有没有办法在 Python 的 Pandas 数据框中通过 SMTPLib 将电子邮件连接到多个收件人？ [复制]

Posted 2023-03-15

【中文标题】有没有办法在 Python 的 Pandas 数据框中通过 SMTPLib 将电子邮件连接到多个收件人？ [复制]

【英文标题】：Is there a way of concatenating emails to multiple recipients via SMTPLib in a Pandas dataframe in Python? [duplicate]

【发布时间】：2021-07-26 08:07:02

【问题描述】：

我有下面的代码来发送特定于熊猫数据框中某些地址的电子邮件。类型为 pandas.series。我怎样才能发送具有多个地址的每个列表？有些有多达 8 个电子邮件地址，用分号 (;) 分隔。发送出去的唯一可能性是到一个地址。从下面的数据框中，我可以将特定于 ID 的电子邮件发送到 TestEmail 值。没有任何东西适用于电子邮件。我收到以下错误：

SMTPRecipientsRefused: '': (421, b'4.7.0 Too many protocol errors (6) on this connection, closing transmission channel.')

数据框 df

IDs  CompanyNames     Emails                                        TestEmail
2003    XXX           [e-mail];[e-mail];[e-mail];[e-mail]    [e-mail]
2004    XXXYY         [e-mail];[e-mail];[e-mail]              [e-mail]
2005    XXTTNN        [e-mail];[e-mail];[e-mail];[e-mail]    [e-mail]
2006    BBOOLL        [e-mail];[e-mail]                        [e-mail]

代码如下。对于单个地址，我可以将名称与 df['IDs'] 值匹配的附件发送到相应的电子邮件地址。

import smtplib, ssl
from email.message import EmailMessage
import getpass

ids = df['IDs']
emails_to = df['Emails'] #Pandas column with email addresses split  by semi-colon(;)
namesofcompanies  = df["CompanyNames"]
sendfrom  = df["SenderList"]

date_7days = (datetime.now() + timedelta(days=7)).strftime('%d/%m/%Y')
date_14days = (datetime.now() + timedelta(days=13)).strftime('%d/%m/%Y')

email_pass = input() #Office 365 password 
context=ssl.create_default_context()
for i in range(len(emails_to)): # iterate through the records
    # for every record get the name and the email addresses
    ID = str(ids[i])
    Emaitstosendto = emails_to[i]
    companynames = namesofcompanies[i]
    tosendfrom = sendfrom[i]
    
    if my_files_dict.get(ID): #Looks for  attachments in the same folder with same name  as the corresponding record 
        smtp_ssl_host = 'smtp.office365.com'
        smtp_ssl_port = 587
        email_login = "[e-mail]" #Office 365 email  
        email_from = tosendfrom         
        email_to = Emaitstosendto
        
        msg = MIMEMultipart()
        msg['Subject'] = "Received Emails between "+date_7days+" - "+date_14days
        msg['From'] = email_from
        msg['To'] = email_to
        msg['X-Priority'] = '2'    
         
        text = ("XXXX,\n"                
                f"xxxxxx\n\n")
        
        msg.attach(MIMEText(text))
        filename = my_files_dict.get(ID)#Files in the folder matching the ID   
        fo = open(filename,'rb')

        s2 = smtplib.SMTP(smtp_ssl_host, smtp_ssl_port)
        s2.starttls(context=context)
        s2.login(email_login, email_pass) 
        attachment = email.mime.application.MIMEApplication(fo.read(),_subtype="xlsx")
        fo.close()
        attachment.add_header('Content-Disposition','attachment',filename=filename)

        msg.attach(attachment)        
        s2.send_message(msg)        
        s2.quit()  

【参考方案1】：

取自这个答案：How to send email to multiple recipients using python smtplib?

这是您必须更改的行：

首先将 email_to 拆分为不同电子邮件的列表，然后使用 ", " 加入

msg['To'] = ", ".join(email_to.split(";"))