间】：2021-05-10 22:14:02

【问题描述】：

非常感谢您查看这篇文章 :)。我有以下问题：我有一段在 Oracle 数据库上完美运行的 SQL 代码。当我尝试以 JPQL 代码运行时，问题就来了。我在 Eclipse IDE 中收到以下错误：

内部异常：java.sql.SQLSyntaxErrorException：ORA-00904：“THIRDTABLE”。“NAME”：标识符无效。

有效的 SQL 如下：

SELECT e.status_q,
       q.name,
       q.masterdatastatus_id
FROM firstTable e
JOIN secondTable q ON e.status_q = q.id
AND q.masterdatastatus_id = e.status_s
WHERE q.id != 7122
  AND e.qserie_id = 1296
  AND q.masterdatastatus_id not in
    (SELECT l1.status_s
     FROM thirdTable l1
     WHERE (l1.id,
            l1.name) not in
         (SELECT l2.id,
                 l2.name
          FROM thirdTable l2
          WHERE l2.status_s = 1))
  AND
    (SELECT count(*)
     FROM thirdTable l3
     WHERE l3.status_s = q.masterdatastatus_id) =
    (SELECT count(*)
     FROM thirdTable l4
     WHERE l4.status_s = 1)
  AND q.masterdatastatus_id in
    (SELECT x.status_s
     FROM thirdTable x
     LEFT JOIN thirdTable y ON x.id = y.id
     AND x.name = y.name
     WHERE y.id IS NOT NULL
       AND y.status_s = 1 )
ORDER BY q.id DESC;

这是不起作用的 JPQL 代码：

public static final String QUERY = "SELECT e.status, q.name, q.masterdatastatus.id FROM firstTableBE e JOIN secondTableBE q "
            + "ON e.status = q.id AND q.masterdatastatus.id = e.statusS WHERE "
            + "q.id != :STATUS_Q AND e.qSerieOid = :QSERIE_ID AND "
            + "q.masterdatastatus.id NOT IN (SELECT l1.status from ThirdTableBE l1 where (l1.oid, l1.name) NOT IN (SELECT l2.oid, l2.name from ThirdTableBE l2 where l2.status = 1)) AND "
            + "(SELECT COUNT(l3) from ThirdTableBE l3 where l3.status = q.masterdatastatus.id) = (SELECT COUNT(l4) from ThirdTableBE l4 where l4.status = 1) AND "
            + "q.masterdatastatus.id IN (SELECT x.status from ThirdTableBE x LEFT JOIN ThirdTableBE y on x.oid = y.oid and x.name = y.name where y.oid is not null and y.status = 1) "
            + "ORDER BY q.id DESC";

我猜问题出在这部分代码上：

"q.masterdatastatus.id NOT IN (SELECT l1.status from ThirdTableBE l1 where (l1.oid, l1.name) NOT IN (SELECT l2.oid, l2.name from ThirdTableBE l2 where l2.status = 1))"

JPQL 是否不支持子查询中的多个表达式？是'where'语句之后的那对吗？当我只尝试一个表达式（例如 l1.oid）时，它可以工作，但结果不是预期的。此外，如果我删除上面的代码，它可以工作，但同样，这不是我想要的结果。

提前感谢您的帮助！ :)

【问题讨论】：

Sql 比 JPQL 更强大。如果无法将 sql 查询转换为 JPQL 查询，可以使用 entityManager 的 createNativeQuery 方法直接执行 sql 查询，而无需将其转换为 JPQL。

嗨阿贝纳莫。谢谢回复。我会试试你的建议，看看是否可行。

【参考方案1】：

我通过使用 entityManager 中的 createNativeQuery 方法运行 SQL 代码解决了这个问题。 JPQL 似乎不太喜欢 where 语句中的对。也许我使用的 JPA 版本不支持对（我使用 JPA 2.6.4）。这是代码：

        Query query = entityManager
                .createNativeQuery("select e.status_q, q.name, q.masterdatastatus_id from firstTable e "
                        + "join secondTable q on e.status_q = q.id and q.masterdatastatus_id = e.status_s "
                        + " WHERE q.id != 7122 and e.qserie_id = 1296 and "
                        + "q.masterdatastatus_id not in (select l1.status_s from thirdTable l1 where (l1.id, l1.name) not in (select l2.id, l2.name from thirdTable l2 where l2.status_s = 1)) and "
                        + "(select count(*) from thirdTable l3 where l3.status_s = q.masterdatastatus_id) = (select count(*) from thirdTable l4 where l4.status_s = 1) and "
                        + "q.masterdatastatus_id in (select x.status_s from thirdTable x left join thirdTable y on x.id = y.id and x.name = y.name where y.id is not null and y.staatus_s = 1 ) "
                        + "order by q.id desc");
        List<Object> result = query.getResultList();

再次感谢 Abenamor 的解决方案 :)。